Problem 42
Question
For the following problems, solve the equations using the quadratic formula. $$ x^{2}+6 x+8=-x-2 $$
Step-by-Step Solution
Verified Answer
Question: Solve the quadratic equation using the extraction of roots method: $$4x^2 - 64 = 0$$
Answer: The two solutions for the given equation are \(x = 4\) and \(x = -4\).
1Step 1: Divide the equation by the coefficient of the squared term
To make it easier to work with, let's first divide the entire equation by the coefficient of the squared term (4):
$$
\frac{4x^2}{4} - \frac{64}{4} = \frac{0}{4}
$$
This simplifies to:
$$
x^2 - 16 = 0
$$
2Step 2: Isolate the squared term
Now, we need to isolate the squared term by moving the constant to the other side of the equation:
$$
x^2 = 16
$$
3Step 3: Use the square root property
The square root property states that if \(x^2 = a\), then \(x = \pm \sqrt{a}\). So, we can use the square root property to find the two solutions for x:
$$
x = \pm \sqrt{16}
$$
Now we can calculate the square root of 16:
$$
x = \pm 4
$$
So the two solutions to the equation are \(x = 4\) and \(x = -4\).
Key Concepts
Extraction of RootsSquare Root PropertyIsolation of Variable
Extraction of Roots
In mathematics, the process of solving quadratic equations often involves 'extraction of roots.' This method essentially aims to "solve" the algebraic equation by finding the values of the variable that make the equation true. When you have an equation like \(4x^2 - 64 = 0\), extracting roots is an efficient way to identify the solutions.
To begin, it's important to simplify the equation to make the squared term easy to manage. This involves dividing the entire equation by the number that is multiplying the squared variable, typically referred to as the coefficient. Here, you would divide everything by 4:
To begin, it's important to simplify the equation to make the squared term easy to manage. This involves dividing the entire equation by the number that is multiplying the squared variable, typically referred to as the coefficient. Here, you would divide everything by 4:
- \(\frac{4x^2}{4} - \frac{64}{4} = \frac{0}{4}\)
- Which simplifies to \(x^2 - 16 = 0\)
Square Root Property
The square root property is a crucial principle used in the process of solving quadratic equations. It states that for any real number \(a\), if \(x^2 = a\), then \(x = \pm \sqrt{a}\). This property allows us to systematically find solutions to quadratic equations without needing to factor them.
When you have isolated the squared variable (for instance, \(x^2 = 16\)), applying the square root property helps you quickly find the potential values of \(x\). In practice, this process looks like:
Using the square root property is a powerful tool because it provides simplicity and speed when working through these kinds of quadratic equations.
When you have isolated the squared variable (for instance, \(x^2 = 16\)), applying the square root property helps you quickly find the potential values of \(x\). In practice, this process looks like:
- Recognizing that \(x^2 = 16\), which means \(x = \pm \sqrt{16}\)
- Calculating the square root to determine that \(x = \pm 4\)
Using the square root property is a powerful tool because it provides simplicity and speed when working through these kinds of quadratic equations.
Isolation of Variable
In solving equations, particularly quadratics, isolation of variable is a fundamental step that simplifies the problem. Isolating the variable means getting it on one side of the equation by itself, often so you can apply further methods or properties, such as the square root property we discussed earlier.
Look at the simplified equation \(x^2 - 16 = 0\). To isolate \(x^2\), you need to move any constants to the other side of the equation:
So, isolation of the variable prepares the equation for the next logical step in finding the solution. Whether you're extracting roots or using the quadratic formula in more complicated equations, isolating the variable is essential for clarity and ease of solving.
Look at the simplified equation \(x^2 - 16 = 0\). To isolate \(x^2\), you need to move any constants to the other side of the equation:
- Add 16 to both sides: \(x^2 = 16\)
So, isolation of the variable prepares the equation for the next logical step in finding the solution. Whether you're extracting roots or using the quadratic formula in more complicated equations, isolating the variable is essential for clarity and ease of solving.
Other exercises in this chapter
Problem 41
For the following problems, solve for the indicated variable. $$ k^{2}=m^{2} n^{2}, \text { for } k $$
View solution Problem 41
For the following problems, use the zero-factor property to solve the equations. $$ x(x+8)=0 $$
View solution Problem 42
Find the product: \(\frac{x^{2}-4 x-12}{x^{2}-2 x-8} \cdot \frac{x^{2}-3 x-4}{x^{2}-3 x-18}\).
View solution Problem 42
For the following problems, solve the equations, if possible. $$ b^{2}-49=0 $$
View solution