Problem 42
Question
Find the vertex for the parabola whose equation is given by first writing the equation in the form \(y=a x^{2}+b x+c\) $$y=2(x-1)^{2}-4$$
Step-by-Step Solution
Verified Answer
The vertex of the given parabola is at point (1, -4).
1Step 1: Identify the Vertex Form of the Parabola
The vertex form of the parabola is \(y=a(x-h)^{2}+k\). So the vertex of the parabola is at point (h, k).
2Step 2: Compare with the Given Equation
Now, compare the given equation \(y=2(x-1)^{2}-4\) with the vertex form. It can be observed that the equation already is in vertex form.
3Step 3: Identify the Vertex
From step 2, identify the values of h and k. Here, h=1 and k=-4. Therefore, the vertex of the parabola is at point (1, -4).
Key Concepts
Parabola EquationsVertex FormQuadratic Functions
Parabola Equations
A parabola is a U-shaped graph that is represented in a coordinate plane by a quadratic equation. The most common form of this equation is the standard form, written as \[y = ax^2 + bx + c.\]Here,
The vertex of the parabola, which is a key point, is where the direction changes. This point provides valuable information about the curve's minimum or maximum. Understanding the parabola's equation helps in sketching the graph and analyzing the vertex. Each part of the equation plays a crucial role in these calculations.
- \(a\), \(b\), and \(c\) are constants.
- \(x\) and \(y\) are variables.
The vertex of the parabola, which is a key point, is where the direction changes. This point provides valuable information about the curve's minimum or maximum. Understanding the parabola's equation helps in sketching the graph and analyzing the vertex. Each part of the equation plays a crucial role in these calculations.
Vertex Form
The vertex form of a quadratic equation is especially useful for finding the vertex of a parabola quickly and accurately. The equation is written as \[y = a(x-h)^2 + k.\]In this form, the vertex of the parabola is clearly indicated by the point
By comparing this with the vertex form \(y = a(x-h)^2 + k\), we can easily identify the vertex. In this equation, \(h = 1\) and \(k = -4\), making the vertex (1, -4).
This format simplifies finding the vertex compared to other forms like the standard form.
- \((h, k)\).
- \(h\) represents the horizontal shift from the origin.
- \(k\) represents the vertical shift.
By comparing this with the vertex form \(y = a(x-h)^2 + k\), we can easily identify the vertex. In this equation, \(h = 1\) and \(k = -4\), making the vertex (1, -4).
This format simplifies finding the vertex compared to other forms like the standard form.
Quadratic Functions
Quadratic functions are equations of the form \[y = ax^2 + bx + c,\]which graph as parabolas. These functions are fundamental in algebra and appear frequently in various mathematical and real-world applications.
They always have a degree of 2, which differentiates them from linear functions, which are degree 1.
Quadratic functions have several key characteristics:
They always have a degree of 2, which differentiates them from linear functions, which are degree 1.
Quadratic functions have several key characteristics:
- They produce a parabolic graph, either opening upwards or downwards.
- The coefficient \(a\) affects the width and direction of the parabola.
- The vertex provides information about either the minimum or maximum value.
Other exercises in this chapter
Problem 41
Solve each equation by the method of your choice. Simplify irrational solutions, if possib $$\frac{3}{4} x^{2}-\frac{5}{2} x-2=0$$
View solution Problem 41
Explain how to complete the square for a binomial. Use \(x^{2}+6 x\) to illustrate your explanation.
View solution Problem 42
Solve each equation by the method of your choice. Simplify irrational solutions, if possib $$\frac{1}{3} x^{2}-\frac{1}{2} x-\frac{3}{2}=0$$
View solution Problem 42
Explain how to solve \(x^{2}+6 x+8=0\) by completing the square.
View solution