Problem 42
Question
Find the solution sets of the given inequalities. $$ |2 x-7|>3 $$
Step-by-Step Solution
Verified Answer
The solution set is \(x \in (-\infty, 2) \cup (5, \infty)\).
1Step 1: Understand the Absolute Value Inequality
The inequality \(|2x - 7| > 3\) tells us that the expression \(2x - 7\) is more than 3 units away from 0. This implies two separate conditions: \(2x - 7 > 3\) and \(2x - 7 < -3\).
2Step 2: Solve the First Inequality
Start by solving \(2x - 7 > 3\). First, add 7 to both sides to isolate the term with \(x\): \(2x > 10\). Then divide both sides by 2 to solve for \(x\): \(x > 5\).
3Step 3: Solve the Second Inequality
Now, solve the inequality \(2x - 7 < -3\). Add 7 to both sides: \(2x < 4\). Then divide both sides by 2 to isolate \(x\): \(x < 2\).
4Step 4: Write the Solution Set
Combine the solutions from Step 2 and Step 3. These two solutions define the solution set for the original inequality: \(x > 5\) or \(x < 2\). Therefore, the solution set is \(x \in (-\infty, 2) \cup (5, \infty)\).
Key Concepts
Solving InequalitiesSolution SetsMathematical Expressions
Solving Inequalities
When it comes to absolute value inequalities like \(|2x - 7| > 3\), the goal is to find the range of values that satisfy the inequality. Absolute value inequalities often break down into two separate inequalities because the absolute value represents the distance from zero on a number line. So, in our example, the expression inside the absolute value \((2x - 7)\) must either be greater than 3 or less than -3.
The trick to handling these inequalities is to consider both possibilities.
The trick to handling these inequalities is to consider both possibilities.
- Condition 1: The expression inside can be greater than the positive threshold, i.e., \(2x - 7 > 3\).
- Condition 2: Alternatively, it can be less than the negative threshold, i.e., \(2x - 7 < -3\).
Solution Sets
The solution set of an inequality is essentially a collection of numbers that satisfy the given condition. With a compound inequality resulting from absolute values, you'll often find the need to express the solution using intervals.
When solving \(|2x - 7| > 3\), we derived two inequalities: \(x > 5\) and \(x < 2\). Each inequality provides a solution set, but together they describe the interval where the original inequality holds true.
When solving \(|2x - 7| > 3\), we derived two inequalities: \(x > 5\) and \(x < 2\). Each inequality provides a solution set, but together they describe the interval where the original inequality holds true.
- The first inequality, \(x > 5\), translates to an interval \((5, \infty)\).
- Meanwhile, the second inequality, \(x < 2\), corresponds to the interval \((-\infty, 2)\).
Mathematical Expressions
Mathematical expressions are combinations of numbers, variables, and operations that represent a specific value or relationship. In the context of absolute value inequalities like \(|2x - 7| > 3\), understanding the structure of these expressions is crucial for solving them.
In the given exercise, the expression \(2x - 7\) is a linear expression. It combines two crucial operations:
In the given exercise, the expression \(2x - 7\) is a linear expression. It combines two crucial operations:
- First, multiplying the variable \(x\) by 2.
- Second, subtracting 7 from the result.
Other exercises in this chapter
Problem 42
Find the value of \(k\) such that the line \(k x-3 y=10\) (a) is parallel to the line \(y=2 x+4\); (b) is perpendicular to the line \(y=2 x+4\); (c) is perpendi
View solution Problem 42
Which of the following functions satisfies \(f(x+y)=f(x)+f(y)\) for all real numbers \(x\) and \(y ?\) (a) \(f(t)=2 t\) (b) \(f(t)=t^{2}\) (c) \(f(t)=2 t+1\) (d
View solution Problem 42
Change each repeating decimal to a ratio of two integers \(0.399999 \ldots\)
View solution Problem 43
Find the area of the sector of a circle of radius 5 centimeters and central angle 2 radians (see Problem 42).
View solution