Problem 42
Question
find \(f^{\prime}(x)\). $$ f(x)=\left(3 x^{2}-5 x\right)\left(x^{2}+2\right) $$
Step-by-Step Solution
Verified Answer
The derivative of the function \(f(x) = (3x^{2} - 5x)(x^{2} + 2)\) is \(f^{\prime}(x) = 12x^{3} -15x^{2} + 12x - 10\).
1Step 1: Find \(f'(x)\) for the first part of the product
Take the derivative of the first function representing \(f(x)\), which is \(3x^{2} - 5x\). Differentiating \(3x^{2}\) gives \(6x\), and differentiating \(-5x\) gives \(-5\). This yields \(f'(x)\)= \(6x - 5\).
2Step 2: Find \(g'(x)\) for the second part of the product
Next, take the derivative of the second function representing \(g(x)\), which is \(x^{2} + 2\). Differentiating \(x^{2}\) gives \(2x\) and differentiating \(2\), a constant, gives \(0\). This yields \(g'(x)\) = \(2x\).
3Step 3: Apply the product rule
According to the product rule, the derivative of the entire function is given by \((f(x)g(x))' = f'(x)g(x)+ f(x)g'(x)\). Substitute the found values for \(f'(x)\), \(g'(x)\), \(f(x)\) and \(g(x)\) into this formula: \((f(x)g(x))' = (6x - 5)(x^{2} + 2) + (3x^{2} - 5x)(2x)\). Simplifying this gives \(f^{\prime}(x) = 6x^3 + 12x - 5x^{2} - 10 + 6x^{3} -10x^{2} = 12x^{3} -15x^{2} +12x - 10\).
Key Concepts
Product RuleDifferentiationPolynomial Functions
Product Rule
The product rule is a fundamental principle in calculus that helps in finding the derivative of a product of two functions. If you have two functions multiplied together, say \( u(x) \) and \( v(x) \), the product rule states that the derivative of their product is given by:
This means you take the derivative of the first function and multiply it by the second function, then add to it the first function multiplied by the derivative of the second function. Understanding this rule is crucial because it allows us to break down complex expressions involving products into more manageable parts, making differentiation much simpler. In our original problem, we applied the product rule to the expressions \((3x^2 - 5x)\) and \((x^2 + 2)\) to find the derivative effectively. Each derivative was computed separately and then brought together using this rule.
- \((uv)' = u'v + uv'\)
This means you take the derivative of the first function and multiply it by the second function, then add to it the first function multiplied by the derivative of the second function. Understanding this rule is crucial because it allows us to break down complex expressions involving products into more manageable parts, making differentiation much simpler. In our original problem, we applied the product rule to the expressions \((3x^2 - 5x)\) and \((x^2 + 2)\) to find the derivative effectively. Each derivative was computed separately and then brought together using this rule.
Differentiation
Differentiation is the process of finding the derivative of a function. The derivative represents the rate of change of the function with respect to a variable, usually \( x \). Differentiation helps us understand how a function behaves, whether it is increasing, decreasing, or has any turning points.
When differentiating polynomial functions, each term is differentiated individually. You follow the power rule, which involves bringing down the exponent as a multiplier and reducing the exponent by one. For example, differentiating \( 3x^2 \) results in \( 6x \) and differentiating \(-5x\) leads to \(-5\). With constant terms like \(2\), their derivative is \(0\) because constants do not change.
Differentiation is a key part of calculus as it unlocks the understanding of dynamic changes within functional contexts. In practical scenarios, once the basic rules are applied, these concepts make complex derivatives accessible and straightforward.
When differentiating polynomial functions, each term is differentiated individually. You follow the power rule, which involves bringing down the exponent as a multiplier and reducing the exponent by one. For example, differentiating \( 3x^2 \) results in \( 6x \) and differentiating \(-5x\) leads to \(-5\). With constant terms like \(2\), their derivative is \(0\) because constants do not change.
- Poly-exponent reduction: Reduce the power of the variable by one
- Multiplier application: Multiply the coefficient by the original exponent
Differentiation is a key part of calculus as it unlocks the understanding of dynamic changes within functional contexts. In practical scenarios, once the basic rules are applied, these concepts make complex derivatives accessible and straightforward.
Polynomial Functions
Polynomial functions are mathematical expressions involving a sum of powers of variables, each multiplied by a coefficient, plus a constant term. These functions are widely used due to their simplicity and versatility for modeling real-world situations. A typical polynomial function looks like this:\[ f(x) = a_n x^n + a_{n-1} x^{n-1} + \ldots + a_1 x + a_0 \]where \( n \) is a non-negative integer, and \( a_n, a_{n-1},... \) are constants called coefficients.
In using derivatives with polynomial functions, you will often encounter tasks of determining how the output of these functions changes when there is a slight change in the input. Calculating derivatives for polynomials utilizes simple rules derived from the power rule, making them straightforward. In our original question, the functions \( 3x^2 - 5x \) and \( x^2 + 2 \) are examples of polynomial functions.
In using derivatives with polynomial functions, you will often encounter tasks of determining how the output of these functions changes when there is a slight change in the input. Calculating derivatives for polynomials utilizes simple rules derived from the power rule, making them straightforward. In our original question, the functions \( 3x^2 - 5x \) and \( x^2 + 2 \) are examples of polynomial functions.
- Easy to differentiate: Simple differentiation rules apply
- Predictable behavior: Polynomials don't exhibit sudden spikes or erratic changes within their domain
Other exercises in this chapter
Problem 41
find the limit $$ \lim _{x \rightarrow 1} \frac{x^{2}-1}{x-1} $$
View solution Problem 42
Find an equation of the tangent line to the graph of \(f\) at the point \((2, f(2)) .\) Use a graphing utility to check your result by graphing the original fun
View solution Problem 42
Sketch the graph of the function and describe the interval(s) on which the function is continuous. \(f(x)=\frac{x-3}{4 x^{2}-12 x}\)
View solution Problem 42
Use the limit definition to find an equation of the tangent line to the graph of \(f\) at the given point. Then verify your results by using a graphing utility
View solution