Problem 42
Question
Factor the expression. $$ m^{2}-25 $$
Step-by-Step Solution
Verified Answer
The factored form of the expression \(m^2 - 25\) is \((m+5)(m-5)\).
1Step 1: Recognize the structure
The first step is to recognize that the expression \(m^2 - 25\) is in the form of \(a^2 - b^2\), which indicates a difference of squares. Here \(a = m\) and \(b = 5\) because \(m^2 = (m)^2\) and \(25 = (5)^2\).
2Step 2: Apply the formula
By applying the difference of squares formula, which states that \(a^2 - b^2 = (a+b)(a-b)\), the given equation becomes \((m+5)(m-5)\).
3Step 3: Writing the final answer
The final factored expression is \((m+5)(m-5)\), as found using the difference of squares formula.
Key Concepts
Difference of SquaresAlgebraic StructuresFactoring Process
Difference of Squares
The difference of squares is a common technique in algebra used to simplify expressions, specifically quadratic expressions like the one given: \( m^2 - 25 \). This method relies on the identity \( a^2 - b^2 = (a+b)(a-b) \). Recognizing the expression as a difference of squares is crucial because it allows us to break them down into simpler terms. In our example, \( m^2 \) is the square of \( m \) and \( 25 \) is the square of \( 5 \). Thus, the expression can be rewritten using the formula to become \( (m+5)(m-5) \). This process not only simplifies the expression but also helps in solving equations where such factored forms are needed.
Algebraic Structures
Understanding algebraic structures is fundamental when working with expressions. In the context of the given expression \( m^2 - 25 \), recognizing this as a binomial expression is key. Binomials are expressions with two terms, like our example which can be broken down using algebraic identities.
Algebraic structures like polynomials and binomials serve as building blocks for more complex expressions. The difference of squares formula used here is an algebraic structure itself, simplifying how we handle expressions and solve equations.
Recognizing these structures not only enhances problem-solving skills but also deepens comprehension, making seemingly complex problems more approachable. By focusing on the familiar pattern of the difference of squares, we efficiently factor and resolve the expression into its simpler components \( (m+5) \) and \( (m-5) \).
Algebraic structures like polynomials and binomials serve as building blocks for more complex expressions. The difference of squares formula used here is an algebraic structure itself, simplifying how we handle expressions and solve equations.
Recognizing these structures not only enhances problem-solving skills but also deepens comprehension, making seemingly complex problems more approachable. By focusing on the familiar pattern of the difference of squares, we efficiently factor and resolve the expression into its simpler components \( (m+5) \) and \( (m-5) \).
Factoring Process
The factoring process involves breaking down equations or expressions into simpler, easily manageable parts, often factors or products of simpler expressions. The example given, \( m^2 - 25 \), demonstrates this well. Factoring this involves recognizing the expression as a difference of squares and applying the corresponding formula.
Here are the steps:
The factoring process transforms a more complex expression into a product of simpler expressions, making analysis and solution finding much more straightforward. Understanding this process is invaluable for students tackling various algebraic problems.
Here are the steps:
- Identify the expression format: Compare the given expression with classic forms, such as \( a^2 - b^2 \).
- Determine components: Here, \( m^2 \) and \( 25 \) are recognized as squares of \( m \) and \( 5 \) respectively.
- Apply the formula: Use \( (a+b)(a-b) \) to factor the expression.
- Rewrite the expression: Conclude with the factored form \( (m+5)(m-5) \).
The factoring process transforms a more complex expression into a product of simpler expressions, making analysis and solution finding much more straightforward. Understanding this process is invaluable for students tackling various algebraic problems.
Other exercises in this chapter
Problem 42
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Evaluate the expression. Write the answer as a fraction or as a mixed number in simplest form. (Skills Review pp. 764-765) $$ \frac{11}{2}\left(\frac{1}{10}-\fr
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Solve by completing the square. $$ x^{2}+20 x+3=0 $$
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Simplify the variable expression. $$ \left(36 x^{3}\right)^{1 / 2} $$
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