Problem 42
Question
Factor completely. $$ 9 x 2+5 x y-12 y 2 $$
Step-by-Step Solution
Verified Answer
The expression \(9x^2 + 5xy - 12y^2\) factors to \(3(x - y)(3x + 4y)\).
1Step 1: Rearrange the Terms
The expression given is \( 9x^2 + 5xy - 12y^2 \). To make it easier to factor, let's rewrite the expression so that it clearly reflects the standard form \( ax^2 + bxy + cy^2 \). We already have this form: \( 9x^2 + 5xy - 12y^2 \). In this case, no rearrangement is necessary as the terms are already organized correctly.
2Step 2: Identify the Coefficients
Take note of the coefficients in the quadratic trinomial: \( a = 9 \), \( b = 5 \), and \( c = -12 \). These will help us factor the trinomial.
3Step 3: Multiply \( a \times c \)
Multiply the leading coefficient \( a = 9 \) by the constant term \( c = -12 \) to find the product: \( 9 \times -12 = -108 \).
4Step 4: Find Factors of \(-108\) that Add to \(b\)
Look for two numbers that multiply to \(-108\) and add to \(b = 5\). These numbers are \(12\) and \(-9\) because \(12 imes (-9) = -108\) and \(12 + (-9) = 3\). Wait, instead, we should find two numbers multiplying to \(-108\) and adding to \(5\), which are actually \(12\) and \(-9\).
5Step 5: Rewrite the Middle Term
Use the numbers 12 and -9 to rewrite the middle term \(5xy\) as two separate terms: \(12xy - 9xy\). Therefore, the expression becomes \(9x^2 + 12xy - 9xy - 12y^2\).
6Step 6: Group Terms
Group the expression into two pairs: \((9x^2 + 12xy) + (-9xy - 12y^2)\).
7Step 7: Factor Each Group Separately
Factor out the greatest common factor from each pair. For the first group \(9x^2 + 12xy\), factor out \(3x\) to get \(3x(3x + 4y)\). For the second group \(-9xy - 12y^2\), factor out \(-3y\) to get \(-3y(3x + 4y)\).
8Step 8: Factor Out the Common Binomial
Notice that both terms include \((3x + 4y)\). Factor this common binomial out from the two groups to get \((3x - 3y)(3x + 4y)\).
9Step 9: Simplify Further if Possible
Notice that in \((3x - 3y)(3x + 4y)\), the first factor can be further factored by taking out 3: \(3(x - y)(3x + 4y)\). This is the fully factored form.
Key Concepts
Quadratic TrinomialGreatest Common FactorStandard Form of Quadratics
Quadratic Trinomial
A quadratic trinomial is a special type of polynomial that consists of three terms, specifically involving variables raised to the second degree. The general form of a quadratic trinomial is usually written as \(ax^2 + bxy + cy^2\), where:
- \(a\), \(b\), and \(c\) are coefficients
- \(x\) and \(y\) are variables
- \(ax^2\) is the quadratic term because of the squared variable
Greatest Common Factor
The Greatest Common Factor (GCF) is crucial when dealing with polynomials, especially when attempting to factor them. In simple terms, the GCF is the largest number or expression that divides each term in a polynomial without leaving a remainder. Identifying the GCF is a critical step in simplifying expressions or factoring them completely. To find the GCF, you should:
- Examine each term in the expression
- Look for numerical coefficients and variable factors that appear in each term
- Choose the highest powers of each variable common in the terms
Standard Form of Quadratics
The standard form of a quadratic expression lays the foundation for solving and factoring these types of polynomials effectively. This form is typically written as \(ax^2 + bxy + cy^2\) for expressions involving two variables, just like in our given problem: \(9x^2 + 5xy - 12y^2\).The importance of writing an expression in its standard form includes:
- Bringing clarity to the structure of the polynomial
- Identifying the coefficients necessary for further calculations
- Helping in recognizing patterns for factoring
Other exercises in this chapter
Problem 41
Factor completely. $$ x 4-y 4 $$
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Factor out the GCF. $$ 24 a_{2}-36 a-12 $$
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Factor. $$ 15 a 4 b 2-25 a 3 b-10 a 2 $$
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