Problem 42
Question
Expand and simplify the rule of the function \(g .\) $$f(x)=2 x^{3}-x+4 \text { and } g(x)=f(x+3)$$
Step-by-Step Solution
Verified Answer
Question: Given the function \(f(x) = 2x^3 - x + 4\), find the rule for the function \(g(x) = f(x+3)\).
Answer: The rule for the function \(g(x)\) is \(g(x) = 2x^3 + 18x^2 + 53x + 55\).
1Step 1: Substitute \(x+3\) into \(f(x)\)
To find \(g(x)\), we will replace \(x\) in the original function \(f(x)\) with \((x+3)\). This means that wherever we see \(x\) in \(f(x)\), we will replace it with \((x+3)\).
$$
g(x) = f(x + 3) = 2(x+3)^3 - (x+3) + 4
$$
2Step 2: Expand the cubic term
We will now expand the cubic term \((x+3)^3\). We can use the binomial expansion formula for this:
$$
(x+3)^3 = x^3 + 3\cdot(3)x^2 + 3\cdot(3)^2x + 3^3
$$
So, the expression of \(g(x)\) now becomes:
$$
g(x) = 2(x^3 + 9x^2 + 27x + 27) - (x+3) + 4
$$
3Step 3: Distribute the constant and simplify
Now, we will distribute the constant, merging the terms, and simplifying the expression:
$$
g(x) = 2x^3 + 18x^2 + 54x + 54 - x - 3 + 4
$$
Combine like terms:
$$
g(x) = 2x^3 + 18x^2 + (54 - 1)x + (54 - 3 + 4)
$$
Finally, we obtain the expanded and simplified form of \(g(x)\):
$$
g(x) = 2x^3 + 18x^2 + 53x + 55
$$
Key Concepts
Function ExpansionBinomial TheoremSimplification of Expressions
Function Expansion
In mathematics, expanding a function involves transforming one expression into an equivalent expression that is more detailed or spread out. In our exercise, we expand the function by substituting the expression
- First, identify the function that needs expansion. Here, we have the function \(f(x) = 2x^3 - x + 4\).
- Next, the function is modified by evaluating it at \(x + 3\) instead of just \(x\). This involves substituting every \(x\) in \(f(x)\) with \(x+3\).
- This substitution results in a new function \(g(x) = f(x+3) = 2(x+3)^3 - (x+3) + 4\).
Binomial Theorem
The binomial theorem is a powerful method used in algebra to expand expressions raised to a power, such as
- According to the binomial theorem, any power \((a + b)^n\) can be expanded as a sum, often involving combinations, of the terms.
- In our exercise, the component \((x+3)^3\) fits this pattern and can be expanded through the binomial theorem.
- The complete expansion involves the pattern: \[(x+3)^3 = x^3 + 3 \cdot 3x^2 + 3 \cdot 9x + 27\]This method rearranges the simpler term to reveal all components clearly.
Simplification of Expressions
Simplification involves reducing an expression to its most basic form, making it easier to handle or understand. Let's look at the steps involved:
- After expanding the function using the binomial theorem, distribute constant multiples through the expanded expression. For example, we have the term with a coefficient "2" in \[2(x^3 + 9x^2 + 27x + 27)\]Multiplication distributively gives us\[2x^3 + 18x^2 + 54x + 54\]
- Next, handle the other terms, such as \(- (x + 3)\) and \(+ 4\), by distributing or directly evaluating them in context:\[-x - 3 + 4\]
- With all pieces expanded, combine like terms across the expression, where terms with similar powers of \(x\) add or subtract their coefficients.
Other exercises in this chapter
Problem 41
Find the kth partial sum of the arithmetic sequence \(\left\\{a_{n}\right\\}\) with common difference d. $$k=6, a_{1}=2, d=5$$
View solution Problem 42
In Exercises \(39-42,\) find the kth partial sum of the geometric sequence \(\left\\{a_{n}\right\\}\) with common ratio \(r\). $$k=9, a_{2}=6, r=\frac{1}{4}$$
View solution Problem 42
Find the sum. $$\sum_{k=1}^{5}(-k)$$
View solution Problem 42
Find the kth partial sum of the arithmetic sequence \(\left\\{a_{n}\right\\}\) with common difference d. $$k=8, a_{1}=\frac{2}{3}, d=-\frac{4}{3}$$
View solution