Problem 42
Question
Exer. \(41-44:\) Find an equation for the set of points in an Xy-plane such that the sum of the distances from \(F\) and \(F\) is \(k\) $$F(12,0), \quad F(-12,0) ; \quad k=26$$
Step-by-Step Solution
Verified Answer
The equation is \( \frac{x^2}{169} + \frac{y^2}{25} = 1 \).
1Step 1: Understand the Problem
We need to find an equation for a set of points where the sum of distances from two fixed points (foci) is constant. This problem is asking us to find the equation of an ellipse.
2Step 2: Define the Properties of the Ellipse
An ellipse can be defined as the set of all points where the sum of the distances from any point on the ellipse to two fixed points (foci) is constant. Here, the foci are given as \( F(12, 0) \) and \( F(-12, 0) \), and the constant \( k \) is given as 26.
3Step 3: Use the Ellipse Standard Form Equation
The standard equation of an ellipse is \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \). We need to find \( a \) and \( b \) such that the sum of distances is 26 and the distance between the foci is 24 (which is \(2c\)).
4Step 4: Calculate the Semi-Major Axis
For the given sum of distances \( k = 26 \), the length of the major axis \( 2a \) is equal to \( k \). Thus \( a = \frac{k}{2} = \frac{26}{2} = 13 \).
5Step 5: Find the Value of c
The distance between the foci is \( 2c \), so \( c = \frac{12 - (-12)}{2} = 12 \).
6Step 6: Relate c and a to Find b
In an ellipse, \( c^2 = a^2 - b^2 \). With \( c = 12 \) and \( a = 13 \), we have \( 12^2 = 13^2 - b^2 \). Solving for \( b \), we get \( b^2 = 13^2 - 12^2 = 169 - 144 = 25 \), thus \( b = 5 \).
7Step 7: Write the Equation of the Ellipse
Using the values of \( a \) and \( b \), the equation of the ellipse is \( \frac{x^2}{13^2} + \frac{y^2}{5^2} = 1 \), or simplified, \( \frac{x^2}{169} + \frac{y^2}{25} = 1 \).
Key Concepts
FociEllipse PropertiesSum of Distances
Foci
In the context of an ellipse, the term 'foci' refers to two special fixed points that are used in the formal definition of the shape. These points are denoted typically as
In our exercise, the foci are located at
Knowing the foci, it's easier to visualize the ellipse and comprehend how any point on it maintains the property of distance constancy from these fixed markers.
- F1 and F2
- equidistant from the center of the ellipse along the major axis
In our exercise, the foci are located at
- F(12,0) and F(-12,0), positioned symmetrically on the x-axis
Knowing the foci, it's easier to visualize the ellipse and comprehend how any point on it maintains the property of distance constancy from these fixed markers.
Ellipse Properties
An ellipse is a fascinating geometric shape characterized by a few key properties that make it distinct from other curves. Here are some important aspects to understand:
These properties help in visualizing the ellipse and predicting how it interacts with its plane, proving useful in everything from architectural designs to astronomical calculations.
- Major and Minor Axes: The major axis is the longest span across the ellipse, and the minor axis is the shortest. The major axis always passes through both foci.
- The Center: Located at the midpoint of the segment connecting the foci. For our specific ellipse, this point is at the origin (0,0).
- Eccentricity: A measure of how "stretched" an ellipse is. It is defined as the ratio of the distance between foci (2c) to the length of the major axis (2a).
These properties help in visualizing the ellipse and predicting how it interacts with its plane, proving useful in everything from architectural designs to astronomical calculations.
Sum of Distances
The defining trait of an ellipse is the sum of distances from any point on it to its two foci.
In our problem, this sum of distances is defined to be 26. This means if you take any point on the ellipse and measure its distance to each focus, the total will always be 26.
This characteristic provides a method to derive the dimensions of an ellipse by setting distances equal to this constant value, forming the basis of the standard ellipse equation.
- For an ellipse, this sum always stays constant
In our problem, this sum of distances is defined to be 26. This means if you take any point on the ellipse and measure its distance to each focus, the total will always be 26.
This characteristic provides a method to derive the dimensions of an ellipse by setting distances equal to this constant value, forming the basis of the standard ellipse equation.
Other exercises in this chapter
Problem 42
Identify the graph of the equation as a parabola (with vertical or horizontal axis), circle, ellipse, or hyperbola. $$x=2 x^{2}-y+4$$
View solution Problem 42
Find an equation in \(x\) and \(y\) that has the same graph as the polar equation. Use it to help sketch the graph in an \(r \theta\) -plane. $$r=2$$
View solution Problem 42
Find an equation for the indicated half of the parabola. Upper half of \((y-2)^{2}=x-4\)
View solution Problem 43
Identify the graph of the equation as a parabola (with vertical or horizontal axis), circle, ellipse, or hyperbola. $$4 x^{2}-16 x+9 y^{2}+36 y=-16$$
View solution