Problem 42
Question
Dimensions of a Poster \(\quad\) A poster has a rectangular printed area 100 \(\mathrm{cm}\) by 140 \(\mathrm{cm}\) and a blank strip of uniform width around the edges. The perimeter of the poster is 1\(\frac{1}{2}\) times the perimeter of the printed area. What is the width of the blank strip?
Step-by-Step Solution
Verified Answer
The width of the blank strip is 30 cm.
1Step 1: Understand the Problem
The problem describes a poster with a rectangular printed area measuring 100 cm by 140 cm, surrounded by a blank strip of uniform width. The goal is to find the width of the blank strip given that the perimeter of the entire poster is 1.5 times the perimeter of the printed area.
2Step 2: Calculate the Perimeter of the Printed Area
First, calculate the perimeter of the printed area. The formula for the perimeter of a rectangle is:\[ P = 2 \times (\text{length} + \text{width}) \]Substituting the given values for the printed area:\[ P = 2 \times (100 + 140) = 2 \times 240 = 480 \text{ cm} \]
3Step 3: Express the Perimeter of the Entire Poster
Let the width of the blank strip be \(x\) cm. The dimensions of the entire poster, including the strip, would be \((100 + 2x)\) and \((140 + 2x)\). The perimeter of the entire poster is:\[ P' = 2 \times ((100 + 2x) + (140 + 2x)) = 2 \times (240 + 4x) = 480 + 8x \]
4Step 4: Set Up the Perimeter Relationship Equation
According to the problem, the perimeter of the poster is 1.5 times the perimeter of the printed area. Therefore, set up the equation:\[ 480 + 8x = 1.5 \times 480 \]Simplify the right side:\[ 1.5 \times 480 = 720 \]Substitute back into the equation:\[ 480 + 8x = 720 \]
5Step 5: Solve for the Width of the Strip
Rearrange the equation to solve for \(x\):\[ 8x = 720 - 480 \]\[ 8x = 240 \]\[ x = \frac{240}{8} = 30 \]
6Step 6: Conclusion: Identify the Width of the Blank Strip
The calculations indicate that the width of the blank strip around the printed area is 30 cm.
Key Concepts
PerimeterAlgebraic EquationsProblem-Solving Steps
Perimeter
Understanding how the perimeter is calculated is crucial for solving problems in rectangular geometry. Perimeter is essentially the total length around a shape. For a rectangle, this is calculated using the formula:
- \( P = 2 \times (\text{length} + \text{width}) \)
- \( 100 + 140 = 240 \text{ cm} \)
- \( P = 2 \times 240 = 480 \text{ cm} \)
Algebraic Equations
Algebraic equations form the backbone of problem-solving in mathematics. In the exercise you've seen, we deal with an equation that describes the relationship between the printed area and the entire poster. By introducing a variable \( x \) for the width of the blank strip, we can form expressions representing the whole dimensions of the poster:
- The length becomes \( 100 + 2x \)
- The width becomes \( 140 + 2x \)
- \( P' = 2 \times ((100 + 2x) + (140 + 2x)) = 480 + 8x \)
- \( 480 + 8x = 720 \)
Problem-Solving Steps
Effective problem-solving in geometry often involves breaking down exercises into manageable steps. This approach not only makes it easier to follow but also ensures you don't miss out on critical parts of the solution. Here’s a breakdown of how to tackle similar problems:
- Understand the problem: Identify all given information and what is being asked.
- Calculate known values: Start with what you can directly compute. Here, it was the perimeter of the printed area.
- Express unknowns: Use variables for unknown quantities and express all parts of the shape in terms of these variables.
- Formulate the equation: Set up relationships using the known formulas and given conditions in the problem.
- Solve the equation: Use algebraic methods to solve for the unknowns.
- Review your solution: Ensure all steps relate back to the problem and that the solution is reasonable.
Other exercises in this chapter
Problem 42
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