Problem 42
Question
Determine whether each equation defines \(y\) to be a function of \(x .\) If it does not, find two ordered pairs where more than one value of \(y\) corresponds to a single value of \(x .\) See Example 3. $$ y=|x| $$
Step-by-Step Solution
Verified Answer
Yes, \(y = |x|\) defines y to be a function of x, as each x maps to exactly one y.
1Step 1: Understand a Function
To determine if an equation defines a function, recall that a function assigns exactly one output (y) to each input (x). For each x-value, there must be one and only one corresponding y-value.
2Step 2: Analyze the Equation
The given equation is \(y = |x|\). The absolute value function assigns the positive magnitude of x to y, regardless of the sign of x. This means it takes each input x and returns a single output y.
3Step 3: Check Specific Values
Test specific values of x: - If \(x = 3\), then \(y = |3| = 3\).- If \(x = -3\), then \(y = |-3| = 3\).For both inputs, there is a unique output, satisfying the definition of a function.
4Step 4: Apply the Vertical Line Test
Sketch the graph of \(y = |x|\). If a vertical line crosses the graph at more than one point for any x-value, the relation is not a function. However, each vertical line for any x-value only meets the graph once, confirming it's a function.
5Step 5: Conclude
Since each x-value maps to only one y-value and the graph of \(y = |x|\) passes the vertical line test, we conclude that the equation defines y to be a function of x.
Key Concepts
Understanding Absolute ValueUsing the Vertical Line TestDefining a Function
Understanding Absolute Value
The absolute value of a number is its distance from zero on the number line. In mathematical terms, the absolute value is always a non-negative number. For any real number \( x \), the absolute value is represented as \( |x| \). This notation means that:
- If \( x \) is positive or zero, then \( |x| = x \).
- If \( x \) is negative, then \( |x| = -x \).
Using the Vertical Line Test
The vertical line test is a straightforward visual method for verifying whether a curve on the graph represents a function. The test states that a curve is a graph of a function if no vertical line intersects the curve more than once at any given \( x \)-coordinate.When you apply this test to the equation \( y = |x| \), you'll see that for every vertical line drawn over any \( x \)-value, the line crosses the graph only once. This means every possible \( x \) corresponds to a single \( y \). It verifies that \( y = |x| \) is a function.
This technique is particularly useful because it provides a quick check: if any vertical line crosses your curve multiple times, the graph does not describe a function. But for \( y = |x| \), the V-shaped graph will always meet our evaluations, showcasing its function status succinctly.
This technique is particularly useful because it provides a quick check: if any vertical line crosses your curve multiple times, the graph does not describe a function. But for \( y = |x| \), the V-shaped graph will always meet our evaluations, showcasing its function status succinctly.
Defining a Function
A \( function \) is a special kind of relation where each input value has exactly one output value.
- The key rule for functions is that for each \( x \)-value (input), there must be exactly one \( y \)-value (output).
- This assures no ambiguity: every time you input a certain \( x \), you know exactly what \( y \) will be.
- It consistently provides a single output \( y \) for each possible \( x \).
- Whether \( x \) is positive, negative, or zero, \( |x| \) computes to one definite, predictable \( y \).
Other exercises in this chapter
Problem 41
Solve each formula for the specified variable. $$ V=\frac{1}{3} B h \text { for } B $$
View solution Problem 42
Simplify each rational expression. See Example 4 $$\frac{x^{2}-2 x-15}{25-x^{2}}$$
View solution Problem 42
Solve each problem by writing a variation model. The following table shows the listing price for three homes in the same general locality. Write the variation m
View solution Problem 42
Factor. $$ (a-b-c) r-(a-b-c) s $$
View solution