Problem 42
Question
denominators are opposites, or additive inverses. Add or subtract as indicated. Simplify the result, if possible. $$\frac{6 x+5}{x-2}+\frac{4 x}{2-x}$$
Step-by-Step Solution
Verified Answer
The simplified result of adding these two fractions is \( \frac{10x+5}{x-2} \)
1Step 1: Preparatory Step: Make Denominators the Same
Begin by making the denominators the same. Since the second fraction's denominator is negative, this equation could be rewritten as \( \frac{6x+5}{x-2} - \frac{-4x}{x-2} \). The negative sign before the second fraction is absorbed, which means the second fraction becomes positive.
2Step 2: Add or Subtract the Fractions
Now that the fractions have the identical denominators, the numerators can be added or subtracted as directed. This will give: \( \frac{6x+5+4x}{x-2} = \frac{10x+5}{x-2} \)
3Step 3: Simplify the Result
In the final step, the fraction will be simplified if possible. For this problem, it is impossible to simplify the result, as \(10x + 5\) and \(x - 2\) do not share a common divisor. Therefore, the simplified result of this fraction addition problem remains \( \frac{10x+5}{x-2} \).
Key Concepts
Additive InversesSimplifying FractionsCommon Denominators
Additive Inverses
Understanding additive inverses is crucial when dealing with operations involving denominators. The additive inverse of a number is what you add to that number to get zero. For example, the additive inverse of 7 is -7, since 7 + (-7) = 0. This concept is helpful when working with fractions that have negative terms in either the numerators or denominators.
In the exercise given, we had to adjust the fractions so that their denominators appeared the same. The two original denominators were \( x-2 \) and \( 2-x \). You might notice that these two are negative versions of each other, or, practically speaking, additive inverses. Hence, by rewriting \( 2-x \) as \(-1 \cdot (x-2)\), we managed to carry that negative sign outside of the fraction. This adjustment helped us to proceed by adding or subtracting fractions effectively.
In the exercise given, we had to adjust the fractions so that their denominators appeared the same. The two original denominators were \( x-2 \) and \( 2-x \). You might notice that these two are negative versions of each other, or, practically speaking, additive inverses. Hence, by rewriting \( 2-x \) as \(-1 \cdot (x-2)\), we managed to carry that negative sign outside of the fraction. This adjustment helped us to proceed by adding or subtracting fractions effectively.
Simplifying Fractions
Simplifying fractions is an essential step in ensuring that your final answer is in its simplest form, making it easier to interpret.
- Simplification involves reducing a fraction to its lowest form, where the numerator and the denominator have no common divisors other than 1.
- To simplify a fraction, divide both the numerator and the denominator by their greatest common divisor (GCD).
Common Denominators
When adding or subtracting fractions, having a common denominator is absolutely necessary. This means that the fractions should have the same bottom part, the denominator, which allows their numerators to be directly combined.Why is this important?
- A common denominator ensures that the pieces of the whole (fractions) we are dealing with are comparable.
- Without a common denominator, adding fractions by simply combining their numerators is not logically correct.
Other exercises in this chapter
Problem 41
Divide as indicated. $$\frac{7}{x-5} \div \frac{28}{3 x-15}$$
View solution Problem 41
Solve each rational equation. $$\frac{4 y}{y^{2}-25}+\frac{2}{y-5}=\frac{1}{y+5}$$
View solution Problem 42
Determine whether each statement "makes sense" or "does not make sense" and explain your reasoning. I can solve \(\frac{x}{9}=\frac{4}{6}\) by using the cross-p
View solution Problem 42
Simplify each rational expression. If the rational expression cannot be simplified, so state. $$\frac{y^{2}+5 y+4}{y^{2}-4 y-5}$$
View solution