Problem 42
Question
At least \(25 \mu \mathrm{g}\) of tetrahydrocannabinol (THC), the active ingredient in marijuana, is required to produce intoxication. The molecular formula of THC is \(\mathrm{C}_{21} \mathrm{H}_{30} \mathrm{O}_{2}\). How many moles of THC does this \(25 \mu \mathrm{g}\) represent? How many molecules?
Step-by-Step Solution
Verified Answer
25 µg of THC represents approximately \(7.95 \times 10^{-11}\) moles and \(4.79 \times 10^{13}\) molecules of THC.
1Step 1: Calculate the molar mass of THC
First, we need to find the molar mass of THC. To do this, we'll use the molecular formula \(\mathrm{C}_{21} \mathrm{H}_{30} \mathrm{O}_{2}\) and the atomic masses of each element. We know the atomic masses of carbon (C), hydrogen (H), and oxygen (O) are approximately 12.01 g/mol, 1.01 g/mol, and 16.00 g/mol, respectively. So, the molar mass of THC is:
Molar mass of THC = (21 × 12.01 g/mol) + (30 × 1.01 g/mol) + (2 × 16.00 g/mol) = 314.47 g/mol
2Step 2: Convert the given mass of THC to moles
Next, we will convert the given mass of THC, \(25 \mu \mathrm{g}\), to moles. To do this, we will use the molar mass of THC (314.47 g/mol) and the conversion factor: 1 g = 1,000,000 µg.
Moles of THC = \(\frac{25 \mu \mathrm{g}}{314.47 \frac{\mathrm{g}}{\mathrm{mol}} \times 1,000,000 \frac{\mu \mathrm{g}}{\mathrm{g}}}\) = \(\frac{25}{314.47 \times 10^6}\) mol ≈ 7.95 × 10⁻¹¹ mol
3Step 3: Convert the number of moles to the number of molecules
Finally, we will convert the number of moles of THC (7.95 × 10⁻¹¹ mol) to the number of molecules. To do this, we will use Avogadro's number (6.022 × 10²³ molecules/mol):
Number of molecules = (7.95 × 10⁻¹¹ mol) × (6.022 × 10²³ molecules/mol) ≈ 4.79 × 10¹³ molecules
So, 25 µg of THC represents approximately 7.95 × 10⁻¹¹ moles and 4.79 × 10¹³ molecules of THC.
Key Concepts
Molar MassAvogadro's NumberMolecular Formula
Molar Mass
Molar mass is a fundamental concept in chemistry that helps us understand how to relate the mass of a substance to the amount of that substance in moles. It is the mass of one mole of a given substance, typically expressed in grams per mole (g/mol). To calculate the molar mass, you need the molecular formula of the compound and the atomic masses of its elements.
In the example of tetrahydrocannabinol (THC), which has the molecular formula \(\mathrm{C}_{21} \mathrm{H}_{30} \mathrm{O}_{2}\), we find its molar mass by adding up the molar masses of each atom in the formula:
In the example of tetrahydrocannabinol (THC), which has the molecular formula \(\mathrm{C}_{21} \mathrm{H}_{30} \mathrm{O}_{2}\), we find its molar mass by adding up the molar masses of each atom in the formula:
- Carbon (C): 21 atoms × 12.01 g/mol = 252.21 g/mol
- Hydrogen (H): 30 atoms × 1.01 g/mol = 30.30 g/mol
- Oxygen (O): 2 atoms × 16.00 g/mol = 32.00 g/mol
Avogadro's Number
Avogadro's number, which is 6.022 × 10²³, is a constant that denotes the number of particles in one mole of a substance. These particles can be atoms, molecules, ions, or other entities, depending on the context.
This number is immensely useful when converting between moles and the actual number of molecules or atoms. For instance, in our THC example, we calculated that the 25 micrograms of THC corresponds to 7.95 × 10⁻¹¹ moles. Using Avogadro's number, we can further determine the number of THC molecules:
This number is immensely useful when converting between moles and the actual number of molecules or atoms. For instance, in our THC example, we calculated that the 25 micrograms of THC corresponds to 7.95 × 10⁻¹¹ moles. Using Avogadro's number, we can further determine the number of THC molecules:
- Number of molecules = 7.95 × 10⁻¹¹ moles × 6.022 × 10²³ molecules/mole
- This calculation results in approximately 4.79 × 10¹³ THC molecules
Molecular Formula
The molecular formula provides specific information about the number and types of atoms in a molecule, and it allows us to determine the molecular composition of a compound. The formula shows the exact number of each type of atom present in a molecule.
For THC, the molecular formula is \(\mathrm{C}_{21} \mathrm{H}_{30} \mathrm{O}_{2}\). This tells us that each molecule of THC is composed of:
For THC, the molecular formula is \(\mathrm{C}_{21} \mathrm{H}_{30} \mathrm{O}_{2}\). This tells us that each molecule of THC is composed of:
- 21 carbon atoms
- 30 hydrogen atoms
- 2 oxygen atoms
Other exercises in this chapter
Problem 41
The allowable concentration level of vinyl chloride, \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Cl},\) in the atmosphere in a chemical plant is \(2.0 \times 10^{-6
View solution Problem 42
At least \(25 \mu \mathrm{g}\) of tetrahydrocannabinol \((\mathrm{THC}),\) the active ingredient in marijuana, is required to produce intoxication. The molecula
View solution Problem 43
Give the empirical formula of each of the following compounds if a sample contains (a) \(0.0130 \mathrm{~mol} \mathrm{C}, 0.0390 \mathrm{~mol} \mathrm{H},\) and
View solution Problem 45
Determine the empirical formulas of the compounds with the following compositions by mass: (a) \(10.4 \% \mathrm{C}, 27.8 \% \mathrm{~S},\) and \(61.7 \% \mathr
View solution