Problem 42
Question
(a) What is the trend in first ionization energies as one proceeds down the group 7 A elements? Explain how this trend relates to the variation in atomic radii. (b) What is the trend in first ionization energies as one moves across the fourthperiod from \(\mathrm{K}\) to \(\mathrm{Kr}\) ? How does this trend compare with the trend in atomic radii?
Step-by-Step Solution
Verified Answer
As one proceeds down the group 7A elements, the ionization energy generally decreases due to an increase in atomic radius and shielding effect. However, when moving across the fourth period from \(\mathrm{K}\) to \(\mathrm{Kr}\), the ionization energy increases because of a decrease in atomic radius and an increase in effective nuclear charge.
1Step 1: Trends in Ionization Energy in Group 7A Elements
As one proceeds down the group 7A elements, the ionization energy generally decreases. We will explain this trend by considering the changes in atomic radius.
2Step 2: Relationship between Atomic Radius and Ionization Energy in Group 7A Elements
When moving down the group 7A elements, the atomic radius increases. This is because additional electron shells are added as we move down the group. This leads to an increase in the shielding effect, causing a decreased hold of the nucleus on the valence electrons. As the atomic radius increases, the distance between the valence electron and the nucleus also increases, causing the electrostatic attraction between the electron and nucleus to decrease. As a result, the ionization energy decreases because less energy is required to remove the valence electron.
3Step 3: Trends in Ionization Energy across the Fourth Period from \(\mathrm{K}\) to \(\mathrm{Kr}\)
As one moves across the fourth period from \(\mathrm{K}\) (potassium) to \(\mathrm{Kr}\) (krypton), the ionization energy generally increases.
4Step 4: Relationship between Atomic Radius and Ionization Energy across the Fourth Period
When moving across the fourth period, the atomic radius generally decreases. This is due to an increase in the effective nuclear charge experienced by the valence electrons. The shielding effects remain relatively constant, which means that the increasing nuclear charge results in stronger binding of valence electrons to the nucleus. The decreasing atomic radius means that the valence electrons are closer to the nucleus, resulting in stronger electrostatic attraction between the electrons and the nucleus. Consequently, the ionization energy increases across the period because more energy is required to remove the valence electron.
In conclusion, when moving down the group 7A elements, the ionization energy decreases due to an increase in atomic radius and shielding effect. When moving across the fourth period from \(\mathrm{K}\) to \(\mathrm{Kr}\), the ionization energy increases because of a decrease in atomic radius and an increase in effective nuclear charge.
Key Concepts
Atomic RadiusGroup 7A ElementsFourth Period ElementsEffective Nuclear Charge
Atomic Radius
The atomic radius refers to the size of an atom. It is the distance from the nucleus of an atom to the outermost electron shell, where the valence electrons reside. Understanding atomic radius changes helps to predict chemical properties of elements.
- Moving down a group (like group 7A), atomic radius increases. This is due to the addition of extra electron shells.
- Moving across a period from left to right, atomic radius decreases because electrons are added to the same shell while the nuclear charge increases.
Group 7A Elements
Group 7A elements, also known as the halogens, include elements like fluorine, chlorine, bromine, iodine, and astatine. These elements are highly reactive nonmetals known for forming salts when combined with metals.
The elements in group 7A show decreasing ionization energies as one moves down the group. This is due to:
The elements in group 7A show decreasing ionization energies as one moves down the group. This is due to:
- An increase in atomic radius as more electron shells are added.
- Greater electron shielding, which reduces the effective nuclear charge felt by outer electrons.
Fourth Period Elements
The fourth period in the periodic table extends from potassium (K) to krypton (Kr). As you move across this period, several trends can be observed:
- Ionization Energy: This generally increases. As more protons are added to the nucleus, the nuclear charge increases, resulting in a stronger attraction to the electrons.
- Atomic Radius: It decreases as the effective nuclear charge pulls valence electrons closer to the nucleus.
Effective Nuclear Charge
Effective nuclear charge (
Z_ ext{eff}
) describes the net positive charge experienced by valence electrons. It highlights the inner shell electron shielding effects and helps in understanding many chemical properties:
- Increases across a period: More protons are added to the nucleus, and despite the same shell electrons, more are present to repel each other minimally.
- Stays relatively constant down a group: More inner shells buffer the valence electrons from the increased number of protons.
Other exercises in this chapter
Problem 40
Identify each statement as true or false: (a) Ionization energies are always negative quantities. (b) Oxygen has a larger first ionization energy than fluorine.
View solution Problem 41
(a) What is the general relationship between the size of an atom and its first ionization energy? (b) Which element in the periodic table has the largest ioniza
View solution Problem 43
Based on their positions in the periodic table, predict which atom of the following pairs will have the smaller first ionization energy\(:(\mathbf{a}) \mathrm{C
View solution Problem 44
For each of the following pairs, indicate which element has the smaller first ionization energy: (a) Ti, Ba; (b) Ag, Cu; (c) Ge, Cl; (d) Pb, Sb.
View solution