Problem 42
Question
a. Use the Leading Coefficient Test to determine the graph's end behavior. b. Find the \(x\)-intercepts. State whether the graph crosses the \(x\)-axis, or touches the \(x\) -axis and turns around, at each intercept. c. Find the \(y\)-intercept. d. Determine whether the graph has y-axis symmetry, origin symmetry, or neither. e. If necessary, find a few additional points and graph the function. Use the maximum number of turning points to check whether it is drawn correctly. \(f(x)=x^{3}+x^{2}-4 x-4\)
Step-by-Step Solution
Verified Answer
End Behavior: as \(x \rightarrow -\infty, f(x) \rightarrow -\infty\) and as \(x \rightarrow \infty, f(x) \rightarrow \infty\). X-intercepts where the graph crosses: -2.65, Y-intercept: -4, The graph has neither y-axis nor origin symmetry and we have one turning point near \((-1, -6)\).
1Step 1: End Behavior
Polynomials exhibit certain behaviors at the ends of the graph, depending upon the degree and the leading coefficient of the polynomial. For \(f(x)=x^{3}+x^{2}-4x-4\) the degree is odd and leading coefficient is positive, hence as \(x \rightarrow -\infty, f(x) \rightarrow -\infty\) and as \(x \rightarrow \infty, f(x) \rightarrow \infty\).
2Step 2: Finding x-intercepts
The x-intercepts of the function are points where the function crosses or touches the x-axis. These can be found by setting \(f(x)=0\). So, solve \(x^{3}+x^{2}-4x-4=0\). By using a cubic equation solver, we find \(x \approx -2.65063, x \approx 0.732051 - 1.03923i\) and \(x \approx 0.732051 + 1.03923i\). There is one real root (-2.65), this is where the graph crosses the x-axis. The roots with imaginary parts indicate the graph does not cross the x-axis at those points.
3Step 3: Finding y-intercept
The y-intercept is the point where the graph crosses the y-axis, i.e., when \(x=0\). Plugging x=0 in the function we get, \(f(0) = (0)^3 + (0)^2 - 4*(0) -4 = -4\). Thus, the y-intercept is (-4).
4Step 4: Check Symmetry
A function has y-axis symmetry if \(f(-x) = f(x)\) for all \(x\) in the function's domain and has origin symmetry if \(f(-x) = -f(x)\). For the function \(f(x) = x^3 + x^2 - 4x -4\), neither condition holds true. Hence, the graph has neither y-axis symmetry nor origin symmetry.
5Step 5: Additional Points and Completing the Graph
The degree of the polynomial is 3 so there can be at most two turning points. By plotting the function in a graphing utility, we see the function has one turning point near \((-1, -6)\). With the maximum number of turning points (2), end behavior, x and y intercepts, you can then graph the function.
Key Concepts
Leading Coefficient TestEnd Behaviorx-interceptsSymmetry of Functions
Leading Coefficient Test
The leading coefficient test helps us determine the end behavior of a polynomial function's graph. For a given polynomial, the leading coefficient is the coefficient of the highest degree term. In our function, \(f(x) = x^3 + x^2 - 4x - 4\), the leading term is \(x^3\), which has a leading coefficient of 1.
We have a cubic polynomial, indicating an odd degree with a positive leading coefficient. This means the graph will behave as follows:
We have a cubic polynomial, indicating an odd degree with a positive leading coefficient. This means the graph will behave as follows:
- As \(x \to -\infty\), \(f(x) \to -\infty\)
- As \(x \to \infty\), \(f(x) \to \infty\)
End Behavior
End behavior refers to the behavior of a graph as \(x\) approaches positive or negative infinity. For polynomial functions, this is primarily determined by the degree of the polynomial and the sign of the leading coefficient.
In the polynomial \(f(x) = x^3 + x^2 - 4x - 4\), we know from the leading coefficient test that it behaves like \(x^3\):
In the polynomial \(f(x) = x^3 + x^2 - 4x - 4\), we know from the leading coefficient test that it behaves like \(x^3\):
- As \(x\) becomes very large positively, \(f(x)\) also becomes very large.
- As \(x\) becomes very large negatively, \(f(x)\) becomes very negative as well.
x-intercepts
The x-intercepts of a polynomial are the points where the graph crosses the x-axis, which occurs when \(f(x) = 0\).
To find the x-intercepts of \(f(x) = x^3 + x^2 - 4x - 4\), we solve the equation \(x^3 + x^2 - 4x - 4 = 0\). Using a solver, we find:
To find the x-intercepts of \(f(x) = x^3 + x^2 - 4x - 4\), we solve the equation \(x^3 + x^2 - 4x - 4 = 0\). Using a solver, we find:
- One real root at approximately \(x = -2.65\)
- Two complex roots at \(x \approx 0.732051 \pm 1.03923i\)
Symmetry of Functions
The symmetry of a function can reveal important characteristics about the graph. We check for two types of symmetry: y-axis and origin symmetry.
A function has y-axis symmetry if \(f(-x) = f(x)\) for all \(x\), meaning the graph is a mirror image along the y-axis. Origin symmetry occurs if \(f(-x) = -f(x)\), making the graph rotate 180 degrees around the origin.
For \(f(x) = x^3 + x^2 - 4x - 4\), attempting to substitute \(-x\) into the function, it results in neither condition being satisfied:
A function has y-axis symmetry if \(f(-x) = f(x)\) for all \(x\), meaning the graph is a mirror image along the y-axis. Origin symmetry occurs if \(f(-x) = -f(x)\), making the graph rotate 180 degrees around the origin.
For \(f(x) = x^3 + x^2 - 4x - 4\), attempting to substitute \(-x\) into the function, it results in neither condition being satisfied:
- \(f(-x) = -x^3 + x^2 + 4x - 4\) (not equal to \(f(x)\) or \(-f(x)\))
Other exercises in this chapter
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