Problem 42
Question
(a) Graph the conics $$r=\frac{e d}{(1+e \sin \theta)}$$ for \(e=1\) and various values of \(d .\) How does the value of \(d\) affect the shape of the conic? (b) Graph these conics for \(d=1\) and various values of \(e\) How does the value of \(e\) affect the shape of the conic?
Step-by-Step Solution
Verified Answer
Changing \( d \) modifies the parabola size, and changing \( e \) changes the conic type and shape.
1Step 1: Understanding the Conic Section Equation
The given polar equation is \( r = \frac{e d}{1 + e \sin \theta} \), which represents a conic section in polar coordinates. The parameter \( e \) is the eccentricity, determining the type of conic, and \( d \) is the directrix, influencing its scale.
2Step 2: Graphing for Fixed Eccentricity (e = 1)
For \( e = 1 \), the conic is a parabola. Vary \( d \) (e.g., \( d = 0.5, 1, 2 \)) and graph each conic. A smaller \( d \) results in a smaller-scale parabola, while a larger \( d \) results in a larger, more stretched parabola.
3Step 3: Effect of Parameter 'd'
The parameter \( d \) acts as a scaling factor. As \( d \) increases, the parabola widens, and as \( d \) decreases, it narrows. Thus, \( d \) affects the size of the conic section but not its type when \( e = 1 \).
4Step 4: Graphing for Fixed Directrix (d = 1)
Fix \( d = 1 \) and vary \( e \). For \( e = 0.5, 1, 1.5 \), graph the conics. This will show different types of conics: \( e < 1 \) (an ellipse), \( e = 1 \) (a parabola), and \( e > 1 \) (a hyperbola).
5Step 5: Effect of Eccentricity 'e'
The eccentricity \( e \) determines the type of conic: an ellipse if \( e < 1 \), a parabola if \( e = 1 \), and a hyperbola if \( e > 1 \). As \( e \) varies from less than 1 to greater than 1, the conic transitions through these types.
Key Concepts
EccentricityPolar CoordinatesDirectrix
Eccentricity
Eccentricity, denoted by the symbol \( e \), is a key parameter in defining the shape of a conic section. It tells us how much the conic deviates from being circular. Depending on its value, the conic section can take different forms:
- **Ellipse**: If \( e < 1 \), the conic is an ellipse, which means the shape looks like an elongated circle. The smaller the \( e \), the more rounded the ellipse appears.
- **Parabola**: If \( e = 1 \), the conic becomes a parabola. Parabolas are mirror-symmetrical and open shapes.
- **Hyperbola**: If \( e > 1 \), the conic is identified as a hyperbola. Hyperbolas look like two opposite-facing curves.
Polar Coordinates
Polar coordinates are a way to define the position of a point in a two-dimensional plane. Unlike the Cartesian coordinate system, which uses \( x \) and \( y \) coordinates, polar coordinates use the distance from a reference point and an angle from a reference direction to specify locations.
- The reference point, often labeled as the origin or pole, serves as the starting point for measure.
- The angular coordinate, \( \theta \), is the angle measured from a fixed direction, commonly the positive x-axis.
- The radial coordinate, \( r \), is the direct distance from the pole to the point.
Directrix
The directrix is another fundamental component in understanding conic sections. It is a straight line that helps in defining the conic along with a focus and eccentricity. Essentially, the directrix serves as a reference line that, together with the focus, helps describe the set of points that form the conic section.
- For ellipses and parabolas, there is usually one directrix, while hyperbolas have two.
- The role of the directrix in equations is crucial, as seen in \( r = \frac{e d}{1 + e \sin \theta} \). The parameter \( d \) corresponds to the distance from a directrix.
- When dealing with parabolas, the distance from any point on the parabola to the focus equals the perpendicular distance from the point to the directrix.
Other exercises in this chapter
Problem 41
Find an equation for the conic section with the given properties. The hyperbola with foci \(F_{1}(1,-5)\) and \(F_{2}(1,5)\) that passes through the point \((1,
View solution Problem 41
Find an equation for the parabola that has its vertex at the origin and satisfies the given condition(s). Directrix: \(x=\frac{1}{20}\)
View solution Problem 42
Finding the Equation of an Ellipse Find an equation for the ellipse that satisfies the given conditions. Foci \(F(0, \pm 2),\) vertices: \((0, \pm 3)\)
View solution Problem 42
Find an equation for the hyperbola that satisfies the given conditions. Vertices: \((0, \pm 6),\) asymptotes: \(y=\pm \frac{1}{3} x\)
View solution