Problem 42
Question
41–54 These problems involve combinations. Pizza Toppings In how many ways can three pizza toppings be chosen from 12 available toppings?
Step-by-Step Solution
Verified Answer
There are 220 ways to choose three pizza toppings from twelve.
1Step 1: Identify the Problem Type
The problem involves choosing three toppings from a set of 12 available toppings, which is a combination problem. In combination problems, the order does not matter.
2Step 2: Know the Combination Formula
Recall the formula for combinations, which is \( C(n, r) = \frac{n!}{r!(n-r)!} \), where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose.
3Step 3: Substitute the Given Values
In this exercise, \( n = 12 \) and \( r = 3 \). Substitute these values into the combination formula: \[C(12, 3) = \frac{12!}{3!(12-3)!}\]
4Step 4: Simplify the Factorials
Simplify the expression by calculating the factorials:\[12! = 12 \times 11 \times 10 \times 9! \quad\text{and}\quad 9! = \text{cancels out with the denominator},\]\[C(12, 3) = \frac{12 \times 11 \times 10}{3!}\]Calculate \(3! = 3 \times 2 \times 1 = 6\).
5Step 5: Complete the Calculation
Now, perform the division:\[\frac{12 \times 11 \times 10}{6} = \frac{1320}{6} = 220\]So, there are 220 ways to choose three toppings from 12 available toppings.
Key Concepts
FactorialsCombination FormulaProblem Solving Steps
Factorials
Factorials are a fundamental concept in mathematics that often appear in calculations involving permutations and combinations. A factorial is the product of all positive integers up to a given number.
For example, the factorial of 5, denoted as 5!, is calculated as:
Factorials grow rapidly with larger numbers, which can lead to very large values even for relatively small integers. Understanding how to work with factorials efficiently, such as through simplification or canceling terms, is key to solving combination problems efficiently.
For example, the factorial of 5, denoted as 5!, is calculated as:
- 5! = 5 × 4 × 3 × 2 × 1 = 120
Factorials grow rapidly with larger numbers, which can lead to very large values even for relatively small integers. Understanding how to work with factorials efficiently, such as through simplification or canceling terms, is key to solving combination problems efficiently.
Combination Formula
The combination formula is an essential mathematical tool for finding the number of ways to choose a subset of items from a larger set, where the order of selection does not matter.
The formula is expressed as:
This makes it particularly useful in situations like choosing pizza toppings, where the order of topping selection doesn't change the outcome.
The formula is expressed as:
- \( C(n, r) = \frac{n!}{r!(n-r)!} \)
- \( n \) is the total number of items available.
- \( r \) is the number of items to be chosen.
This makes it particularly useful in situations like choosing pizza toppings, where the order of topping selection doesn't change the outcome.
Problem Solving Steps
Approaching a combination problem methodically improves your chances of solving it correctly.
Here is a clear step-by-step approach you can use:
Here is a clear step-by-step approach you can use:
- Identify the Problem Type: Recognize that the problem involves combinations, meaning the order doesn't matter.
- Recall the Combination Formula: Make sure you are familiar with the formula \( C(n, r) = \frac{n!}{r!(n-r)!} \).
- Substitute the Given Values: Input your specific problem values into the formula. For example, if you have 12 items and you need to choose 3, set \( n = 12 \) and \( r = 3 \).
- Simplify the Factorials: Break down large factorials to manageable pieces and cancel out common terms to simplify the calculation.
- Complete the Calculation: Perform the final division to find the number of combinations. For instance, \( \frac{12 \times 11 \times 10}{6} = 220 \) tells us there are 220 ways to choose the 3 items from 12.
Other exercises in this chapter
Problem 41
41–54 These problems involve combinations. Choosing Books In how many ways can three books be chosen from a group of six?
View solution Problem 41
A committee of five is chosen randomly from a group of six males and eight females. What is the probability that the committee includes either all males or all
View solution Problem 42
Explain why in any group of 677 people, at least two people must have the same pair of initials.
View solution Problem 42
In the 6/49 lottery game a player selects six numbers from 1 to 49. What is the probability of selecting at least five of the six winning numbers?
View solution