Problem 42
Question
\(23-44=\) Find the exact value of the expression, if it is defined. \(\tan \left(\sin ^{-1} \frac{\sqrt{2}}{2}\right)\)
Step-by-Step Solution
Verified Answer
The value of the expression is 1.
1Step 1: Understand the Inverse Sine Function
Recognize that \(\sin^{-1}\left( \frac{\sqrt{2}}{2} \right)\) is the angle whose sine value is \(\frac{\sqrt{2}}{2}\). This is a commonly known angle in the unit circle which corresponds to \(\frac{\pi}{4}\) or \(45^\circ\).
2Step 2: Determine the Tangent of the Angle
Next, we need to find \(\tan\left( \frac{\pi}{4} \right)\). From trigonometric identities, we know that \(\tan(\frac{\pi}{4}) = 1\).
3Step 3: Combine the Steps
Combine the results from Step 1 and Step 2 to find \(\tan\left(\sin^{-1} \left(\frac{\sqrt{2}}{2}\right)\right) = \tan\left(\frac{\pi}{4}\right) = 1\).
Key Concepts
Inverse Trigonometric FunctionsUnit CircleTrigonometric Identities
Inverse Trigonometric Functions
Inverse trigonometric functions, like \( \sin^{-1}, \cos^{-1}, \) and \( \tan^{-1} \), allow us to find the angle that corresponds to a particular trigonometric ratio. When you see \( \sin^{-1}(x) \), it means "the angle whose sine is \( x \)." These functions are incredibly useful for solving problems involving angles and measurements.
For example, in this problem, \( \sin^{-1}(\frac{\sqrt{2}}{2}) \) represents the angle whose sine value is \( \frac{\sqrt{2}}{2} \). This is a familiar angle from the unit circle, namely \( \frac{\pi}{4} \) radians, or \( 45^{\circ} \).
These inverse functions have specific ranges to ensure that they return a unique value (angle). For instance, \( \sin^{-1}(x) \) returns values in the range of \(-\frac{\pi}{2} \) to \( \frac{\pi}{2} \). This makes them a powerful tool for finding exact angle values based on trigonometric ratios.
For example, in this problem, \( \sin^{-1}(\frac{\sqrt{2}}{2}) \) represents the angle whose sine value is \( \frac{\sqrt{2}}{2} \). This is a familiar angle from the unit circle, namely \( \frac{\pi}{4} \) radians, or \( 45^{\circ} \).
These inverse functions have specific ranges to ensure that they return a unique value (angle). For instance, \( \sin^{-1}(x) \) returns values in the range of \(-\frac{\pi}{2} \) to \( \frac{\pi}{2} \). This makes them a powerful tool for finding exact angle values based on trigonometric ratios.
Unit Circle
The unit circle is a foundational concept for understanding trigonometry. It's a circle with a radius of 1, centered at the origin of a coordinate plane. The unit circle helps us visualize angles and their corresponding sine, cosine, and tangent values.
In the unit circle, each angle correlates to a point on the circle, with coordinates \((\cos(\theta), \sin(\theta))\). For the angle \(\frac{\pi}{4}\), the point is \((\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2})\). This is because both the sine and cosine of \(\frac{\pi}{4}\) are \(\frac{\sqrt{2}}{2}\).
In the unit circle, each angle correlates to a point on the circle, with coordinates \((\cos(\theta), \sin(\theta))\). For the angle \(\frac{\pi}{4}\), the point is \((\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2})\). This is because both the sine and cosine of \(\frac{\pi}{4}\) are \(\frac{\sqrt{2}}{2}\).
- The circle allows us to immediately see the relationship between different trigonometric functions.
- It is easy to determine common values like \(\tan(\theta)\) by using \(\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}\).
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that are true for all values of the variable where both sides are defined. One fundamental identity is \(\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}\), which is crucial in solving the problem given.
Utilizing these identities aids in transforming complex trigonometric expressions into simpler, more manageable forms, helping solve exercises efficiently.
- Knowing \(\sin(\theta)\) and \(\cos(\theta)\), you can directly find \(\tan(\theta)\).
- This identity helps balance expressions and simplify calculations.
Utilizing these identities aids in transforming complex trigonometric expressions into simpler, more manageable forms, helping solve exercises efficiently.
Other exercises in this chapter
Problem 41
\(29-42\) . Find the amplitude, period, and phase shift of the function, and graph one complete period. $$ y=\sin (\pi+3 x) $$
View solution Problem 41
Find the period and graph the function. $$ y=\tan 2(x-\pi) $$
View solution Problem 42
\(29-42\) . Find the amplitude, period, and phase shift of the function, and graph one complete period. $$ y=\cos \left(\frac{\pi}{2}-x\right) $$
View solution Problem 42
Find the period and graph the function. $$ y=\sec 2\left(x-\frac{\pi}{2}\right) $$
View solution