Problem 41
Question
Write each of the following in terms of \(i\) and simplify. For example, $$ \sqrt{-20}=i \sqrt{20}=i \sqrt{4} \sqrt{5}=2 i \sqrt{5} $$ $$12 \sqrt{-90}$$
Step-by-Step Solution
Verified Answer
\(12 \sqrt{-90} = 36i \sqrt{10}\)
1Step 1: Recognize the Imaginary Unit
Identify the imaginary unit associated with the negative number under the square root. Here, we have \(-90\), which indicates the use of the imaginary unit \(i\) where \(i = \sqrt{-1}\).
2Step 2: Factor the Negative Number
Write \(-90\) as \(-1 \times 90\). This allows us to separate the negative part from the positive for the use of the imaginary unit.
3Step 3: Apply the Imaginary Unit
Since \(\sqrt{-90} = \sqrt{-1 \times 90}\), it becomes \(\sqrt{-1} \times \sqrt{90}\). Using \(\sqrt{-1} = i\), it becomes \(i \sqrt{90}\).
4Step 4: Simplify the Square Root
Factor \(90\) into a product of perfect squares: \(90 = 9 \times 10\). Thus, \(\sqrt{90} = \sqrt{9} \times \sqrt{10} = 3 \times \sqrt{10}\).
5Step 5: Combine the Results
Combine the imaginary unit with the simplified square root: \(12 \sqrt{-90} = 12 \times i \times 3 \times \sqrt{10} = 36i \sqrt{10}\).
Key Concepts
Complex NumbersSquare RootsSimplificationAlgebraic Expressions
Complex Numbers
Complex numbers might sound a bit complicated at first because they involve an imaginary unit, but they are not that difficult once you break them down. A complex number is a number that has both a real part and an imaginary part. The standard form is written as:
- Real part: a
- Imaginary part: bi (where i is the imaginary unit, which equals \(\sqrt{-1}\)).
- They extend our numeric system beyond the real numbers.
- They enable us to effectively work with and solve equations that don't have real solutions.
Square Roots
The square root is another essential concept when dealing with both real and complex numbers. Simply put, finding a square root is like reverse multiplication. When you take the square root of a number, you're finding a value which, when multiplied by itself, gives that number back.Consider the square root of a positive number, like 9. It’s straightforward: \(\sqrt{9} = 3\) because \(3 \times 3 = 9\). But what about negative numbers? This is where the imaginary unit i comes into play. We can't find the square root of a negative number without using i because there is no real number that, when squared, will result in a negative.That’s why \(\sqrt{-90}\) was rewritten as \(i\sqrt{90}\). Separation of components inside the square root sign allows us to manage with real numbers by setting aside the negative part for i.
Simplification
Simplification in mathematics, especially when dealing with square roots, helps make expressions easier to work with. The goal is to get to the simplest form without altering the value.When it comes to expressions involving square roots of negative numbers, like in our example \(12\sqrt{-90}\), simplification involves several steps:
- First, recognize that there's an imaginary component. \(\sqrt{-1}\) separates as i.
- Next, decompose the components of the square root into simpler parts.
- Identify any perfect squares, which are numbers like 4, 9, or 16 — numbers that have whole number square roots.
- The expression \(\sqrt{90}\) gets broken down into \(3\sqrt{10}\) because \90 = 9 \times 10\ and \(\sqrt{9} = 3\).
- Finally, gather the results and multiply them, ensuring you're following mathematical operations order.
Algebraic Expressions
Algebraic expressions, like the one involved in \(12\sqrt{-90}\), are basic tools in algebra involving variables, numbers, and operations together. Think of them as mathematical phrases that can include constants (like the 12), variables (like x or y), coefficients (numbers in front of variables), and even imaginary units.By breaking down the algebraic expression you've got:
- The constant 12, which stays the same.
- The operation of multiplication connecting all parts — the root, the number, and the imaginary unit.
- Finally, the simplified square root, as previously calculated.
Other exercises in this chapter
Problem 41
Use the quadratic formula to solve each of the quadratic equations. Check your solutions by using the sum and product relationships. $$6 t^{2}+t-3=0$$
View solution Problem 41
Solve each quadratic equation using the method that seems most appropriate. $$2 n^{2}-8 n=-3$$
View solution Problem 42
Solve each inequality. $$-3 x^{2}-27 \geq 0$$
View solution Problem 42
Set up an equation and solve each problem. Find two consecutive odd whole numbers such that the sum of their squares is 74 .
View solution