Problem 41
Question
Write an equation of the circle with the given center and radius. See Example 8. $$ (0,0) ; \sqrt{3} $$
Step-by-Step Solution
Verified Answer
The equation of the circle is \( x^2 + y^2 = 3 \).
1Step 1: Understanding the Formula
To write the equation of a circle, we use the standard form of the circle's equation: \[ (x - h)^2 + (y - k)^2 = r^2 \]where \((h, k)\) is the center of the circle, and \(r\) is the radius.
2Step 2: Substitute the Center
The center of the circle is given as \((0,0)\). Substitute \(h = 0\) and \(k = 0\) into the standard circle equation:\[ (x - 0)^2 + (y - 0)^2 = r^2 \].Simplifying, we get: \[ x^2 + y^2 = r^2 \].
3Step 3: Substitute the Radius
The radius of the circle is given as \(\sqrt{3}\). Substitute \(r = \sqrt{3}\) into the equation:\[ x^2 + y^2 = (\sqrt{3})^2 \].Since \((\sqrt{3})^2 = 3\), the equation becomes:\[ x^2 + y^2 = 3 \].
4Step 4: Final Equation of the Circle
Now that we have substituted both the center and the radius, the final equation of the circle is:\[ x^2 + y^2 = 3 \].
Key Concepts
Center of a CircleRadius of a CircleStandard Form of a CircleSubstitution in Equations
Center of a Circle
In mathematics, the center of a circle is an important concept that refers to the fixed point located exactly in the middle of the circle. The center is denoted in coordinate geometry as
For the given example, the center of the circle is
- \((h, k)\) in the general equation where \(h\) and \(k\) are the \(x\) and \(y\) coordinates, respectively.
- It's the point where the radii of the circle meet and is equidistant from any point on the circumference.
For the given example, the center of the circle is
- \((0, 0)\), often referred to as the origin.
Radius of a Circle
The radius of a circle refers to the distance between the center of the circle and any point on its circumference. It is a crucial measurement that determines the size of the circle. In the standard equation of a circle, the radius is denoted by \(r\).
In the given exercise, the radius is
This positive value ensures the circle is drawn proportionate to its center.
It contributes significantly to the shape and size of the resulting circle equation.
In the given exercise, the radius is
- \(\sqrt{3}\), which is a numerical value representing the circle's extent.
This positive value ensures the circle is drawn proportionate to its center.
It contributes significantly to the shape and size of the resulting circle equation.
Standard Form of a Circle
The standard form of a circle's equation is a fundamental algebraic representation that helps in identifying essential characteristics of a circle. Given by the formula:
The right side, \(r^2\), represents the square of the radius.
The purpose of this form is to conveniently display the circle’s equation in geometry; making it easy to understand its position and size in a coordinate system.
- \((x - h)^2 + (y - k)^2 = r^2 \).
- \((h, k)\) as the center of the circle.
- \(r\) as the radius.
The right side, \(r^2\), represents the square of the radius.
The purpose of this form is to conveniently display the circle’s equation in geometry; making it easy to understand its position and size in a coordinate system.
Substitution in Equations
Substitution is a widely used method in algebra where specific values are inserted into an equation to find a solution or result. In the context of circle equations:
For instance, with a circle centered at \((0,0)\) and radius \(\sqrt{3}\), after substitution, we find the equation simplifies to \(x^2 + y^2 = 3\).
This step ensures that we come to an accurate and precise representation of the circle.Using substitution efficiently solves the initial question about the circle’s specific equation, maintaining correctness and understanding.
- You substitute the values for the center \((h, k)\) and radius \(r\) into the standard form.
For instance, with a circle centered at \((0,0)\) and radius \(\sqrt{3}\), after substitution, we find the equation simplifies to \(x^2 + y^2 = 3\).
This step ensures that we come to an accurate and precise representation of the circle.Using substitution efficiently solves the initial question about the circle’s specific equation, maintaining correctness and understanding.
Other exercises in this chapter
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