Problem 41
Question
Which term of the arithmetic sequence \(1,4,7, \ldots\) is \(88 ?\)
Step-by-Step Solution
Verified Answer
The 30th term of the sequence is 88.
1Step 1: Identify the sequence parameters
An arithmetic sequence is defined by its first term (\(a_1\)) and common difference (\(d\)). From the given sequence \(1, 4, 7, \ldots\), we can see that \(a_1 = 1\) and the common difference \(d = 4 - 1 = 3\).
2Step 2: Write the formula for the \(n\)-th term
The formula for the \(n\)-th term of an arithmetic sequence is given by \(a_n = a_1 + (n-1) \times d\).
3Step 3: Set up the equation for the \(n\)-th term
We want to find which term \(a_n\) equals \(88\). So, we set up the equation: \(88 = 1 + (n-1) \times 3\).
4Step 4: Solve the equation for \(n\)
First, simplify the right side: \(88 = 1 + 3n - 3\). This leads to \(88 = 3n - 2\). Add 2 to both sides, resulting in \(90 = 3n\). Finally, divide both sides by 3: \(n = \frac{90}{3} = 30\).
5Step 5: Verify the solution
Check if the 30th term is indeed 88 by calculating it using the formula: \(a_{30} = 1 + (30-1) \times 3 = 1 + 87 = 88\). The calculation confirms our solution.
Key Concepts
Common Differencen-th Term FormulaSequence Parameters
Common Difference
An arithmetic sequence is defined by having equal differences between consecutive terms. This difference is termed the "common difference." It's a crucial component in identifying and working with arithmetic sequences. In our exercise, the sequence provided is \(1, 4, 7, \ldots\). To find the common difference \(d\), subtract the first term from the second term:
The sequence continues by adding this common difference to each subsequent term.
- Second term: 4
- First term: 1
- Common difference \(d = 4 - 1 = 3\)
The sequence continues by adding this common difference to each subsequent term.
n-th Term Formula
The n-th term formula is the backbone of finding the value of any term in an arithmetic sequence. For an arithmetic sequence, the n-th term, denoted as \(a_n\), can be calculated using the initial term \(a_1\) and the common difference \(d\). The formula is:\[a_n = a_1 + (n-1) \times d\]This formula is derived from adding the common difference \(d\)
- \((n-1)\times\) times to the first term \(a_1\)
Sequence Parameters
Sequence parameters are crucial in defining the nature of any arithmetic sequence. The two primary parameters are:
- \(a_1\) - the first term of the sequence
- \(d\) - the common difference
- The first term \(a_1 = 1\)
- The common difference \(d = 3\)
Other exercises in this chapter
Problem 40
\(37-40\) . Find the first four partial sums and the nth partial sum of the sequence \(a_{m}\) \(a_{n}=\log \left(\frac{n}{n+1}\right) \quad[\text { Hint: Use a
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Find the term containing \(y^{3}\) in the expansion of \((\sqrt{2}+y)^{12}\)
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Which term of the geometric sequence \(2,6,18, \ldots\) is \(118,098 ?\)
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\(41-48\) Find the sum. $$ \sum_{k=1}^{4} k $$
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