Problem 41
Question
Which of the following gas is evolved when cupric sulphide (CuS) is dissolved in dilute hydrochloric acid \((\mathrm{HCl}) ?\) (a) \(\mathrm{S}\) (b) \(\mathrm{Cl}_{2}\) (c) \(\mathrm{H}_{2} \mathrm{~S}\) (d) \(\mathrm{H}_{2}\)
Step-by-Step Solution
Verified Answer
The gas evolved is hydrogen sulfide, \(\mathrm{H}_2\mathrm{S}\).
1Step 1: Identify the Reaction Components
Cupric sulphide is known as \(\text{CuS}\), and we are considering its reaction with dilute hydrochloric acid \(\text{HCl}\). Our task is to determine which gas is produced when these two react.
2Step 2: Write the Reaction Equation
The reaction between cupric sulphide \(\text{CuS}\) and hydrochloric acid \(\text{HCl}\) is: \[ \text{CuS} + 2\text{HCl} \rightarrow \text{CuCl}_2 + \text{H}_2\text{S} \] Here, \(\text{CuCl}_2\) (cupric chloride) is formed, and \(\text{H}_2\text{S}\) (hydrogen sulfide gas) is released.
3Step 3: Analyze the Reaction Products
Upon analyzing the chemical reaction, it is evident that when cupric sulphide reacts with hydrochloric acid, hydrogen sulfide \(\text{H}_2\text{S}\) gas is evolved as one of the products.
4Step 4: Verify the Answer
Given options are: (a) \(\mathrm{S}\), (b) \(\mathrm{Cl}_{2}\), (c) \(\mathrm{H}_{2} \mathrm{~S}\), (d) \(\mathrm{H}_{2}\). From the reaction, we established that hydrogen sulfide \(\mathrm{H}_{2}\mathrm{S}\) is the gas released. Thus, option (c) is correct.
Key Concepts
Chemical ReactionsCupric SulphideDilute Hydrochloric AcidHydrogen Sulfide Gas
Chemical Reactions
Chemical reactions involve the transformation of reactants into products, incorporating changes at the molecular level. When substances interact, the atoms rearrange, forming new compounds as a result of this reorganization. Such reactions can be identified by
- The formation of gas
- Precipitate formation
- Color change
- Temperature change
Cupric Sulphide
Cupric sulphide is a chemical compound represented by the formula \[\text{CuS}\]. It consists of copper and sulfur elements bonded together. This compound is often seen as a black solid, indicative of its metallic nature.
Cupric sulphide is commonly found in its natural state as the mineral covellite. Its applications extend to:
Cupric sulphide is commonly found in its natural state as the mineral covellite. Its applications extend to:
- Catalysis in organic synthesis
- Electrodes in certain types of batteries
- Photovoltaic materials
Dilute Hydrochloric Acid
Dilute hydrochloric acid is simply hydrochloric acid with a reduced concentration. This dilution often makes it safer to handle and react with various substances without causing violent reactions. It retains the fundamental properties of \(\text{HCl}\) and is noted for being:
- A strong acid
- Highly corrosive
- Reactive with metals and bases
Hydrogen Sulfide Gas
Hydrogen sulfide \(\text{H}_2\text{S}\) is a colorless gas known for its characteristic "rotten egg" smell. It naturally occurs in crude petroleum and natural gas, as well as from bacterial breakdown of organic materials. While toxic and flammable, it has distinct uses:
- Precursors in synthetic chemistry
- Production of heavy water
- Lab scale production of many organosulfur compounds
Other exercises in this chapter
Problem 36
Bell metal is an alloy of (a) \(\mathrm{Cu}+\mathrm{Sn}\) (b) \(\mathrm{Cu}+\mathrm{Zn}\) (c) \(\mathrm{Cu}+\mathrm{Ni}\) (d) \(\mathrm{Cu}+\mathrm{Pb}\)
View solution Problem 39
Which of the following metal does not react with the solution of copper sulphate? (a) \(\mathrm{Fe}\) (b) \(\mathrm{Zn}\) (c) \(\mathrm{Ag}\) (d) \(\mathrm{Mg}\
View solution Problem 42
On strongly heating copper nitrate, we get (a) copper metal (b) cuprous oxide (c) cupric oxide (d) copper sulphate
View solution Problem 43
What is formed when \(\mathrm{H}_{2} \mathrm{~S}\) is passed through acidified solution of \(\mathrm{CuSO}_{4}\) ? (a) \(\mathrm{CuSO}_{4}\) (b) \(\mathrm{CuS}\
View solution