Problem 41
Question
Verify the given identity. $$ 1+\frac{1}{\cos x}=\frac{\tan ^{2} x}{\sec x-1} $$
Step-by-Step Solution
Verified Answer
Identity verified; both sides simplify to \( \frac{1+\cos x}{\cos x} \).
1Step 1: LHS Transformation
Start with the left-hand side of the equation: \( 1 + \frac{1}{\cos x} \). Express 1 as \( \cos x / \cos x \) so the expression becomes \( \frac{\cos x + 1}{\cos x} \).
2Step 2: Simplify RHS
The right-hand side is \( \frac{\tan^2 x}{\sec x - 1} \). Recall that \( \tan x = \frac{\sin x}{\cos x} \) and \( \sec x = \frac{1}{\cos x} \), thus \( \tan^2 x = \frac{\sin^2 x}{\cos^2 x} \) and \( \sec x - 1 = \frac{1}{\cos x} - 1 = \frac{1 - \cos x}{\cos x} \).
3Step 3: Transform RHS Further
Substitute the expressions for \( \tan^2 x \) and \( \sec x - 1 \) from Step 2 into the RHS: \( \frac{\frac{\sin^2 x}{\cos^2 x}}{\frac{1-\cos x}{\cos x}} = \frac{\sin^2 x}{(1-\cos x)\cos x} \).
4Step 4: Use Pythagorean Identity
Use the identity \( \sin^2 x = 1 - \cos^2 x \) to rewrite \( \sin^2 x \) in terms of \( \cos x \): \( \sin^2 x = (1-\cos x)(1+\cos x) \). Substitute this back into the RHS: \( \frac{(1-\cos x)(1+\cos x)}{(1-\cos x)\cos x} \).
5Step 5: Simplify Final Expression
Cancel the common factor \((1-\cos x)\) from numerator and denominator: \( \frac{1+\cos x}{\cos x} \).
6Step 6: Compare Simplified Expressions
Notice both LHS, \( \frac{1+\cos x}{\cos x} \), and RHS, \( \frac{1+\cos x}{\cos x} \), are identical after simplification, thus verifying the identity.
Key Concepts
Pythagorean IdentityTrigonometric TransformationVerification of Trigonometric Identities
Pythagorean Identity
The Pythagorean Identity is a foundational concept in trigonometry. It tells us that for any angle \( x \), the equation \( \sin^2 x + \cos^2 x = 1 \) holds true. This can be incredibly useful when verifying or transforming trigonometric identities. By using this identity, we can express one trigonometric function in terms of another, which often simplifies the original problem.
- For instance, if we need \( \sin^2 x \), we can rewrite it as \( 1 - \cos^2 x \).
- Similarly, \( \cos^2 x \) can be expressed as \( 1 - \sin^2 x \).
Trigonometric Transformation
Trigonometric transformations involve manipulating expressions using known identities and relationships between trigonometric functions, such as tangent, secant, sine, and cosine. Transformations allow us to convert a complex expression or equation into a simpler form or another equivalent form.
In the context of our exercise, several transformations were applied:
In the context of our exercise, several transformations were applied:
- The expression for \( 1 \) was transformed into \( \cos x / \cos x \) to combine with another fraction.
- The identity \( \tan x = \sin x / \cos x \) was used, where \( \tan^2 x \) turned into \( \sin^2 x / \cos^2 x \).
- The transformation continued by turning \( \sec x - 1 \) into \( (1 - \cos x) / \cos x \).
Verification of Trigonometric Identities
Verification of trigonometric identities involves showing that two sides of a given equation are equivalent for all values of the involved variables. This involves simplifying both sides of the equation independently until they are shown to be the same.
The process often requires:
The process often requires:
- Identifying and applying suitable trigonometric identities, like the Pythagorean Identity.
- Performing algebraic manipulations such as factoring, combining fractions, or canceling common terms.
Other exercises in this chapter
Problem 41
Find the period and the vertical asymptotes of the given function. Sketch at least one cycle of the graph. $$ y=\sec \left(3 x-\frac{\pi}{2}\right) $$
View solution Problem 41
Find the amplitude, period, and phase shift of the given function. Sketch at least one cycle of the graph. $$ y=\sin \left(3 x-\frac{\pi}{4}\right) $$
View solution Problem 41
Find all solutions of the given trigonometric equation if \(x\) is a real number and \(\theta\) is an angle measured in degrees. $$ \sin \theta+\cos \theta=1 $$
View solution Problem 41
Sketch the graph of the given function. $$ y=\arctan |x| $$
View solution