Problem 41
Question
Vanadium and carbon form vanadium carbide, an interstitial alloy. Given the atomic radii of \(\mathrm{V}(135 \mathrm{pm})\) and \(\mathrm{C}(77 \mathrm{pm}),\) which holes in a cubic closest-packed array of vanadium atoms do you think the carbon atoms are more likely to occupy-octahedral or tetrahedral?
Step-by-Step Solution
Verified Answer
Answer: Carbon atoms are more likely to occupy tetrahedral holes.
1Step 1: Calculate the octahedral hole size
The size of the octahedral hole in a cubic closest-packed structure can be calculated as:
Octahedral hole size = \(\sqrt{2}\) x radius of a vanadium atom
Using the given atomic radius of vanadium (135 pm), the calculation becomes:
Octahedral hole size = \(\sqrt{2}\) x 135 pm ≈ 190.92 pm
2Step 2: Calculate the tetrahedral hole size
The size of the tetrahedral hole in a cubic closest-packed structure can be calculated as:
Tetrahedral hole size = \(\sqrt{3}/2\) x radius of a vanadium atom
Using the given atomic radius of vanadium (135 pm), the calculation becomes:
Tetrahedral hole size = \(\sqrt{3}/2\) x 135 pm ≈ 116.88 pm
3Step 3: Compare hole sizes with carbon's atomic radii
Now that we have both the octahedral and tetrahedral hole sizes, we will compare them to the atomic radius of carbon (77 pm) given in the exercise:
Octahedral hole size = 190.92 pm
Tetrahedral hole size = 116.88 pm
Carbon's atomic radius = 77 pm
4Step 4: Determine the hole in which the carbon atom fits
Comparing the hole sizes with the atomic radius of carbon, we can see that the carbon atom is too small to occupy the octahedral hole as it's atomic radius (77 pm) is smaller than the octahedral hole size (190.92 pm). But, the carbon atom fits well into the tetrahedral hole as its atomic radius (77 pm) is closer to the size of the tetrahedral hole (116.88 pm).
Therefore, it is more likely that the carbon atoms will occupy the tetrahedral holes in a cubic closest-packed array of vanadium atoms.
Key Concepts
Octahedral HolesTetrahedral HolesCubic Closest-Packed Structure
Octahedral Holes
When atoms are packed in a three-dimensional structure, spaces or "holes" are created between them. In a cubic closest-packed (ccp) structure, octahedral holes are one kind of space found between the atoms. These holes have a symmetrical, eight-sided shape like an octahedron.
To imagine an octahedral hole, picture two stacked triangular pyramids. These can fit in the spaces surrounded by six atoms in the ccp structure.
To imagine an octahedral hole, picture two stacked triangular pyramids. These can fit in the spaces surrounded by six atoms in the ccp structure.
- Each unit cell in a ccp structure has four octahedral holes.
- These holes are relatively large, making them ideal for larger atoms to fit inside.
Tetrahedral Holes
Tetrahedral holes are another type of space created in a ccp structure. These are smaller than octahedral holes. To picture a tetrahedral hole, think of a four-faced pyramid – a tetrahedron. This space is formed when four atoms come together in a ccp structure.
Unlike octahedral holes, tetrahedral holes are smaller and found in different locations within the unit cell.
Unlike octahedral holes, tetrahedral holes are smaller and found in different locations within the unit cell.
- Each unit cell in a ccp structure contains eight tetrahedral holes.
- These smaller holes can better accommodate smaller atoms or ions.
Cubic Closest-Packed Structure
The cubic closest-packed (ccp) structure is a common and efficient way that atoms
stack together. It is also called face-centered cubic (fcc) because one atom is present on each face of a cube.
This arrangement aims to minimize empty space, allowing atoms to pack tightly together.
This arrangement aims to minimize empty space, allowing atoms to pack tightly together.
- Each atom in a ccp structure is surrounded by 12 others, offering high stability.
- The structure develops a repeating pattern, filling space in a uniform manner.
Other exercises in this chapter
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