Problem 41
Question
Use the Laplace transform to solve the given integral equation or integrodifferential equation. $$ f(t)+\int_{0}^{t} f(\tau) d \tau=1 $$
Step-by-Step Solution
Verified Answer
Apply Laplace transforms and solve algebraically for \(F(s)\).
1Step 1: Apply the Laplace Transform
First, apply the Laplace transform to both terms in the equation. Recall that the Laplace transform of a constant is \(\mathcal{L}\{1\} = \frac{1}{s}\), and the Laplace transform of an integral from \(0\) to \(t\) is \(\frac{F(s)}{s}\). Therefore, the Laplace transform of the equation becomes: \(\mathcal{L}\{f(t)\} + \mathcal{L}\{\int_{0}^{t} f(\tau) d\tau\} = \mathcal{L}\{1\}\).
Key Concepts
Integral EquationIntegrodifferential EquationLaplace Transform PropertiesSolving Differential Equations
Integral Equation
An integral equation involves an unknown function that appears under an integral sign. In mathematical terms, it can be written as a relation where the function is connected to its integral. This type of problem often appears in applied mathematics and physics, where the function must satisfy the constraints of the equation involving its integral. For the given problem, \[ f(t) + \int_{0}^{t} f(\tau) d\tau = 1 \],the goal is to determine the function \( f(t) \) that satisfies this equation for all appropriate values of \( t \).
These solutions help reveal insights into physical processes and systems that can be described mathematically.
- Integral equations are classified by their limits of integration and how the unknown function appears.
- The equation given here is a type of Volterra equation, where the upper limit of the integral is a variable.
These solutions help reveal insights into physical processes and systems that can be described mathematically.
Integrodifferential Equation
An integrodifferential equation combines aspects of both differential and integral equations. These equations involve unknown functions that are differentiated and also appear under integral signs.
They are commonplace in fields that describe dynamic systems, such as biology, engineering, and physics.
In our context, while the problem at hand was more of an integral equation, similar techniques such as the Laplace transform are applied to solve them.
- Integrodifferential equations can model scenarios where both the rate of change and accumulated quantity affect the system's behavior.
- Simplifying these equations often requires the use of advanced techniques like the Laplace and Fourier transforms.
Laplace Transform Properties
The Laplace transform is a powerful tool for solving differential and integral equations. It transforms complex equations from the time domain into a simpler form in the frequency domain. Several key properties make it indispensable:
- Linearity: The Laplace transform of a sum of functions is the sum of their Laplace transforms, i.e., \( \mathcal{L}\{f(t) + g(t)\} = \mathcal{L}\{f(t)\} + \mathcal{L}\{g(t)\} \).
- Integration: The Laplace transform of an integral of a function \( f(t) \) is given by \( \frac{F(s)}{s} \).
- Transforms of constants: Consistent with the concept of a constant having no time variance, the Laplace transform of a constant, \( 1 \), is \( \frac{1}{s} \).
Solving Differential Equations
Solving differential equations is a cornerstone of mathematical modeling, allowing us to predict and analyze the behavior of systems. Applying the Laplace transform here involves:
- Transforming the original differential or integral equation into the \( s \)-domain to make it algebraic.
- Simplifying and solving for \( F(s) \), the Laplace transform of \( f(t) \).
- Using partial fraction decomposition if necessary, to make inverse transformation manageable.
- Applying the inverse Laplace transform, converting \( F(s) \) back into the time domain to find \( f(t) \).
Other exercises in this chapter
Problem 40
Find \(\mathscr{L}\\{f(t)\\}\) by first using an appropriate trigonometric identity. \(f(t) \quad 10 \cos (t-\pi / 6)\)
View solution Problem 40
Use the Laplace transform to solve each system. $$ \begin{aligned} &x^{\prime \prime}+y^{\prime \prime}=e^{2 t} \\ &2 x^{\prime}+y^{\prime \prime}=-e^{2 t} \\ &
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Use the Laplace transform and these inverses to solve the given initial-value problem. $$ y^{\prime}+y=e^{-3 t} \cos 2 t, \quad y(0)=0 $$
View solution Problem 41
One definition of the gamma function \(\Gamma(\alpha)\) is given by the improper integral $$ \Gamma(\alpha) \quad \int_{0}^{\infty} t^{\alpha-1} e^{-t} d t, \al
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