Problem 41
Question
Use a table of values to graph the equation. \(y=4 x-1\)
Step-by-Step Solution
Verified Answer
The graph of the function \(y=4x-1\) is a straight line that passes through the points (0,-1) and (1, 3).
1Step 1: Create a Table of Values
Choose at least two values for x. In this case, let's choose 0 and 1. When \(x=0\), \(y= 4*0 -1 = -1\). When \(x=1\), \(y= 4*1 - 1 = 3\). So, our table of values is: \n (0,-1) and (1, 3)
2Step 2: Plot Points on the Graph
Now that we have our table of values, we can plot these points on the graph. Plot the point (0,-1) on the location where x=0 and y=-1. Likewise, plot the point (1,3) where x=1 and y=3.
3Step 3: Draw a Line Through the Points
The next step is to draw a line that goes through all the points. This line represents the function in our graph. Since we are dealing with a linear function, our line will be straight.
Key Concepts
Table of ValuesPlotting PointsLinear Function
Table of Values
Understanding how to create a table of values is essential when graphing linear equations. Think of it as a tool that translates abstract algebraic expressions into concrete numerical pairs that you can easily plot on a graph. To use a table of values for the linear equation \(y = 4x - 1\), we start by selecting input values for \(x\). These values can be any numbers, but it's often convenient to start with simple ones like 0 and 1, as they make the calculations easier.
For each chosen value of \(x\), we must apply the equation to find the corresponding \(y\) value. Let's calculate a few pairs: If we substitute \(x\) with 0, the equation becomes \(y = 4(0) - 1\), which simplifies to \(y = -1\). Thus, our first pair is (0, -1). If we let \(x = 1\), then \(y = 4(1) - 1 = 3\), and the second pair is (1, 3). We now have a set of points that can be plotted on a graph to represent the equation visually.
For each chosen value of \(x\), we must apply the equation to find the corresponding \(y\) value. Let's calculate a few pairs: If we substitute \(x\) with 0, the equation becomes \(y = 4(0) - 1\), which simplifies to \(y = -1\). Thus, our first pair is (0, -1). If we let \(x = 1\), then \(y = 4(1) - 1 = 3\), and the second pair is (1, 3). We now have a set of points that can be plotted on a graph to represent the equation visually.
Plotting Points
Plotting points is like placing anchors on your graph that map out the path of the equation. Each point represents a real-world combination of \(x\) and \(y\) that satisfies the equation \(y = 4x - 1\). To plot the points from our table of values effectively, begin with your axes labeled and marked evenly.
Take the point (0, -1) we calculated earlier; the first number, 0, tells us where to stand on the \(x\)-axis, and the second number, -1, tells us how far to move up or down on the \(y\)-axis. In this case, since our \(x\) value is 0, we start at the origin and move one unit down on the \(y\)-axis. Similarly, for the point (1, 3), we move one unit right from the origin along the \(x\)-axis and then go up 3 units along the \(y\)-axis. Connecting these 'anchors' will help us visualize the equation's behavior.
Take the point (0, -1) we calculated earlier; the first number, 0, tells us where to stand on the \(x\)-axis, and the second number, -1, tells us how far to move up or down on the \(y\)-axis. In this case, since our \(x\) value is 0, we start at the origin and move one unit down on the \(y\)-axis. Similarly, for the point (1, 3), we move one unit right from the origin along the \(x\)-axis and then go up 3 units along the \(y\)-axis. Connecting these 'anchors' will help us visualize the equation's behavior.
Linear Function
A linear function is the algebraic equivalent of a straight line on a graph. It's an equation of the first degree, which means none of the variables are raised to a power higher than one. For the function we're working with, \(y = 4x - 1\), the convention follows that \(y\) is the dependent variable which changes in response to the independent variable \(x\).
Important characteristics of a linear function include its slope and y-intercept. The slope describes the steepness of the line, in our case, 4. This indicates that for each step we move to the right on the x-axis, the y-value increases by 4 steps. The y-intercept is the point where the line crosses the y-axis, which occurs when \(x\) is zero. In this equation, the y-intercept is -1. Understanding these concepts allows us to chart the function's course and predict its behavior across the graph.
Important characteristics of a linear function include its slope and y-intercept. The slope describes the steepness of the line, in our case, 4. This indicates that for each step we move to the right on the x-axis, the y-value increases by 4 steps. The y-intercept is the point where the line crosses the y-axis, which occurs when \(x\) is zero. In this equation, the y-intercept is -1. Understanding these concepts allows us to chart the function's course and predict its behavior across the graph.
Other exercises in this chapter
Problem 41
Find the value of \(y\) so that the line passing through the two points has the given slope. $$(0, y),(2,5), m=2$$
View solution Problem 41
Write the equation in slope-intercept form. Then graph the equation. $$ x+3 y-3=0 $$
View solution Problem 42
Evaluate the expression for the given value of the variable. (Review 1.3 and 2.5 for 4.2 ) \(3 x+9\) when \(x=2\)
View solution Problem 42
Use a graphing calculator to find the solution of the equation. Check your solution algebraically. $$\frac{3}{4}(4 x-15)=-\frac{3}{2}(4 x-18)$$
View solution