Problem 41
Question
The demand function for a product is modeled by \(p=5000\left(1-\frac{4}{4+e^{-0.002 x}}\right)\) Find the price of the product if the quantity demanded is (a) \(x=100\) units and (b) \(x=500\) units. What is the limit of the price as \(x\) increases without bound?
Step-by-Step Solution
Verified Answer
The price of the product for \( x=100 \) units and \( x=500 \) units will be calculated by substituting these values of \( x \) in the given function and solving the equation. The price of the product as \( x \) increases without bound is equal to the limit of the function as \( x \) approaches infinity.
1Step 1: Substitute \( x = 100 \) in the function
The first requirement is to find the price when \( x=100 \). Substitute \( x=100 \) in the given function to get the corresponding price.
2Step 2: Substitute \( x = 500 \) in the function
The second requirement is to find the price when \( x=500 \). Substitute \( x=500 \) in the given function to get the corresponding price.
3Step 3: Calculate the limit as \( x \) increases without bound
Finally, take the limit of the given function as \( x \) approaches infinity. Here you have to use the limit properties correctly.
Key Concepts
Price CalculationExponential FunctionLimit at Infinity
Price Calculation
In economics, understanding how the price of a product changes with varying demand is vital. This task involves using a demand function, which is a mathematical representation to calculate the price based on demand. For the provided problem, the demand function is:
\[ p = 5000 \left( 1 - \frac{4}{4 + e^{-0.002 x}} \right) \]
To determine the price for specific quantities, we substitute these values directly into the function:- For \( x = 100 \), replace \( x \) in the formula and compute the result to find the price when 100 units are demanded. This process will involve exponential calculation, which we'll address in the next section.
- Similarly, substitute \( x = 500 \) to find the price for 500 units. The function dynamically adjusts the price based on demand through this substitution.
Exponential Function
An exponential function is a mathematical function depicting exponential growth or decay. Here, we're dealing with the term \( e^{-0.002x} \). The constant "\( e \)" is Euler's number, approximately 2.71828, a fundamental base of natural logarithms. The exponent in our function contains \((-0.002x)\) which affects how quickly the function changes as \( x \) increases or decreases.
- When substituting specific values of \( x \), like 100 or 500, calculate \( e^{-0.002x} \) to see its impact. A larger \( x \) results in a smaller exponential term, since \( e^{-0.002x} \) becomes a fraction approaching zero.
- This expression influences how the denominator in the demand function changes, leading directly to alterations in the price.
Limit at Infinity
Taking the limit of a function as a variable approaches infinity helps us understand its behavior over time. For our demand function, we want to see what happens to the price \( p \) as \( x \to \infty \).
The term \( e^{-0.002x} \) approaches zero as \( x \) becomes larger. Consequently, the denominator \( 4 + e^{-0.002x} \) gets closer to 4.
- As \( e^{-0.002x} \to 0 \), the fraction \( \frac{4}{4 + e^{-0.002x}} \to 1 \) since the denominator becomes simply 4.
- Substituting back into the demand function, we see \( 1 - 1 = 0 \). Thus, the expression simplifies to \( 5000 \times 0 = 0 \).
Other exercises in this chapter
Problem 41
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