Problem 41
Question
The conjugate acid of \(\mathrm{NH}_{2}^{-}\)is (a) \(\mathrm{NH}_{4}^{+}\) (b) \(\mathrm{NH}_{3}\) (c) \(\mathrm{NH}_{2} \mathrm{OH}\) (d) \(\mathrm{N}_{2} \mathrm{H}_{4}\)
Step-by-Step Solution
Verified Answer
(b) \(\mathrm{NH}_{3}\)
1Step 1: Understanding the Conjugate Acid
To find the conjugate acid of a base, you must add a proton (\(\text{H}^+\)) to the base. The base in this problem is \(\text{NH}_{2}^{-}\).
2Step 2: Adding a Proton to the Base
Adding a proton (\(\text{H}^+\)) to \(\text{NH}_{2}^{-}\) gives you \(\text{NH}_{3}\). This is because the negative charge of \(\text{NH}_{2}^{-}\) will be neutralized by the added proton.
3Step 3: Identifying the Conjugate Acid
The species obtained after adding a proton, \(\text{NH}_{3}\), is the conjugate acid of the base \(\text{NH}_{2}^{-}\).
4Step 4: Choosing the Correct Answer
From the choices given (a) \(\text{NH}_{4}^{+}\), (b) \(\text{NH}_{3}\), (c) \(\text{NH}_{2}\text{OH}\), (d) \(\text{N}_{2}\text{H}_{4}\), the correct conjugate acid for \(\text{NH}_{2}^{-}\) is \(\text{NH}_{3}\), which corresponds to option (b).
Key Concepts
Proton TransferAmino GroupAcid-Base Reactions
Proton Transfer
The concept of proton transfer is central to understanding many acid-base reactions. In chemistry, a proton transfer refers to the movement of a hydrogen ion (H\(^+\)) from one molecule to another. This process is integral in forming conjugate acid-base pairs.
When a base, like \( ext{NH}_2^-\), accepts a proton, it transforms into its conjugate acid, \( ext{NH}_3\). This transfer of a proton is what distinguishes one member of the pair from the other.
When a base, like \( ext{NH}_2^-\), accepts a proton, it transforms into its conjugate acid, \( ext{NH}_3\). This transfer of a proton is what distinguishes one member of the pair from the other.
- Base (before proton transfer): \( ext{NH}_2^-\)
- Proton (what's transferred): \( ext{H}^+\)
- Conjugate Acid (after proton transfer): \( ext{NH}_3\)
Amino Group
An amino group, chemically denoted as \( ext{-NH}_2\), is a basic functional group commonly found in organic molecules. Its basicity arises primarily from the lone electron pair on the nitrogen atom. This pair can readily accept a proton, rendering the amino group a potential site for proton attachment.
When the amino group \( ext{-NH}_2\) receives a proton, it forms ammonium \(\text{-NH}_3\). Here’s how the process occurs:
When the amino group \( ext{-NH}_2\) receives a proton, it forms ammonium \(\text{-NH}_3\). Here’s how the process occurs:
- The nitrogen atom's lone pair interacts with the incoming proton \(\text{H}^+\).
- As a proton is accepted, the electron pair forms a new N-H bond.
- Once protonated, the group transitions into a positively charged ammonium ion.
Acid-Base Reactions
Acid-base reactions are fundamental to the field of chemistry and involve the transfer of protons between reactants. In the Bronsted-Lowry theory, which is commonly referenced, an acid donates a proton to a base.
The reaction between \(\text{NH}_2^-\) and \(\text{H}^+\) showcases a classic acid-base interaction:
Overall, acid-base reactions are not just limited to the laboratory but occur throughout nature, affecting processes in digestion, cellular respiration, and even buffering systems in the human body.
The reaction between \(\text{NH}_2^-\) and \(\text{H}^+\) showcases a classic acid-base interaction:
- The base, \(\text{NH}_2^-\), accepts the proton \(\text{H}^+\), forming the conjugate acid, \(\text{NH}_3\).
- The original acid (often a hydronium ion or water) loses a proton, turning into its conjugate base.
Overall, acid-base reactions are not just limited to the laboratory but occur throughout nature, affecting processes in digestion, cellular respiration, and even buffering systems in the human body.
Other exercises in this chapter
Problem 39
The best indicator for detection of end point in titration of a weak acid and strong base is (a) methyl red ( 5 to 6 ) (b) methyl orange ( 3 to 4 ) (c) phenolph
View solution Problem 40
The compound that is not a Lewis acid is (a) \(\mathrm{SnCl}_{4}\) (b) \(\mathrm{BeCl}_{2}\) (c) \(\mathrm{BF}_{3}\) (d) \(\mathrm{AlCl}_{3}\)
View solution Problem 43
The compound whose \(0.1 \mathrm{M}\) solution is basic is (a) ammonium acetate (b) ammonium sulphate (c) sodium acetate (d) ammonium chloride
View solution Problem 44
Amongst the following hydroxides, the one which has the lowest value of \(\mathrm{K}_{\mathrm{sp}}\) at ordinary temperature (about \(25^{\circ} \mathrm{C}\) )
View solution