Problem 41
Question
Solve the equation algebraically. Check your solutions by graphing. $$x^{2}+37=118$$
Step-by-Step Solution
Verified Answer
The solutions to the quadratic equation are \(x = 9\) and \(x = -9\).
1Step 1: Arrange the equation
Rearrange the equation to look like a standard quadratic equation \(x^{2}+37=118\), which simplifies to \(x^{2} = 81\) where we subtract 37 from both sides.
2Step 2: Square root of RHS
Take the square root on both sides. We get \(x = \pm 9\). Remember, whenever we take square root in algebra, we consider both + and - values.
3Step 3: Check by Graphing
To verify your solution(s), graph the equation \(y = x^{2} - 81\). The x-intercepts of the graph should correspond to the solution(s) we found, i.e., \(x = 9, -9\).
Key Concepts
Quadratic EquationsGraphing SolutionsSquare Roots
Quadratic Equations
Quadratic equations are a fundamental concept in algebra and are commonly used in various areas of mathematics to model real-world scenarios. These equations take the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants and \(a eq 0\). In the equation, \(x\) represents the variable, or the unknown value you need to find.
A core aspect of solving quadratic equations is that they can produce two possible solutions. This is because the graph of a quadratic equation is a parabola, which can intersect the x-axis at two distinct points, one point, or sometimes none at all.
A core aspect of solving quadratic equations is that they can produce two possible solutions. This is because the graph of a quadratic equation is a parabola, which can intersect the x-axis at two distinct points, one point, or sometimes none at all.
- If the equation intersects the x-axis at two points, it has two real roots.
- If it just touches the x-axis, there is one real double root.
- If it does not touch the x-axis, the roots are complex or imaginary.
Graphing Solutions
Graphing is a useful technique to verify the solutions of quadratic equations visually. When we graph a quadratic equation like \(y = x^2 - 81\), the resulting curve is a parabola. The solutions to the quadratic equation are found where this parabola intersects the x-axis, known as the x-intercepts.
For our equation, after rearranging it as \(x^2 - 81 = 0\), graphing \(y = x^2 - 81\) will help us see that there are two x-intercepts at \(x = 9\) and \(x = -9\). This confirms our algebraic solutions:
For our equation, after rearranging it as \(x^2 - 81 = 0\), graphing \(y = x^2 - 81\) will help us see that there are two x-intercepts at \(x = 9\) and \(x = -9\). This confirms our algebraic solutions:
- When \(x = 9\), \((9)^2 - 81 = 0\)
- When \(x = -9\), \((-9)^2 - 81 = 0\)
Square Roots
The operation of taking square roots is essential when solving quadratic equations, particularly in equations that can be arranged into the form \(x^2 = k\), where \(k\) is a constant. In our example, \(x^2 = 81\), taking the square root of both sides means we seek a number that, when multiplied by itself, results in 81.
Here, the solutions are \(x = 9\) and \(x = -9\) because both \((9)^2 = 81\) and \((-9)^2 = 81\). When taking square roots in algebra, it is important to consider both the positive and negative roots, as both are valid solutions in quadratic contexts.
This duality is rooted in the property of exponents and quadratic equations, where squaring either a positive or negative number results in the same non-negative number. Thus, recognizing that solutions come in pairs is crucial, each with its algebraic significance.
Here, the solutions are \(x = 9\) and \(x = -9\) because both \((9)^2 = 81\) and \((-9)^2 = 81\). When taking square roots in algebra, it is important to consider both the positive and negative roots, as both are valid solutions in quadratic contexts.
This duality is rooted in the property of exponents and quadratic equations, where squaring either a positive or negative number results in the same non-negative number. Thus, recognizing that solutions come in pairs is crucial, each with its algebraic significance.
Other exercises in this chapter
Problem 41
The variables \(x\) and \(y\) vary directly. Use the given values to write an equation that relates x and y . \(\text { (Lesson } 4.6)\) $$ x=6, y=42 $$
View solution Problem 41
Sketch the graph of the function. Label the coordinates of the vertex. $$ y=3 x^{2}-2 x-1 $$
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Use the quadratic formula to solve the equation. If the solution involves radicals, round to the nearest hundredth. $$y^{2}+11 y+10=0$$
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Determine whether the graph of the function will intersect the x-axis in zero, one, or two points. \(y=2 x^{2}+2 x+6\)
View solution