Problem 41
Question
Solve each system by elimination. $$\begin{aligned}&3 x+y=6\\\&6 x+2 y=1\end{aligned}$$
Step-by-Step Solution
Verified Answer
The system has no solution.
1Step 1: Understand the Equations
We are given two equations: \(3x + y = 6\) and \(6x + 2y = 1\). The goal is to eliminate one variable by combining the equations.
2Step 2: Multiply to Align Coefficients
Notice that the second equation \(6x + 2y = 1\) is exactly double the first equation \(3x + y = 6\). Let's multiply the first equation by 2 to align the coefficients of \(x\):\[2(3x + y) = 2(6)\]Which gives us: \(6x + 2y = 12\).
3Step 3: Subtract the Equations
Subtract the new equation \(6x + 2y = 12\) from the original second equation \(6x + 2y = 1\):\[(6x + 2y) - (6x + 2y) = 1 - 12\]This simplifies to: \(0 = -11\).
4Step 4: Analyze the Result
The equation \(0 = -11\) is a contradiction, which means there is no possible solution that can satisfy both equations simultaneously. This implies the system of equations has no solution.
Key Concepts
Elimination MethodNo SolutionLinear Equations
Elimination Method
The elimination method is a technique used to solve systems of linear equations by removing one of the variables. This makes the system easier to solve. To use this method, we manipulate the given equations such that adding or subtracting them eliminates one variable.
- Start with aligning the coefficients of one variable in the two equations. This usually requires multiplying one or both equations by a constant.
- Once the coefficients match, we either add or subtract the equations to eliminate the targeted variable.
- The resulting equation can then be solved to find the value of the remaining variable.
No Solution
In some systems of linear equations, you'll find that they have no solution. This occurs when the equations represent parallel lines that never intersect. In mathematical terms, it often results in an impossible statement like the one in our example, where we derived the equation \(0 = -11\), which is not true.
- When you get a statement like \(0 = a\), where \(a\) is any non-zero number, it indicates no solution.
- This often happens when two equations are essentially multiples of the same equation but have different constants on the right side.
- Such equations describe parallel lines without any point of intersection, thus confirming no solution to the system.
Linear Equations
Linear equations are fundamental in algebra and consist of equations involving variables raised to the power of one. They represent straight lines when graphed on a coordinate plane. A system of linear equations involves finding the point(s) where these lines intersect.
- Each linear equation can be expressed in the form of \(ax + by = c\), where \(a\), \(b\), and \(c\) are constants.
- When solving a system of linear equations, we're seeking the values of \(x\) and \(y\) that satisfy all equations simultaneously.
- There are generally three types of solutions to a system:
- A single solution (lines intersect at one point)
- Infinitely many solutions (lines are identical)
- No solution (lines are parallel)
Other exercises in this chapter
Problem 41
The dimensions of matrices \(A\) and \(B\) are given. Find the dimensions of the product \(A B\) and of the product BA if the products are defined. If they are
View solution Problem 41
Solve each system analytically. If the equations are dependent, write the solution set in terms of the variable \(z\). $$\begin{aligned} &\frac{2}{x}-\frac{2}{y
View solution Problem 42
Write an inequality that satisfies the description.Below the parabola with vertex \((0,1)\) and \(x\) -intercepts \((-1,0)\) and \((1,0)\).
View solution Problem 42
Solve each system by using the matrix inverse method. $$\begin{aligned} 3 x+6 y+3 z &=12 \\ 6 x+4 y-2 z &=-4 \\ y-z &=-3 \end{aligned}$$
View solution