Problem 41
Question
Sketch the quadric surface. \(y^{2}+z^{2}=9\)
Step-by-Step Solution
Verified Answer
It's a circular cylinder along the x-axis with radius 3 in the yz-plane.
1Step 1: Recognize the Equation Type
The equation given is in the form of \[ y^2 + z^2 = 9 \]This is the standard form of a cylinder, specifically a circular cylinder, because it only involves the variables \(y\) and \(z\). The term missing is the \(x\) variable, implying the circular cross-section's invariance along the \(x\)-axis.
2Step 2: Identify the Shape of Cross-sections
Examine the equation \[ y^2 + z^2 = 9 \]This form represents a circle with radius 3 in the \(yz\)-plane (axes \(y\) and \(z\)). Every cross-section parallel to the \(yz\)-plane is a circle of radius 3.
3Step 3: Determine the Direction of the Cylinder
Since the equation does not involve the variable \(x\), the surface described is a cylinder that extends infinitely along the \(x\)-axis. Therefore, for every value of \(x\), the cross-section is the same circle.
4Step 4: Sketch the Surface
In the sketch, draw the cross-section circle with radius 3 in the \(yz\)-plane centered at the origin \((y, z) = (0, 0)\). Then replicate these circles along the \(x\)-axis in both directions, showing that the cylinder is extended along the \(x\)-axis. The result is an infinitely long cylinder with circular cross-sections.
Key Concepts
Circular CylinderCross-sectionsEquation Type
Circular Cylinder
A circular cylinder is a three-dimensional surface formed by moving a circle in a straight line through space. In the context of the equation \( y^2 + z^2 = 9 \), this movement occurs along the \(x\)-axis, since the equation lacks an \(x\) term. The essence of a circular cylinder can be described as:
- The circle remains constant in shape and size; this one has a radius of 3.
- The circles stack infinitely along the given direction (here, the \(x\)-axis).
Cross-sections
Cross-sections are slices or views of a three-dimensional object taken parallel to a plane. For the equation \( y^2 + z^2 = 9 \), each cross-section in the \(yz\)-plane is crucial to understanding the surface. What you'll see is a circle:
- Each circle has a radius of 3.
- The center of these circles is at the origin, \((0,0)\), on the \(yz\)-plane.
Equation Type
The equation \( y^2 + z^2 = 9 \) belongs to a specific group of equations that describe quadric surfaces. Quadric surfaces are second-degree equations in three variables (\(x\), \(y\), and \(z\)). Despite their variety, the absence of one variable simplifies interpretation:
- The absence of the \(x\) term indicates that the surface extends along the \(x\)-axis.
- The remaining equation, \( y^2 + z^2 = 9 \), depicts a set of circles.
Other exercises in this chapter
Problem 41
Find an equation of the plane tangent to the given surface at the given point. $$ x y z=1 ;\left(\frac{1}{2},-2,-1\right) $$
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Find an equation of the plane tangent to the given surface at the given point. $$ y e^{x y}+z^{2}=0 ;(0,-1,1) $$
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