Problem 41
Question
Show that in \(C^{*}\) the subgroup \(\langle i\rangle\) generated by \(i\) is isomorphic to \(\mathbb{Z}_{4}\)
Step-by-Step Solution
Verified Answer
The subgroup \(\langle i \rangle\) is isomorphic to \(\mathbb{Z}_4\) due to their cyclic structure and element mapping.
1Step 1: Understanding the Subgroup
The complex number system \(C^*\) consists of all non-zero complex numbers. The subgroup generated by \(i\) in \(C^*\) includes all powers of \(i\), i.e., \(\{i^n \mid n \in \mathbb{Z}\}\). The important observation here is the cyclic nature of powers of \(i\).
2Step 2: Evaluating Powers of i
Calculate the powers of \(i\): - \(i^1 = i\) - \(i^2 = -1\) - \(i^3 = -i\) - \(i^4 = 1\) - Since \(i^4 = 1\), further powers will repeat this cycle, i.e., \(i^5 = i\), \(i^6 = -1\), and so on.
3Step 3: Setting Up the Isomorphism
The subgroup \(\langle i \rangle = \{1, i, -1, -i\}\) functions like a cyclic group of order 4. Comparatively, \(\mathbb{Z}_4 = \{0, 1, 2, 3\}\) is also a cyclic group with order 4. Map the elements as \(i^0 \mapsto 0, i^1 \mapsto 1, i^2 \mapsto 2, i^3 \mapsto 3\). This correspondence maintains the group operation through addition modulo 4 and multiplication by powers of \(i\).
4Step 4: Proving Isomorphism
To prove isomorphism, the mapping must be bijective and operation-preserving:1. **Bijective**: The map \(\phi: \{1, i, -1, -i\} \rightarrow \{0, 1, 2, 3\}\) is one-to-one and onto.2. **Operation-preserving**: \(\phi(i^a \cdot i^b) = \phi(i^a) + \phi(i^b) \mod 4\). The multiplication in \(\langle i \rangle\) corresponds to addition in \(\mathbb{Z}_4\). Verifying for each pair confirms the operation is preserved.
Key Concepts
Cyclic GroupsPowers of Complex NumbersModular ArithmeticComplex Number System
Cyclic Groups
A cyclic group is a group that can be generated by a single element. This means all elements in the group can be expressed as powers of a particular element, known as the generator. For example, in the group \(Clangle i \rangle\), the generator is \(i\). The powers of \(i\) form a cyclic sequence: \(i^1 = i, i^2 = -1, i^3 = -i,\) and \(i^4 = 1\). After \(i^4\), the powers repeat their sequence.
- Cyclic groups can be finite or infinite.
- They are crucial in understanding the structure and behavior of different types of groups.
- The subgroup \(\langle i \rangle\) is a cyclic group, as it can be fully generated by repeated operations on one element, \(i\).
Powers of Complex Numbers
Complex numbers are numbers that include a real component and an imaginary component, represented as \(a + bi\), where \(a\) and \(b\) are real numbers and \(i\) is the imaginary unit.
- The imaginary unit \(i\) satisfies the equation \(i^2 = -1\).
- Powers of \(i\) cycle every four powers: \(i, -1, -i, \)and \(1\).
Modular Arithmetic
Modular arithmetic is a system of arithmetic for integers, where numbers "wrap around" after reaching a certain value. This process helps to simplify calculations in cyclic groups, like \(\mathbb{Z}_4\), by restricting values to a set that repeats in a predictable manner.
- The arithmetic operates under the concept of modulus, denoted as \(%\).
- For example, in \(\mathbb{Z}_4\), any integer is equivalent to one of \(\{0, 1, 2, 3\}\) under modulo 4.
Complex Number System
The complex number system extends the real numbers by including elements that cannot be expressed solely as a real number. Complex numbers are represented in the form of \(a + bi\), where both \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit.
- They have applications in various fields like electrical engineering, quantum physics, and applied mathematics.
- The subset of non-zero complex numbers forms a group known as the multiplicative group of non-zero complex numbers, \(C^*\).
Other exercises in this chapter
Problem 39
Show that the converse of Lagrange's theorem is false. (Hint: Show that \(A_{4}\) has no subgroup of order \(6 .)\)
View solution Problem 40
Show that \(U(8)\) and \(U(12)\) are isomorphic.
View solution Problem 43
Show that \(\mathbb{Z}_{4}\) and the Klein 4 -group \(V\) of Example 1.1 .22 are not isomorphic.
View solution Problem 45
Find four different subgroups of \(S_{4}\) that are isomorphic to \(S_{3}\).
View solution