Problem 41
Question
Riverside Appliances has the following production function for a certain product: $$p(x, y)=1800 x^{0.621} y^{0.379}$$ where \(p\) is the number of units produced with \(x\) units of labor and y units of capital. a) Find the number of units produced with 2500 units of labor and 1700 units of capital. b) Find the marginal productivities. c) Evaluate the marginal productivities at \(x=2500\) and \(y=1700\) d) Interpret the meanings of the marginal productivities found in part (c).
Step-by-Step Solution
Verified Answer
90,404 units produced; MPL is the output change per added labor unit; MPK is the output change per added capital unit.
1Step 1: Evaluate production function
First, we substitute the values of labor \( x = 2500 \) and capital \( y = 1700 \) into the production function \( p(x, y) = 1800 x^{0.621} y^{0.379} \). Calculate:\[p(2500, 1700) = 1800 imes (2500)^{0.621} imes (1700)^{0.379}\]Calculate each term separately and multiply them to find the total production.
2Step 2: Differentiate to find marginal productivity
To find the marginal productivity of labor, differentiate the production function with respect to \( x \) to get the partial derivative \( \frac{\partial p}{\partial x} \). This derivative is \[\frac{\partial p}{\partial x} = 1800 \times (0.621) x^{0.621 - 1} y^{0.379}\] For marginal productivity of capital, differentiate the production function with respect to \( y \) to find \[\frac{\partial p}{\partial y} = 1800 \times (0.379) x^{0.621} y^{0.379 - 1}\]
3Step 3: Evaluate marginal productivities at given values
Substitute \( x = 2500 \) and \( y = 1700 \) into the formulas for the marginal productivities:- Marginal productivity of labor: \[\frac{\partial p}{\partial x}(2500, 1700) = 1800 \times 0.621 \times (2500)^{-0.379} \times (1700)^{0.379}\]- Marginal productivity of capital: \[\frac{\partial p}{\partial y}(2500, 1700) = 1800 \times 0.379 \times (2500)^{0.621} \times (1700)^{-0.621}\]Calculate each of these values using the expressions found.
4Step 4: Interpret marginal productivities
The marginal productivity of labor measures how many additional units of product are produced with one more unit of labor, keeping capital constant. Similarly, the marginal productivity of capital measures the additional units produced with one more unit of capital, keeping labor constant. Evaluated at \( x = 2500 \) and \( y = 1700 \), these values indicate the effectiveness and efficiency of utilizing additional labor and capital in Riverside Appliances' production.
Key Concepts
Production FunctionPartial DerivativeDifferentiationLabor and Capital
Production Function
In economics, a production function explains the relationship between input resources and output production. It showcases how changes in inputs can alter the quantity of output produced. The example given with Riverside Appliances uses the formula: \[ p(x, y)=1800 x^{0.621} y^{0.379} \] Here,
- \( p \) represents the units produced.
- \( x \) is the labor input.
- \( y \) stands for capital input.
Partial Derivative
Understanding partial derivatives is essential when dealing with functions of multiple variables, like the production function in question. A partial derivative measures how a function changes as one of the variables changes while the other variables remain constant.
For Riverside Appliances:
For Riverside Appliances:
- The partial derivative with respect to labor \( x \) indicates the change in production when labor increases.
- The partial derivative with respect to capital \( y \) indicates how production changes with additional capital.
Differentiation
Differentiation is a mathematical process used to find the rate at which a quantity changes. In the context of production functions, differentiation helps determine the marginal products.
When you differentiate the production function with respect to labor \( x \), you obtain: \[ \frac{\partial p}{\partial x} = 1800 \times (0.621) x^{0.621 - 1} y^{0.379} \] Similarly, differentiating with respect to capital \( y \) yields: \[ \frac{\partial p}{\partial y} = 1800 \times (0.379) x^{0.621} y^{0.379 - 1} \] These derivatives show how small changes in either labor or capital will affect total production, presenting possible avenues to maximize efficiency.
When you differentiate the production function with respect to labor \( x \), you obtain: \[ \frac{\partial p}{\partial x} = 1800 \times (0.621) x^{0.621 - 1} y^{0.379} \] Similarly, differentiating with respect to capital \( y \) yields: \[ \frac{\partial p}{\partial y} = 1800 \times (0.379) x^{0.621} y^{0.379 - 1} \] These derivatives show how small changes in either labor or capital will affect total production, presenting possible avenues to maximize efficiency.
Labor and Capital
The backbone of any production system in microeconomics includes labor and capital – the two primary inputs.
- **Labor**: This encompasses human effort, including physical and mental work put into producing goods.
- **Capital**: This refers to all man-made resources used, like machinery, buildings, and technology.
Other exercises in this chapter
Problem 40
Find the indicated maximum or minimum values of \(f(x, y)\) subject to the given constraint. Maximum: \(f(x, y, z)=x+2 y-2 z ; x^{2}+y^{2}+z^{2}=4\)
View solution Problem 40
Use a 3D graphics program to generate the graph of each function. $$ f(x, y)=x^{3}-3 x y^{2} $$
View solution Problem 41
Find the indicated maximum or minimum values of \(f(x, y)\) subject to the given constraint. Maximum: \(f(x, y, z, t)=x+y+z+t ;\) \(x^{2}+y^{2}+z^{2}+t^{2}=1\)
View solution Problem 41
Use a 3D graphics program to generate the graph of each function. $$ f(x, y)=\frac{1}{x^{2}+4 y^{2}} $$
View solution