Problem 41
Question
Prove the Quotient Rule and Power Rule for Logarithms.
Step-by-Step Solution
Verified Answer
Logarithm of a quotient is the difference, and logarithm of a power is the exponent multiplied.
1Step 1: Recall the Properties of Exponents
To begin, let's recall the basic property of exponents which states that division of powers can be rewritten using subtraction: \( a^m / a^n = a^{m-n} \). This is fundamental in understanding the Quotient Rule for logarithms, as logarithms are essentially the inverse of exponentiation.
2Step 2: Define the Quotient Rule for Logarithms
The Quotient Rule states that the logarithm of a quotient is the difference of the logarithms: \( \log_b\left(\frac{x}{y}\right) = \log_b(x) - \log_b(y) \). This means if you have two numbers, \(x\) and \(y\), and you want to find the logarithm of their division, you can subtract the logarithm of \(y\) from the logarithm of \(x\).
3Step 3: Prove the Quotient Rule Using Exponents
Assume \( \log_b(x) = m \) and \( \log_b(y) = n \). This implies \( b^m = x \) and \( b^n = y \). The quotient \( \frac{x}{y} \) is \( \frac{b^m}{b^n} = b^{m-n} \). Logarithm on base \(b\) gives us \( \log_b\left(b^{m-n}\right) = m-n \). Thus, \( \log_b\left(\frac{x}{y}\right) = \log_b(x) - \log_b(y) \).
4Step 4: Define the Power Rule for Logarithms
The Power Rule states that the logarithm of a power is the exponent times the logarithm: \( \log_b(x^c) = c \cdot \log_b(x) \). This means if you have a number \(x\) raised to a power \(c\), you can multiply \(c\) by the logarithm of \(x\).
5Step 5: Prove the Power Rule Using Exponents
Assume \( \log_b(x) = m \), which means \( b^m = x \). Then, \( x^c = (b^m)^c = b^{mc} \). Taking the logarithm on both sides, \( \log_b(x^c) = \log_b(b^{mc}) = mc \) which simplifies to \( c \cdot \log_b(x) \). Therefore, \( \log_b(x^c) = c \cdot \log_b(x) \).
Key Concepts
Quotient Rule for LogarithmsPower Rule for LogarithmsProperties of Exponents
Quotient Rule for Logarithms
The Quotient Rule for logarithms is a handy tool in mathematics that simplifies the process of finding the logarithm of a division. The rule states that the logarithm of a quotient is equivalent to the difference between the logarithms of the numerator and the denominator. In mathematical terms, this is expressed as:
For example, if you have \( \log_2(8) = 3 \) and \( \log_2(4) = 2 \), by applying the quotient rule, you find:
- \( \log_b\left(\frac{x}{y}\right) = \log_b(x) - \log_b(y) \)
For example, if you have \( \log_2(8) = 3 \) and \( \log_2(4) = 2 \), by applying the quotient rule, you find:
- \( \log_2\left(\frac{8}{4}\right) = \log_2(8) - \log_2(4) = 3 - 2 = 1 \)
Power Rule for Logarithms
The Power Rule for logarithms is an important principle allowing you to simplify logarithmic expressions involving exponents. According to this rule, if you have a number raised to a power, the logarithm of this power equals the exponent times the logarithm of the base number. The formula can be expressed as:
Consider the case where \( \log_2(3) = 1.585 \). If you want to find \( \log_2(3^2) \), applying the power rule gives:
- \( \log_b(x^c) = c \cdot \log_b(x) \)
Consider the case where \( \log_2(3) = 1.585 \). If you want to find \( \log_2(3^2) \), applying the power rule gives:
- \( \log_2(3^2) = 2 \cdot \log_2(3) = 2 \cdot 1.585 = 3.17 \)
Properties of Exponents
Understanding the properties of exponents is essential when working with logarithms, as they form the basis for both the quotient and power rules. One key exponent property is the division of like bases, which states:
To apply this in the context of logarithms, let's assume you know \( a^m = x \) and \( a^n = y \). If you wanted to express the division of these as a logarithm, the property becomes:
- \( a^m / a^n = a^{m-n} \)
To apply this in the context of logarithms, let's assume you know \( a^m = x \) and \( a^n = y \). If you wanted to express the division of these as a logarithm, the property becomes:
- \( x/y = a^{m-n} \)
- Taking the logarithm, you have \( \log_b\left(\frac{x}{y}\right) = m-n \)
Other exercises in this chapter
Problem 40
Evaluate the expression. \(\log \left(e^{\ln (100)}\right)\)
View solution Problem 41
In Exercises \(40-45,\) use your ealculator to help you solve the equation or inequality. $$ e^{x}=\ln (x)+5 $$
View solution Problem 41
Evaluate the expression. \(\log _{2}\left(3^{-\log _{3}(2)}\right)\)
View solution Problem 42
In Exercises \(40-45,\) use your ealculator to help you solve the equation or inequality. $$ e^{\sqrt{x}}=x+1 $$
View solution