Problem 41
Question
Prove the Cauchy-Schwarz Inequality for Integrals: \(\left[\int_{a}^{b} f(x) g(x) d x\right]^{2} \leq \int_{a}^{b} f^{2}(x) d x \int_{a}^{b} g^{2}(x) d x\) Hint: Consider the double integral of $$ F(x, y)=[f(x) g(y)-f(y) g(x)]^{2} $$ over the rectangle \(R=\\{(x, y): a \leq x \leq b, a \leq y \leq b\\}\).
Step-by-Step Solution
Verified Answer
The inequality is proven using the non-negative property of squared expressions and double integrals.
1Step 1: Rewrite the Expression
Start by considering the function \( F(x, y) = [f(x) g(y) - f(y) g(x)]^2 \). The goal is to explore the integral of \( F(x,y) \) over the rectangle \( R = \{(x, y): a \leq x \leq b, a \leq y \leq b\} \). Thus, we have the double integral \( \int_{a}^{b} \int_{a}^{b} [f(x) g(y) - f(y) g(x)]^2 \, dy \, dx \).
2Step 2: Expand the Square
Expand \( [f(x) g(y) - f(y) g(x)]^2 \) to get \( f^2(x)g^2(y) - 2f(x)g(x)f(y)g(y) + f^2(y)g^2(x) \). This will simplify our calculations when we integrate over \( R \).
3Step 3: Integrate Term by Term
For the first term, integrate \( \int_{a}^{b} \int_{a}^{b} f^2(x) g^2(y) \, dy \, dx = \left( \int_{a}^{b} f^2(x) \, dx \right) \left( \int_{a}^{b} g^2(y) \, dy \right) \). Use Fubini's Theorem for this independent integration.
4Step 4: Integrate the Cross Term
For the cross term, which is \(-2 \int_{a}^{b} \int_{a}^{b} f(x) g(x) f(y) g(y) \, dy \, dx \), the function factors into separate integrals: \(- 2 \int_{a}^{b} f(x) g(x) \, dx \cdot \int_{a}^{b} f(y) g(y) \, dy \).
5Step 5: Integrate the Second Square Term
For the second square term, integrate \( \int_{a}^{b} \int_{a}^{b} f^2(y) g^2(x) \, dy \, dx \). Use similar logic from step 3, giving \( \left( \int_{a}^{b} f^2(y) \, dy \right) \left( \int_{a}^{b} g^2(x) \, dx \right) \).
6Step 6: Combine All Terms
Sum the results from Steps 3, 4, and 5. You will have: \[ \int_{a}^{b} \int_{a}^{b} [f(x) g(y) - f(y) g(x)]^2 \, dy \, dx = \int_{a}^{b} f^2(x) \, dx \int_{a}^{b} g^2(y) \, dy + \int_{a}^{b} f^2(y) \, dy \int_{a}^{b} g^2(x) \, dx - 2 \left( \int_{a}^{b} f(x) g(x) \, dx \right)^2 \]
7Step 7: Conclude the Inequality
Since \( \int_{a}^{b} \int_{a}^{b} [f(x) g(y) - f(y) g(x)]^2 \, dy \, dx \geq 0 \) (as it is the integral of a square), it follows that: \[ \left( \int_{a}^{b} f(x) g(x) \, dx \right)^2 \leq \int_{a}^{b} f^2(x) \, dx \int_{a}^{b} g^2(y) \, dy \]. This completes the proof of the Cauchy-Schwarz inequality for integrals.
Key Concepts
IntegralsDouble IntegralsFubini's TheoremMathematical Proofs
Integrals
An integral is a mathematical concept used to calculate the accumulation of quantities. Imagine it as adding up a series of tiny pieces to find the total. For example, you might use an integral to calculate the area under a curve or the total distance traveled by an object moving at a variable speed.
Think of it as a method to combine or accumulate several small parts into a whole. When you need to integrate a function, you are essentially summing up these tiny slices over a certain interval.
Think of it as a method to combine or accumulate several small parts into a whole. When you need to integrate a function, you are essentially summing up these tiny slices over a certain interval.
- Definite integrals, such as \( \int_{a}^{b} f(x) \, dx \), provide a number that represents the area under the function from point \( a \) to point \( b \).
- Indefinite integrals, on the other hand, give you a new function whose derivative matches the original function.
Double Integrals
Building on the concept of single integrals, double integrals allow us to integrate functions over a two-dimensional area. It is like adding up the volume under a surface in three-dimensional space.
For a function \( z = f(x, y) \) over a region \( R \), the double integral \[ \int \int_{R} f(x, y) \, dA \] represents the volume under the surface defined by the function, across the specified region.
For a function \( z = f(x, y) \) over a region \( R \), the double integral \[ \int \int_{R} f(x, y) \, dA \] represents the volume under the surface defined by the function, across the specified region.
- In terms of calculations, you first integrate with respect to one variable while treating the other as constant, and then proceed to the second integration.
- Double integrals are widely used in physics and engineering to calculate quantities like mass, area, and volume of physically varied shapes.
Fubini's Theorem
Fubini's Theorem is an invaluable tool when dealing with double integrals. It states that under certain conditions, the order of integration can be changed without affecting the result of the integral. This is especially useful when one order of integration is much easier to compute than the other.
To apply Fubini's Theorem, the function must be continuous on the closed region you are integrating over. It allows us to express a double integral as two consecutive single integrals:\[ \int \int_{R} f(x, y) \, dA = \int_{a}^{b} \left( \int_{c}^{d} f(x, y) \, dy \right) \, dx = \int_{c}^{d} \left( \int_{a}^{b} f(x, y) \, dx \right) \, dy \]
To apply Fubini's Theorem, the function must be continuous on the closed region you are integrating over. It allows us to express a double integral as two consecutive single integrals:\[ \int \int_{R} f(x, y) \, dA = \int_{a}^{b} \left( \int_{c}^{d} f(x, y) \, dy \right) \, dx = \int_{c}^{d} \left( \int_{a}^{b} f(x, y) \, dx \right) \, dy \]
- This change can simplify the calculation and potentially make the problem more tractable.
- It is typically used when evaluating integrals over rectangular regions or other simple shapes.
Mathematical Proofs
A mathematical proof is a logical argument that demonstrates the truth of a mathematical statement. Proving a theorem ensures that it holds under all possible circumstances covered by its assumptions. Mathematical proofs can involve different methods depending on the nature of the proposition.
- The idea is not only to verify if something is true, but also to understand why it is true.
- Direct proofs involve straightforward argumentation by logical steps. Indirect proofs, such as proof by contradiction, assume the opposite of what you want to prove and show that it leads to a contradiction.
- Constructive proofs provide explicit examples demonstrating the truth, while non-constructive proofs show existence without necessarily providing a witness.
Other exercises in this chapter
Problem 38
In Problems 33-38, write the given iterated integral as an iterated integral with the order of integration interchanged. Hint: Begin by sketching a region \(S\)
View solution Problem 39
Evaluate each iterated integral. \(\int_{-2}^{2} \int_{-1}^{1}\left[x^{2}\right]\left|y^{3}\right| d y d x\)
View solution Problem 42
Evaluate \(\iint_{S} \sin \left(x y^{2}\right) d A\), where \(S\) is the annulus \(\left\\{(x, y): 1 \leq x^{2}+y^{2} \leq 4\right\\}\). Hint: Done without thin
View solution Problem 43
Evaluate \(\iint_{S} \sin \left(y^{3}\right) d A\), where \(S\) is the region bounded by \(y=\sqrt{x}, y=2\), and \(x=0\). Hint: If one order of integration doe
View solution