Problem 41
Question
Let \(C\) be any circle with centre \((0, \sqrt{2})\). Then, on the circle \(C\), there can be (A) at the most one rational point (B) at the most two rational points (C) at the most three rational points (D) none of these
Step-by-Step Solution
Verified Answer
(D) None of these. No rational points on the circle with center \((0, \sqrt{2})\).
1Step 1: Define what a Rational Point is
A rational point is a point on the Cartesian plane whose coordinates \((x, y)\) are both rational numbers. This means both \(x\) and \(y\) can be expressed as fractions of integers where the denominator is not zero.
2Step 2: Identify the Circle Equation
The general equation of a circle with a center at \((0, \, \sqrt{2})\) is \((x - 0)^2 + (y - \sqrt{2})^2 = r^2\). This simplifies to \(x^2 + (y - \sqrt{2})^2 = r^2\).
3Step 3: Investigate Rational Points on the Circle
For the circle to have rational points, \(y - \sqrt{2}\) must be rational, since \(x^2\) is already rational if \(x\) is rational. Let \(y = a + b\sqrt{2}\) where \(a\) and \(b\) are rational. For \(y\) itself to be rational, \(b\) must be zero (otherwise \(\sqrt{2}\), an irrational number, will be multiplied with a non-zero rational \(b\) yielding an irrational number). Therefore, \(y - \sqrt{2} = a\) must be zero, which implies no rational solutions unless \(b = 0\), making \(\sqrt{2}\) rational, which it is not. Thus, constructing a rational solution here is impossible.
4Step 4: Evaluate the Possibility of Rational Points
Even if we attempt to solve for rational points rigorously, under our assumption, the circle equation with any rational solution results in a contradiction due to the irrational path involving \(\sqrt{2}\). There cannot be rational coordinates that make the distance from the origin a rational number without balancing terms involving \(\sqrt{2}\) hence confirming the non-existence of such points.
Key Concepts
Circle EquationRational NumbersCoordinate Geometry
Circle Equation
A circle equation in coordinate geometry represents all the points that form a circle around a specific center point. The general equation for a circle with center \( (h, k) \) and radius \( r \) is: \[(x - h)^2 + (y - k)^2 = r^2\] This formula makes it easy to identify whether a point \( (x, y) \) lies on the circle. If it satisfies the equation, the point is on the circle.
For the specific circle we discussed, with center at \( (0, \sqrt{2}) \), its equation becomes: \[x^2 + (y - \sqrt{2})^2 = r^2\]To find points on the circle, one needs to solve this equation for values of \( x \) and \( y \) that satisfy it. The parameters of this equation can be adjusted for different circles by changing \( h, k, \) or \( r \) to fit different scenarios or problem statements.
For the specific circle we discussed, with center at \( (0, \sqrt{2}) \), its equation becomes: \[x^2 + (y - \sqrt{2})^2 = r^2\]To find points on the circle, one needs to solve this equation for values of \( x \) and \( y \) that satisfy it. The parameters of this equation can be adjusted for different circles by changing \( h, k, \) or \( r \) to fit different scenarios or problem statements.
Rational Numbers
Rational numbers are numbers that can be expressed as the quotient of two integers, where the denominator is not zero. In simpler terms, they are numbers that can be written as a fraction like \( \frac{a}{b} \).
Here are some examples of rational numbers:
Finding rational points on a circle involves looking for coordinates \( (x, y) \), both of which need to be rational. For example, if the center of the circle or the radius itself involves an irrational number, such as \( \sqrt{2} \), like in our original problem, creating rational points becomes challenging.
Here are some examples of rational numbers:
- \( \frac{1}{2} \)
- \( \frac{-3}{4} \)
- \( 7 \) (as this can be written as \( \frac{7}{1} \))
Finding rational points on a circle involves looking for coordinates \( (x, y) \), both of which need to be rational. For example, if the center of the circle or the radius itself involves an irrational number, such as \( \sqrt{2} \), like in our original problem, creating rational points becomes challenging.
Coordinate Geometry
Coordinate geometry, or analytic geometry, is the study of geometry using a coordinate system. This allows for the description of geometric shapes in algebraic equations.
Coordinates are typically given in the form of \( (x, y) \) in a 2-dimensional plane, and using this system, we can study figures like lines, circles, and more complex shapes.
Understanding points on this plane is crucial as it allows solving problems related to finding distances, midpoints, and verifying particular criteria like points laying on a circle.
This makes coordinate geometry not just about pictures, but about figuring out where those pictures are and how they interact using math. It’s a bridge between algebra and geometry that opens up new ways to solve spatial problems.
Coordinates are typically given in the form of \( (x, y) \) in a 2-dimensional plane, and using this system, we can study figures like lines, circles, and more complex shapes.
Understanding points on this plane is crucial as it allows solving problems related to finding distances, midpoints, and verifying particular criteria like points laying on a circle.
- The x-coordinate determines the horizontal positioning.
- The y-coordinate determines the vertical positioning.
This makes coordinate geometry not just about pictures, but about figuring out where those pictures are and how they interact using math. It’s a bridge between algebra and geometry that opens up new ways to solve spatial problems.
Other exercises in this chapter
Problem 39
To which of the following circles, the line \(y-x+3=\) 0 is normal at the point \(\left(3+\frac{3}{\sqrt{2}}, \frac{3}{\sqrt{2}}\right) ?\) (A) \(\left(x-3-\fra
View solution Problem 40
If a circle passes through the points where the lines \(3 k x-2 y-1=0\) and \(4 x-3 y+2=0\) meet the coordinate axes then \(k=\) (A) 1 (B) \(-1\) (C) \(\frac{1}
View solution Problem 42
If the tangents \(P Q\) and \(P R\) are drawn to the circle \(x^{2}+\) \(y^{2}=a^{2}\) from the point \(P\left(x_{1}, y_{1}\right)\), then the equation of the c
View solution Problem 43
A ray of light, incident at the point \((-2,-1)\), gets reflected from the tangent at \((0,-1)\) to the circle \(x^{2}+y^{2}\) \(=1\). The reflected ray touches
View solution