Problem 41
Question
Let \(A\) be an \(n \times n\) invertible matrix. Prove that if \(\lambda\) is an eigenvalue of \(A\), then \(1 / \lambda\) is an eigenvalue of \(A^{-1}\). [Note: By Proposition \(7.1 .4, \lambda \neq 0 \text { here. }]\)
Step-by-Step Solution
Verified Answer
Given an \(n \times n\) invertible matrix \(A\) and an eigenvalue \(\lambda\) with corresponding eigenvector \(\mathbf{x}\), we have \(A\mathbf{x} = \lambda\mathbf{x}\). By multiplying both sides by \(A^{-1}\), we get \(\mathbf{x} = A^{-1}\lambda\mathbf{x}\). Bringing out \(\lambda\), we have \(\frac{1}{\lambda}\mathbf{x} = A^{-1}\mathbf{x}\), showing that \(\frac{1}{\lambda}\) is an eigenvalue of \(A^{-1}\).
1Step 1: Define eigenvalue and eigenvector
A scalar \(\lambda\) is an eigenvalue of a matrix \(A\) if there exists a non-zero vector \(\mathbf{x}\) such that \(A\mathbf{x} = \lambda\mathbf{x}\). The vector \(\mathbf{x}\) is called the eigenvector corresponding to the eigenvalue \(\lambda\).
2Step 2: Rewrite the equation
From the given equation \(A\mathbf{x} = \lambda\mathbf{x}\), we want to find a relationship between \(\lambda\) and \(1/\lambda\). Let's begin by multiplying both sides of the equation \(A\mathbf{x} = \lambda\mathbf{x}\) by \(A^{-1}\):
\(A^{-1}A\mathbf{x} = A^{-1}\lambda\mathbf{x}\)
3Step 3: Simplify the equation
Now simplify the left-hand side of the previous equation using the property \(A^{-1}A=I\), where \(I\) is the identity matrix:
\(I\mathbf{x} = A^{-1}\lambda\mathbf{x}\)
And since the identity matrix times any vector is the vector itself, we have:
\(\mathbf{x} = A^{-1}\lambda\mathbf{x}\)
4Step 4: Bring out \(\lambda\) from \(A^{-1}\)
Now, we bring out the \(\lambda\) from the matrix \(A^{-1}\):
\(\mathbf{x} = \lambda A^{-1}\mathbf{x}\)
Since \(\lambda \neq 0\), we can divide by it:
\(\frac{1}{\lambda}\mathbf{x} = A^{-1}\mathbf{x}\)
5Step 5: Conclude that \(\frac{1}{\lambda}\) is an eigenvalue of \(A^{-1}\)
Thus, we have shown that if \(A\mathbf{x} = \lambda\mathbf{x}\), then \(A^{-1}\mathbf{x} = \frac{1}{\lambda}\mathbf{x}\). So, the eigenvalue of \(A\) is \(\lambda\) and the corresponding eigenvalue of \(A^{-1}\) is \(\frac{1}{\lambda}\). Since the existence of these eigenvalues is guaranteed by the given proposition, we have proved that if \(\lambda\) is an eigenvalue of \(A\), then \(\frac{1}{\lambda}\) is an eigenvalue of \(A^{-1}\).
Key Concepts
Inverse MatricesEigenvectorsMatrix Theory
Inverse Matrices
When exploring the fascinating world of matrix theory, understanding inverse matrices is fundamental. An inverse matrix, symbolized as \(A^{-1}\) for a matrix \(A\), is a matrix that, when multiplied by \(A\), results in the identity matrix \(I\). This is expressed as \(AA^{-1} = A^{-1}A = I\).
This concept is vital because it allows us to "undo" the effects of matrix \(A\), much like dividing by a number undoes multiplication by that number in elementary arithmetic.
Not all matrices have inverses, though. For an \(n \times n\) matrix to have an inverse, it must satisfy two main conditions:
This concept is vital because it allows us to "undo" the effects of matrix \(A\), much like dividing by a number undoes multiplication by that number in elementary arithmetic.
Not all matrices have inverses, though. For an \(n \times n\) matrix to have an inverse, it must satisfy two main conditions:
- The matrix must be square, meaning it has the same number of rows and columns.
- The determinant of the matrix, denoted as \(\det(A)\), must be non-zero. This ensures that the matrix is non-singular and hence invertible.
Eigenvectors
Eigenvectors are an essential part of matrix theory and are deeply connected to eigenvalues. An eigenvector of a matrix \(A\) is a non-zero vector \(\mathbf{x}\) that, when the matrix operates on it, transforms into a scalar multiple of itself. Mathematically, this is expressed as \(A\mathbf{x} = \lambda\mathbf{x}\), where \(\lambda\) is the eigenvalue associated with the eigenvector \(\mathbf{x}\).
The concept of eigenvectors can be fascinating because they represent directions or axes along which a matrix acts by merely stretching or compressing rather than rotating.
The concept of eigenvectors can be fascinating because they represent directions or axes along which a matrix acts by merely stretching or compressing rather than rotating.
- These vectors provide a basis for diagonalizing matrices when possible, simplifying many algebraic processes.
- They have practical applications in numerous fields such as physics, computer science, and statistics, in areas like principal component analysis (PCA) and systems of differential equations.
Matrix Theory
Matrix theory forms the backbone of linear algebra and is an area of mathematics that focuses on the study of matrices and their properties. Matrices are rectangular arrays of numbers, which can represent linear transformations and systems of linear equations.
The importance of matrix theory stems from its wide range of applications:
Additionally, matrix operations such as addition, multiplication, and finding the inverse allow for the manipulation and transformation of matrices—aiding in solving complex mathematical problems.
By understanding matrix theory, students can leverage its principles across various fields, enhancing their problem-solving skills and analytical capabilities.
The importance of matrix theory stems from its wide range of applications:
- In engineering and physics, matrices help model and solve real-world systems and phenomena.
- In computer graphics, they are used to perform rotations, translations, and scaling of images.
- Economists utilize matrices to represent and analyze economic models and financial systems.
Additionally, matrix operations such as addition, multiplication, and finding the inverse allow for the manipulation and transformation of matrices—aiding in solving complex mathematical problems.
By understanding matrix theory, students can leverage its principles across various fields, enhancing their problem-solving skills and analytical capabilities.
Other exercises in this chapter
Problem 41
Determine the general solution to the system \(\mathbf{x}^{\prime}=A \mathbf{x}\) for the given matrix \(A\). \(A=\left[\begin{array}{rrr}3 & 0 & 4 \\ 0 & 2 & 0
View solution Problem 41
Use some form of technology to determine the eigenvalues and a basis for each eigenspace of the given matrix. Hence, determine the dimension of each eigenspace
View solution Problem 42
Solve the initial-value problem \(\mathbf{x}^{\prime}=A \mathbf{x},\) where \(A=\left[\begin{array}{rr}-2 & -1 \\ 1 & -4\end{array}\right], \quad \mathbf{x}(0)=
View solution Problem 42
Use some form of technology to determine the eigenvalues and a basis for each eigenspace of the given matrix. Hence, determine the dimension of each eigenspace
View solution