Problem 41
Question
In the titration of a solution of a weak monoprotic acid with a standard solution of \(\mathrm{NaOH}\), the \(\mathrm{pH}\) halfway to the equivalence point was \(4.44 .\) In the titration of a second solution of the same acid, exactly twice as much of the standard solution of \(\mathrm{NaOH}\) was needed to reach the equivalence point. What was the \(\mathrm{pH}\) halfway to the equivalence point in this titration?
Step-by-Step Solution
Verified Answer
Answer: The pH value halfway to the equivalence point in the second titration is 4.44.
1Step 1: Recall the relationship between pH, pKa, and concentrations at the half-equivalence point
At the half-equivalence point of a titration between a weak acid and a strong base, the concentration of the acid is equal to the concentration of its conjugate base. According to the Henderson-Hasselbalch equation, we have:
\(pH = pKa + \log \frac{[\mathrm{A}^-]}{[\mathrm{HA}]}\)
Since \([\mathrm{A}^-]=[\mathrm{HA}]\), the equation becomes:
\(pH = pKa\)
2Step 2: Determine the pKa value of the first titration
We are given the pH value halfway to the equivalence point in the first titration, which is equal to the pKa value of the weak acid. Thus, we have:
\(pKa = 4.44\)
3Step 3: Apply the pKa value to the second titration
In the second titration, we have twice the amount of NaOH to reach the equivalence point. However, the pKa value of the weak acid remains the same, regardless of the volume of the NaOH solution used. Therefore, the pH value halfway to the equivalence point in the second titration is also equal to the pKa value.
\(pH = pKa = 4.44\)
So, the pH halfway to the equivalence point in the second titration is also \(4.44\).
Key Concepts
Understanding Weak AcidsThe Henderson-Hasselbalch EquationUnderstanding pKa
Understanding Weak Acids
Weak acids partially dissociate in water. This means they do not release all their hydrogen ions (H⁺) into a solution. Unlike strong acids, where dissociation is complete, weak acids form an equilibrium between undissociated acid molecules and ions.
Key characteristics of weak acids include:
Key characteristics of weak acids include:
- They have a higher pH value compared to strong acids of the same concentration.
- The degree of ionization is less than 100%.
- They establish an equilibrium in aqueous solution between the acid (HA) and its ions (H⁺ and A⁻).
The Henderson-Hasselbalch Equation
The Henderson-Hasselbalch equation is a formula used to estimate the pH of a buffer solution. It is particularly useful in the context of titration involving a weak acid and a strong base. The equation is expressed as: \[ pH = pKa + \log \frac{[\text{A}^-]}{[\text{HA}]} \] This equation helps in understanding how the concentration ratio of a base ([A⁻] - the conjugate base) and an acid ([HA]) in a solution influences its pH.
In a titration scenario, using the Henderson-Hasselbalch equation at the half-equivalence point simplifies calculations because:
In a titration scenario, using the Henderson-Hasselbalch equation at the half-equivalence point simplifies calculations because:
- The concentration of the acid equals the concentration of its conjugate base ([A⁻] = [HA]).
- This simplifies the equation to \( pH = pKa \).
Understanding pKa
The term 'pKa' is a measure of the strength of an acid in solution. It is slightly more descriptive than 'Ka', the acid dissociation constant, with the primary difference being representation. pKa is expressed on a logarithmic scale: \[ pKa = -\log(Ka) \] This logarithmic nature means each integer change in pKa represents a tenfold change in acid strength.
Some critical characteristics of pKa are:
Some critical characteristics of pKa are:
- A lower pKa value indicates a stronger acid, which dissociates more to release H⁺ ions.
- A higher pKa signifies a weaker acid, with a lesser tendency to donate protons.
Other exercises in this chapter
Problem 39
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