Problem 41
Question
For the following problems, determine the slope and \(y\) -intercept of the lines. $$ -10 y=-12 x+1 $$
Step-by-Step Solution
Verified Answer
Answer: The slope of the line is 12/10 and the y-intercept is -1/10.
1Step 1: Rearrange the given equation to the slope-intercept form
First, we'll divide both sides of the equation by -10 to isolate y:
$$
-10 y = -12 x + 1 \implies y = \frac{-12}{-10} x + \frac{1}{-10}
$$
2Step 2: Identify the slope and y-intercept
Now that we have the equation in the form \(y= mx+b\), we can identify the slope and y-intercept:
$$
y = \frac{12}{10} x - \frac{1}{10}
$$
So, the slope \(m = \frac{12}{10}\), and the y-intercept \(b = -\frac{1}{10}\).
Thus, the slope of the line is \(\frac{12}{10}\) and the y-intercept is \(-\frac{1}{10}\).
Key Concepts
Understanding the Slope-Intercept FormDecoding the SlopeSignificance of the Y-Intercept
Understanding the Slope-Intercept Form
The slope-intercept form of a linear equation is one of the easiest ways to write a line equation. It is generally expressed as \( y = mx + b \). This form immediately tells you two crucial pieces of information about the line:
In our example, rearranging the equation \(-10y = -12x + 1\) into \(y = \frac{12}{10}x - \frac{1}{10}\) helps us swiftly identify these key features.
- The slope \( m \)
- The y-intercept \( b \)
In our example, rearranging the equation \(-10y = -12x + 1\) into \(y = \frac{12}{10}x - \frac{1}{10}\) helps us swiftly identify these key features.
Decoding the Slope
The slope of a line is essentially a measure of its steepness and direction. It is calculated as the ratio of the vertical change (rise) to the horizontal change (run) between any two points on the line.This is why you often hear that slope equals \( \frac{\text{rise}}{\text{run}} \).
In mathematical terms, the slope \( m \) of a line through two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by:\[m = \frac{y_2 - y_1}{x_2 - x_1}\]In the slope-intercept form \( y = mx + b \), the slope \( m \) directly tells us:
In mathematical terms, the slope \( m \) of a line through two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by:\[m = \frac{y_2 - y_1}{x_2 - x_1}\]In the slope-intercept form \( y = mx + b \), the slope \( m \) directly tells us:
- A positive slope means the line rises as it moves from left to right.
- A negative slope means the line falls as it goes from left to right.
Significance of the Y-Intercept
The y-intercept is the point where a line crosses the y-axis. It specifically occurs at the point where the value of \( x \) is zero.
In the context of the slope-intercept form equation \( y = mx + b \), the \( b \) value represents the y-intercept: the y-coordinate of the point where the line meets the y-axis.
If you picture the line on a graph, the y-intercept is a fundamental starting point for drawing your line. Using it, along with the slope, you can quickly plot a whole line.
In our equation \( y = \frac{12}{10}x - \frac{1}{10} \), the y-intercept is \( -\frac{1}{10} \), which is quite close to zero, indicating the line crosses the y-axis just below the origin.
In the context of the slope-intercept form equation \( y = mx + b \), the \( b \) value represents the y-intercept: the y-coordinate of the point where the line meets the y-axis.
If you picture the line on a graph, the y-intercept is a fundamental starting point for drawing your line. Using it, along with the slope, you can quickly plot a whole line.
In our equation \( y = \frac{12}{10}x - \frac{1}{10} \), the y-intercept is \( -\frac{1}{10} \), which is quite close to zero, indicating the line crosses the y-axis just below the origin.
Other exercises in this chapter
Problem 41
Determine the slope and \(y\) -intercept of the lines. $$ 6 y-12 x=24 $$
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For the following problems, write the equation of the line using the given information in slope-intercept form. $$ (1,6),(-1,-6) $$
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Supply the missing word. The coordinate axes divide the plane into four equal regions called
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Determine the slope and \(y\) -intercept of the lines. $$ 5 y-10 x-15=0 $$
View solution