Problem 41
Question
For the following exercises, sketch a graph of the piecewise function. Write the domain in interval notation. $$ f(x)=\left\\{\begin{array}{ll}{3} & {\text { if } x<0} \\ {\sqrt{x}} & {\text { if } x \geq 0}\end{array}\right. $$
Step-by-Step Solution
Verified Answer
The domain of the function is \( (-\infty, +\infty) \) and the graph is a horizontal line at \( y=3 \) for \( x<0 \) and the square root function for \( x\geq0 \).
1Step 1: Understand the Function
The function is piecewise defined, meaning it behaves differently on separate intervals of the input variable, \( x \). Specifically, \( f(x) = 3 \) when \( x < 0 \) and \( f(x) = \sqrt{x} \) when \( x \geq 0 \). This implies we have two distinct expressions describing the function based on the value of \( x \).
2Step 2: Determine the Domain
The domain of the function consists of all the values \( x \) can take. For the current function, \( f(x) \) is defined for all real numbers because \( f(x) = 3 \) for all \( x < 0 \) and \( f(x) = \sqrt{x} \) for all \( x \geq 0 \). Therefore, the domain in interval notation is \(( -\infty, +\infty)\).
3Step 3: Analyzing the Function on Each Interval
For \( x < 0 \), the function outputs a constant value of 3. Therefore, for negative values of \( x \), the graph will be a horizontal line at \( y = 3 \). For \( x \geq 0 \), the function's output is \( \sqrt{x} \) which is a standard square root function starting from \( x = 0 \). This portion of the graph will start at the origin and increase as \( x \) increases.
4Step 4: Sketch the Graph
On the graph, plot a horizontal line at \( y = 3 \) for \( x < 0 \). The segment of the graph representing \( \sqrt{x} \) will begin at \( (0,0) \) and curve upwards as \( x \) increases, showing the square root function. Use an open circle at \((0,3)\) to indicate \( f(x) = 3 \) is not inclusive at \( x = 0 \), and a filled circle at \((0,0)\) for the square root function to indicate \( x = 0 \) is inclusive.
Key Concepts
Domain in Interval NotationGraph SketchingSquare Root FunctionContinuous Function
Domain in Interval Notation
When working with functions, specifying the domain is crucial, as it tells us the set of input values over which the function is defined. In interval notation, the domain of a function is indicated using brackets and parentheses:
- Round parentheses
(...)indicate that an endpoint is not included in the interval. - Square brackets
[...]indicate that an endpoint is included in the interval.
Graph Sketching
Creating a visual representation of a function can greatly simplify the understanding of its behavior and characteristics. To effectively sketch a graph of a piecewise function, follow these steps:
- Identify the different intervals and the corresponding expressions of the function.
- Determine if there are any endpoints on each interval, and whether these points are included or excluded.
- Sketch each part of the function within its given interval. Clearly mark where the function transitions from one part to another.
- Use open and closed circles to show whether endpoints are inclusive or exclusive.
Square Root Function
The square root function, typically expressed as \( f(x) = \sqrt{x} \), features unique properties:
- Its domain includes only non-negative numbers, \( x \geq 0 \), as square roots of negative numbers are not real.
- The graph of \( \sqrt{x} \) begins at the origin \((0,0)\), and moves upwards in a smooth curve.
- As \( x \) increases, the growth of \( \sqrt{x} \) slows down due to the nature of square roots.
Continuous Function
A continuous function is one that has no breaks, jumps, or holes in its graph. Continuity means you can draw the function without lifting your pencil from the paper. In terms of piecewise functions, continuity is assessed at points where different pieces of the function meet.
For our function:
For our function:
- Naturally, \( f(x) = 3 \) for \( x < 0 \) is continuous within its interval because it is a constant line.
- \( f(x) = \sqrt{x} \) is likewise continuous within the domain \( x \geq 0 \).
- The function needs examination at \( x = 0 \), the transition point between the two expressions.
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