Problem 41
Question
For the following exercises, find the \(x\) - and \(y\) -intercepts of each equation. $$ f(x)=-x+2 $$
Step-by-Step Solution
Verified Answer
The x-intercept is (2, 0), and the y-intercept is (0, 2).
1Step 1: Understanding Intercepts
To find the intercepts of the equation, we need to determine the points where the graph intersects the axes. For the x-intercept, we set \(y = 0\), and for the y-intercept, we set \(x = 0\). The function given is \(f(x) = -x + 2\), which can be written as \(y = -x + 2\).
2Step 2: Finding x-Intercept
To find the x-intercept, set \(y = 0\) in the equation \(y = -x + 2\). This implies: \[0 = -x + 2\]Now solve for \(x\):\[-x = -2\]which simplifies to: \[ x = 2 \]Thus, the x-intercept is the point \((2, 0)\).
3Step 3: Finding y-Intercept
To find the y-intercept, set \(x = 0\) in the equation \(y = -x + 2\). This implies:\[y = -0 + 2\]which simplifies to:\[y = 2\]Thus, the y-intercept is the point \((0, 2)\).
4Step 4: Summary of Intercepts
The intercepts of the equation \(f(x) = -x + 2\) are the points \((2, 0)\) for the x-intercept and \((0, 2)\) for the y-intercept.
Key Concepts
Graphing Linear EquationsFinding x-InterceptFinding y-InterceptLinear Functions
Graphing Linear Equations
Graphing linear equations is a basic but crucial skill in understanding the behavior of linear functions. A linear equation is usually of the form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. The graph of a linear equation is a straight line. The equation \(f(x) = -x + 2\) is a straightforward example of a linear equation. Its slope \(m\) is \(-1\), and its y-intercept \(b\) is \(2\). To plot this on a graph:
- Start by marking the y-intercept \((0, 2)\) on the y-axis. This is where the line will cross the y-axis.
- Use the slope to find another point. A slope of \(-1\) means that for every step you take to the right (positive x-direction), you step down (negative y-direction) by 1 unit. From \((0, 2)\), go right 1 unit and down 1 unit to reach \((1, 1)\).
- Draw a line through these points, extending it in both directions across the graph.
Finding x-Intercept
The x-intercept is the point where the graph of the equation crosses the x-axis. At this point, the value of \(y\) is zero. To find the x-intercept of an equation, set \(y = 0\) in the equation and solve for \(x\). For \(f(x) = -x + 2\), set the equation to:\[0 = -x + 2\]Solving for \(x\) involves:
- Rearranging the equation to isolate \(x\): \(-x = -2\)
- Dividing both sides by \(-1\) to solve for \(x\): \(x = 2\)
Finding y-Intercept
The y-intercept is where the graph crosses the y-axis, and at this point, the value of \(x\) is zero. To find the y-intercept, set \(x = 0\) in the equation and solve for \(y\). Using the example \(f(x) = -x + 2\), insert \(x = 0\):\[y = -0 + 2\]Thus, simplifying gives:
- \(y = 2\)
Linear Functions
Linear functions are among the simplest types of functions in algebra, characterized by their straight-line graphs. They are typically expressed as \(y = mx + b\), where \(m\) represents the slope and \(b\) is the y-intercept. Every linear function creates a graph that's a straight line, showing a constant rate of change.Key features of linear functions include:
- Slope \(m\): This determines the direction and steepness of the line. A positive slope rises, while a negative slope falls.
- Y-Intercept \(b\): This is where the line intersects the y-axis. It is the value of \(y\) when \(x\) is zero.
Other exercises in this chapter
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