Problem 41
Question
For exercises \(41-44\), the formula \(R=\frac{V C}{T}\) describes the flow rate of fluid \(R\) through an intravenous drip. Is the relationship of the given variables a direct variation or an inverse variation? $$ V \text { and } T \text { are constant; the relationship of } R \text { and } C \text {. } $$
Step-by-Step Solution
Verified Answer
Direct variation
1Step 1: Identify Constants
It is given that variables \( V \) and \( T \) are constants.
2Step 2: Rewrite the Formula
Rewrite the formula \( R = \frac{V C}{T} \) to show the relationship between \( R \) and \( C \). Since \( V \) and \( T \) are constants, let's denote them as \( k = \frac{V}{T} \).
3Step 3: Substitute Constants
Substitute \( k \) into the formula: \( R = kC \).
4Step 4: Identify the Variation Type
The equation \( R = kC \) indicates a direct variation because \( R \) changes directly with \( C \).
Key Concepts
fluid flow rateintravenous drip formulaconstant variables
fluid flow rate
The fluid flow rate, represented by the variable \(R\), refers to how quickly fluid passes through a system or apparatus. In medical contexts, it is crucial to regulate the flow rate of intravenous (IV) fluids accurately. The formula \(R = \frac{VC}{T}\) allows healthcare professionals to calculate this rate.
Here:
Here:
- \(R\): Flow rate of the fluid
- \(V\): Volume of the fluid
- \(C\): Concentration of the solution
- \(T\): Time to deliver the volume
intravenous drip formula
The intravenous drip formula is given by \(R = \frac{VC}{T}\). This formula helps in determining the rate at which fluid needs to be administered intravenously. It combines several factors:
- Volume of the fluid (\(V\))
- Concentration of the fluid (\(C\))
- Time period (\(T\))
constant variables
In the formula \(R = \frac{VC}{T}\), the variables \(V\) (Volume) and \(T\) (Time) are constant. Constants are values that do not change during the process of calculation. By identifying and using constant variables:
- \
Other exercises in this chapter
Problem 40
For exercises 39-82, simplify. $$ \frac{c d}{b^{2}} \div \frac{d^{2}}{b} $$
View solution Problem 40
For exercises 1-66, simplify. $$ \frac{n^{2}-9}{n^{2}+4 n+3} $$
View solution Problem 41
If both sides of the equation \(\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\) are multiplied by \(x(x-1)\), the simplified equation is \(1 x+2(x-1)=x^{2}\). Rewriti
View solution Problem 41
For exercises \(5-48\), simplify. $$ \frac{2 a^{2}}{3 a^{3}+24 a^{2}+45 a}-\frac{10 a+48}{3 a^{3}+24 a^{2}+45 a} $$
View solution