Problem 41
Question
Find the areas of the triangles whose vertices are given. $$A(0,0), \quad B(-2,3), \quad C(3,1)$$
Step-by-Step Solution
Verified Answer
The area of the triangle is 5.5 square units.
1Step 1: Understanding the Problem
We need to find the area of a triangle whose vertices are given by the points \(A(0,0)\), \(B(-2,3)\), and \(C(3,1)\). We'll use the formula for the area of a triangle given vertices with coordinates \((x_1, y_1), (x_2, y_2), (x_3, y_3)\).
2Step 2: Write Down the Area Formula
The formula to find the area of a triangle with vertices at \((x_1, y_1), (x_2, y_2), (x_3, y_3)\) is:\[ ext{Area} = \frac{1}{2} \left| x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2) \right|\]
3Step 3: Substitute the Coordinates into the Formula
Substitute the given points \(A(0,0)\), \(B(-2,3)\), \(C(3,1)\) into the formula:\[ ext{Area} = \frac{1}{2} \left| 0(3-1) + (-2)(1-0) + 3(0-3) \right|\]
4Step 4: Simplify the Expression
Calculate the expression inside the absolute value:\[0(3-1) = 0, \quad (-2)(1-0) = -2, \quad 3(0-3) = -9\]So the expression becomes:\[ ext{Area} = \frac{1}{2} \left| 0 - 2 - 9 \right| = \frac{1}{2} \left| -11 \right|\]
5Step 5: Calculate the Absolute Value and the Final Area
The absolute value of \(-11\) is \(11\). Now, multiply by \(\frac{1}{2}\):\[\frac{1}{2} \times 11 = 5.5\]Therefore, the area of the triangle is \(5.5\) square units.
Key Concepts
Coordinate GeometryTriangle VerticesArea Calculation
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is a branch of geometry that uses a coordinate system to explore geometric problems.
In this system, every point in the plane is identified through a pair of numerical coordinates. These coordinates define the location of a point in a two-dimensional space.
By using coordinate geometry, we can easily manage and manipulate points, lines, and shapes using algebraic equations.
This approach is incredibly useful in finding the area of triangles when the vertices have specified coordinates.
In this system, every point in the plane is identified through a pair of numerical coordinates. These coordinates define the location of a point in a two-dimensional space.
- The first number is usually the x-coordinate, representing the horizontal position.
- The second number is the y-coordinate, representing the vertical position.
By using coordinate geometry, we can easily manage and manipulate points, lines, and shapes using algebraic equations.
This approach is incredibly useful in finding the area of triangles when the vertices have specified coordinates.
Triangle Vertices
In geometry, a triangle is a polygon with three edges and three vertices.
When finding the area of a triangle using coordinates, it is crucial to understand what vertices and how they contribute to calculations.
Each vertex of the triangle is identified by an ordered pair of numbers in the coordinate plane.
In your exercise, you are given three points:
When finding the area of a triangle using coordinates, it is crucial to understand what vertices and how they contribute to calculations.
Each vertex of the triangle is identified by an ordered pair of numbers in the coordinate plane.
In your exercise, you are given three points:
- A with coordinates egin{math}(0, 0) uildrel{ ext{(point of origin - easiest to work with)}} ight.)
- B with coordinates egin{math}(-2, 3) uildrel{ ext{(a point in the second quadrant)}} ight.)
- C with coordinates egin{math}(3, 1) uildrel{ ext{(a point in the first quadrant)}} ight.)
Area Calculation
Calculating the area using coordinates involves a specific mathematical formula that simplifies the process.
The formula for finding the area of a triangle with given vertices, expressed as egin{math}(x_1, y_1), (x_2, y_2), (x_3, y_3) ight., egin{math} ext{is:} ightrace rac{1}{2} imes| x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2)|.
Using this formula, we apply our coordinates:
With understanding of the logic and calculation practiced, determining the area of triangles using vertices can enhance problem-solving skills in geometry.
The formula for finding the area of a triangle with given vertices, expressed as egin{math}(x_1, y_1), (x_2, y_2), (x_3, y_3) ight., egin{math} ext{is:} ightrace rac{1}{2} imes| x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2)|.
Using this formula, we apply our coordinates:
- egin{math} (0,0) ight.)
- egin{math}(-2,3) ight.)
- egin{math}(3,1) ight.)
- The expression becomes
begin{math}0(3-1) + (-2)(1-0) + 3(0-3).
ight.) - This simplifies to: 0, -2, -9.
- The sum is egin{math}-11 ight. ight.)
With understanding of the logic and calculation practiced, determining the area of triangles using vertices can enhance problem-solving skills in geometry.
Other exercises in this chapter
Problem 40
find the distance from the point to the plane. $$(0,0,0), \quad 3 x+2 y+6 z=6$$
View solution Problem 40
Describe the given set with a single equation or with a pair of equations. The circle of radius 1 centered at (-3,4,1) and lying in a plane parallel to the a. \
View solution Problem 41
Sketch the surfaces ASSORTED $$z=-\left(x^{2}+y^{2}\right)$$
View solution Problem 41
Linear combination \(\quad\) Let \(\mathbf{u}=2 \mathbf{i}+\mathbf{j}, \mathbf{v}=\mathbf{i}+\mathbf{j},\) and \(\mathbf{w}= \mathbf{i} - \mathbf{j}\). Find sca
View solution