Problem 41
Question
Find \(a_{1}\) and \(d\) for each arithmetic sequence. $$S_{20}=1090, a_{20}=102$$
Step-by-Step Solution
Verified Answer
First term \(a_1 = 7\) and common difference \(d = 5\).
1Step 1: Understanding the Arithmetic Sequence Formula
An arithmetic sequence is defined by the first term \(a_1\) and a common difference \(d\). The \(n\)-th term is given by the formula \(a_n = a_1 + (n-1)d\). The sum of the first \(n\) terms is given by \(S_n = \frac{n}{2}(a_1 + a_n)\). We are given \(S_{20} = 1090\) and \(a_{20} = 102\).
2Step 2: Setting Up the Equations
From the nth-term formula, substitute \(n=20\) and \(a_{20} = 102\): \[ a_{20} = a_1 + 19d = 102 \] From the sum formula, substitute \(n=20\) and \(S_{20} = 1090\): \[ S_{20} = \frac{20}{2}(a_1 + a_{20}) = 1090 \] This simplifies to \[ 10(a_1 + 102) = 1090 \] or \[ a_1 + 102 = 109 \]
3Step 3: Solving for \(a_1\)
From the equation \(a_1 + 102 = 109\), solve for \(a_1\): \[ a_1 = 109 - 102 \]\[ a_1 = 7 \]
4Step 4: Solving for \(d\)
Substitute \(a_1 = 7\) into the equation from the nth-term formula: \[ a_1 + 19d = 102 \]\[ 7 + 19d = 102 \] Solve for \(d\): \[ 19d = 102 - 7 \]\[ 19d = 95 \]\[ d = \frac{95}{19} \]\[ d = 5 \]
Key Concepts
Common DifferenceNth-Term FormulaSum of the First N TermsFirst Term of Sequence
Common Difference
In an arithmetic sequence, the **common difference** is a key element that defines the progression from one term to the next. It is the constant difference between any two consecutive terms in the sequence. The common difference is denoted by the symbol **d**.
To find the common difference, subtract the first term from the second term, the second term from the third term, and so on. This value remains constant throughout the sequence.
To find the common difference, subtract the first term from the second term, the second term from the third term, and so on. This value remains constant throughout the sequence.
- Example: In the sequence 3, 7, 11, ..., the common difference is calculated as 7 - 3 = 4. Hence, **d = 4**.
Nth-Term Formula
The **nth-term formula** allows us to find any term in an arithmetic sequence without listing all preceding terms. The formula is expressed as:
\[ a_n = a_1 + (n-1) imes d \]
Here, **a_n** represents the nth term, **a_1** is the first term, and **d** is the common difference. **n** is the position of the term in the sequence.
\[ a_n = a_1 + (n-1) imes d \]
Here, **a_n** represents the nth term, **a_1** is the first term, and **d** is the common difference. **n** is the position of the term in the sequence.
- Example: For a sequence where **a_1 = 5** and **d = 3**, the 4th term, or **a_4**, would be calculated as:
\[ a_4 = 5 + (4-1) imes 3 = 5 + 9 = 14 \]
Sum of the First N Terms
The sum of the first **n** terms in an arithmetic sequence can be calculated using the formula:
\[ S_n = \frac{n}{2}(a_1 + a_n) \]
Here, **S_n** is the sum of the first **n** terms, **a_1** is the first term, and **a_n** is the nth term.
This formula is helpful because it lets us find the total of a large part of the sequence without having to add up each individual term. For instance, if **a_1 = 2**, **a_n = 20**, and **n = 10**, the sum is:
\[ S_n = \frac{n}{2}(a_1 + a_n) \]
Here, **S_n** is the sum of the first **n** terms, **a_1** is the first term, and **a_n** is the nth term.
This formula is helpful because it lets us find the total of a large part of the sequence without having to add up each individual term. For instance, if **a_1 = 2**, **a_n = 20**, and **n = 10**, the sum is:
- \[ S_{10} = \frac{10}{2} (2 + 20) = 5 imes 22 = 110 \]
First Term of Sequence
The **first term of a sequence**, represented as **a_1**, is the initial term from which the sequence begins. It sets the starting point for the arithmetic progression. Knowing this term is vital because it acts as the foundational element of the sequence.
In exercises where the first term isn't directly given, we can often deduce it using other provided information, such as the nth term and the sum formula. For example, if we know the 20th term is 102 and the common difference is 5, we can find **a_1** using:
In exercises where the first term isn't directly given, we can often deduce it using other provided information, such as the nth term and the sum formula. For example, if we know the 20th term is 102 and the common difference is 5, we can find **a_1** using:
- \[ 102 = a_1 + (20-1) imes 5 \]
- \[ a_1 = 102 - 95 = 7 \]
Other exercises in this chapter
Problem 40
Use the fundamental principle of counting or permutations to solve each problem. Concert Program Arrangement \(\mathrm{A}\) concert to raise money for an econom
View solution Problem 40
Find the sum for each series. $$\sum_{i=-1}^{2} 5(2)^{i}$$
View solution Problem 41
A die is rolled 12 times. Approximate the probability of rolling the following. Exactly 12 ones
View solution Problem 41
Write the sum of each geometric series as a rational number. $$0.8+0.08+0.008+0.0008+\cdots$$
View solution