Problem 41
Question
Factor each trinomial completely. See Examples 1 through 7. \(21 b^{2}-48 b-45\)
Step-by-Step Solution
Verified Answer
The trinomial \(21b^2 - 48b - 45\) factors to \(3(b - 3)(7b + 5)\).
1Step 1: Identify and Write Down the Trinomial
The given trinomial is \(21b^2 - 48b - 45\). This is a quadratic trinomial, where \(a = 21\), \(b = -48\), and \(c = -45\).
2Step 2: Find the Product of 'a' and 'c'
Calculate the product of the coefficients \(a\) and \(c\), which are \(21\) and \(-45\) respectively. The product is \[ 21 imes (-45) = -945 \].
3Step 3: Find Two Numbers That Multiply to '-945' and Add to '-48'
Identify two numbers whose product is \(-945\) and sum is \(-48\). After checking factors, the numbers \(15\) and \(-63\) satisfy this requirement because \(15 + (-63) = -48\) and \(15 imes -63 = -945\).
4Step 4: Rewrite the Middle Term Using the Two Numbers
Rewrite the quadratic trinomial by splitting the middle term \(-48b\) into \(15b - 63b\). Thus, the expression becomes \[ 21b^2 + 15b - 63b - 45 \].
5Step 5: Factor by Grouping
Group the terms into pairs:\[ (21b^2 + 15b) + (-63b - 45) \].Factor out the greatest common factor from each pair:1. From \(21b^2 + 15b\), factor \(3b\), giving \(3b(7b + 5)\).2. From \(-63b - 45\), factor \(-9\), giving \(-9(7b + 5)\).
6Step 6: Complete the Factorization
Since both terms contain \((7b + 5)\), factor \((7b + 5)\) out:\[ 3b(7b + 5) - 9(7b + 5) = (3b - 9)(7b + 5) \].
7Step 7: Simplify the Expression
Further factor \(3b - 9\) by finding the greatest common factor, which is 3.Thus, \(3b - 9 = 3(b - 3)\).Combine to get the fully factored form:\[ 3(b - 3)(7b + 5) \].
Key Concepts
Quadratic TrinomialsFactorizationAlgebraic ExpressionsGreatest Common Factor
Quadratic Trinomials
A quadratic trinomial is a polynomial with three terms, each powered by a non-negative integer, with the highest degree being two. In the form \(ax^2 + bx + c\), these trinomials have specific characteristics that make them identifiable in algebra. Understanding quadratic trinomials involves recognizing their terms:
- The first term \(ax^2\) often sets the stage for further calculations with the leading coefficient \(a\).
- The middle term, \(bx\), influences the polynomial's behavior and symmetry.
- The constant term \(c\) closes out this trio.
Factorization
Factorization is a key algebraic method used to break down polynomials into simpler "building blocks" or factors. These factors, when multiplied, give the original polynomial. In simpler terms, factorization splits a complex expression into a product of two or more simpler terms. The process often involves:
- Finding pairs of numbers whose product equals the given terms, a technique known as the "AC method" for quadratic equations.
- Using techniques such as splitting the middle term for more complex quadratic trinomials.
- Applying grouping methods to simplify expressions.
Algebraic Expressions
Algebraic expressions are combinations of variables, constants, and operations like addition and multiplication. These are the language of algebra, and mastering them is crucial for mathematical fluency. In the context of factoring polynomials, algebraic expressions can be categorized into different types, such as monomials, binomials, and polynomials like the quadratic trinomial.
- The use of expressions allows us to represent unknown values and relationships succinctly.
- Factorization transforms these complex expressions into simpler, more manageable forms.
Greatest Common Factor
The greatest common factor (GCF) is the largest factor shared by two or more terms. It plays a pivotal role in simplifying algebraic expressions and is the first step in many factorization processes. To determine the GCF, one must look at:
- The numerical coefficients, finding the largest integer that divides all.
- Any common variable parts, determining the lowest power that appears in each term.
Other exercises in this chapter
Problem 41
Factor out the GCF from each polynomial. $$ 5 x^{3} y-15 x^{2} y+10 x y $$
View solution Problem 41
Factor each trinomial completely. Some of these trinomials contain a greatest common factor (other than 1). Don't forget to factor out the GCF first. $$ x^{2}-1
View solution Problem 41
$$ 5(3-4 x)=9 $$$$ (4 x-3)\left(16 x^{2}-24 x+9\right)=0 $$
View solution Problem 42
Factor each completely. $$ 12 x y^{2}-108 x $$
View solution