Problem 41
Question
Explain when synthetic division may be used to divide polynomials.
Step-by-Step Solution
Verified Answer
Synthetic division may be used to divide polynomials when the divisor is linear (of the form x-c, where c is a constant). It provides a more efficient approach compared to long division, working with the coefficients of the polynomial. For example, when dividing the polynomial \(P(x) = 2x^3 - 5x^2 + 3x + 1\) by the divisor \(x - 1\), the result would be \( (2x^2 - 3x + 1) + \dfrac{3}{x-1}\).
1Step 1: Identify when synthetic division can be used
A synthetic division can be used to divide a polynomial provided that the divisor is linear or of the form x - c, where c is a constant term.
2Step 2: Understand synthetic division method
In synthetic division, the coefficients of each term of the polynomial are written down in order. Then, the constant term c from the divisor x-c is used to perform the division.
3Step 3: Performing synthetic division with an example
Let's divide the polynomial \( P(x) = 2x^3 - 5x^2 + 3x + 1 \) by the linear divisor \(x - 1\).
1. Write down the coefficients of the polynomial: 2, -5, 3, 1
2. Write the constant term from the divisor x - c: 1
3. Perform synthetic division as follows:
____________1______________
| 2 -5 3 1
+2 -3 -0
-----------
0 1 3
4. Interpret the result obtained from synthetic division:
The coefficients of the quotient are in the bottom row of our table: 2, -3, and 1. Since we started with a cubic polynomial and we are dividing by a linear polynomial, our result will be a quadratic polynomial.
Thus, the quotient is: \( 2x^2 - 3x + 1 \)
5. Finally, the remainder of the division is 3, which can be written as a fraction over the divisor: \(\dfrac{3}{x-1}\)
So, the result of the division is: \( (2x^2 - 3x + 1) + \dfrac{3}{x-1} \)
This example demonstrated the usage of synthetic division for dividing a polynomial by a linear divisor. Synthetic division becomes handy when dealing with these specific types of divisions and is an efficient method compared to long division.
Other exercises in this chapter
Problem 40
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