Problem 41
Question
Describe the graph in three-space of each equation. (a) \(z=2\) (b) \(x=y\) (c) \(x y=0\) (d) \(x y z=0\) (e) \(x^{2}+y^{2}=4\) (f) \(z=\sqrt{9-x^{2}-y^{2}}\)
Step-by-Step Solution
Verified Answer
(a) Horizontal plane, (b) Diagonal plane, (c) Two planes, (d) Three planes, (e) Cylinder, (f) Hemisphere.
1Step 1: Horizontal Plane
The equation \(z=2\) describes a horizontal plane parallel to the \(xy\)-plane, located at a height of \(2\) units along the \(z\)-axis. All points on this plane have their \(z\)-coordinate equal to \(2\).
2Step 2: Diagonal Plane
The equation \(x = y\) represents a diagonal plane in three-space, passing through the origin at an angle of 45 degrees to both the \(x\)- and \(y\)-axes. Every point on this plane has equal values for \(x\) and \(y\).
3Step 3: Coordinate Planes
The equation \(xy = 0\) describes the union of two coordinate planes: the \(yz\)-plane (where \(x = 0\)) and the \(xz\)-plane (where \(y = 0\)). Points on these planes satisfy the condition that the product \(xy\) is zero.
4Step 4: Intersection of Planes
The equation \(xyz = 0\) represents a union of three planes: the \(yz\)-plane (\(x = 0\)), the \(xz\)-plane (\(y = 0\)), and the \(xy\)-plane (\(z = 0\)). Points on any of these planes satisfy one of the variables being zero.
5Step 5: Cylindrical Surface
The equation \(x^2 + y^2 = 4\) describes a cylinder with a radius of 2 centered along the \(z\)-axis. The cylinder extends infinitely along the \(z\)-direction with circular cross-sections in the \(xy\)-plane.
6Step 6: Hemisphere
The equation \(z = \sqrt{9 - x^2 - y^2}\) forms a hemisphere with a radius of 3 centered at the origin. The hemisphere is above the \(xy\)-plane, forming a dome where \(z\)-values are non-negative.
Key Concepts
Horizontal PlaneDiagonal PlaneCoordinate PlanesCylindrical SurfaceHemisphere in 3D
Horizontal Plane
In the realm of 3D graphs, a horizontal plane holds a special significance. This concept can be visualized using the equation \(z=2\). Here, the equation conveys a plane that is parallel to the \(xy\)-plane.
What makes it distinct is its positioning at a specific height of 2 units along the \(z\)-axis. In simpler terms, this plane is "floating" in space, above the origin. Consequently, all the points on this horizontal plane share a common trait: their \(z\)-coordinate is always 2.
What makes it distinct is its positioning at a specific height of 2 units along the \(z\)-axis. In simpler terms, this plane is "floating" in space, above the origin. Consequently, all the points on this horizontal plane share a common trait: their \(z\)-coordinate is always 2.
- This means that if you know the \(x\) and \(y\) coordinates, you can automatically know the \(z\) coordinate is 2.
- The plane extends infinitely in the directions of the \(x\) and \(y\) axes.
Diagonal Plane
The diagonal plane represented by the equation \(x = y\) introduces a fascinating feature in three-dimensional space. Unlike horizontal or vertical planes, a diagonal plane slices through the space at an angle.
In this scenario, any given point on this plane has the same value for its \(x\)-coordinate and \(y\)-coordinate. Essentially, it passes through the origin diagonally, making an angle of 45 degrees with both the \(x\)- and \(y\)-axes.
In this scenario, any given point on this plane has the same value for its \(x\)-coordinate and \(y\)-coordinate. Essentially, it passes through the origin diagonally, making an angle of 45 degrees with both the \(x\)- and \(y\)-axes.
- Consider points like (1,1) and (2,2); they lie on this plane because their \(x\) and \(y\) coordinates are equal.
- Unlike a single line, this plane isn't restricted to a single dimension; it stretches infinitely in the space defined by the equality of \(x\) and \(y\).
Coordinate Planes
In 3D space, equations like \(xy = 0\) often denote coordinate planes. Specifically here, it signifies the union of two distinct planes.
These are the \(yz\)-plane, where \(x = 0\), and the \(xz\)-plane, where \(y = 0\). This means any point residing on these planes results in the product \(xy\) being zero.
These are the \(yz\)-plane, where \(x = 0\), and the \(xz\)-plane, where \(y = 0\). This means any point residing on these planes results in the product \(xy\) being zero.
- On the \(yz\)-plane, since \(x=0\), the points could be like (0,1,2) where only \(y\) and \(z\) have values.
- Similarly, for the \(xz\)-plane, a point could be (3,0,-1), implying values for \(x\) and \(z\) only.
Cylindrical Surface
The notion of a cylindrical surface is an intriguing element in calculus, described in this instance by the equation \(x^2 + y^2 = 4\). This translates to a cylinder centered along the \(z\)-axis.
Think of this cylinder as comprising circles of radius 2 in the \(xy\)-plane that stack vertically throughout the \(z\)-dimension. It continues endlessly along the \(z\)-axis, forming a tubular structure.
Think of this cylinder as comprising circles of radius 2 in the \(xy\)-plane that stack vertically throughout the \(z\)-dimension. It continues endlessly along the \(z\)-axis, forming a tubular structure.
- The center of each circular cross-section sits at the origin, making them symmetric around the \(z\)-axis.
- Regardless of the \(z\)-coordinate, all horizontal cross-sections are identical circles.
Hemisphere in 3D
A hemisphere is a half of a sphere, and it is visually captivating when depicted in 3D space, exemplified by the equation \(z = \sqrt{9 - x^2 - y^2}\). This represents a hemisphere with a radius of 3.
Centered at the origin, it rests above the \(xy\)-plane, creating a dome-like structure.
Centered at the origin, it rests above the \(xy\)-plane, creating a dome-like structure.
- The equation ensures that the \(z\)-values are non-negative, reflecting the upper half of a sphere.
- When \(x\) and \(y\) are zero, \(z\) reaches its peak value at 3, the radius.
Other exercises in this chapter
Problem 41
find the tangential and normal components \(\left(a_{T}\right.\) and \(\left.a_{N}\right)\) of the acceleration vector at \(t .\) Then evaluate at \(t=t_{1} .\)
View solution Problem 41
Find two perpendicular vectors \(\mathbf{u}\) and \(\mathbf{v}\) such that each is also perpendicular to \(\mathbf{w}=\langle-4,2,5\rangle\).
View solution Problem 42
Evaluate the integrals $$ \int_{-1}^{1}\left[(1+t)^{3 / 2} \mathbf{i}+(1-t)^{3 / 2} \mathbf{j}\right] d t $$
View solution Problem 42
find the tangential and normal components \(\left(a_{T}\right.\) and \(\left.a_{N}\right)\) of the acceleration vector at \(t .\) Then evaluate at \(t=t_{1} .\)
View solution