Problem 41
Question
Add and subtract the rational expressions, and then simplify. $$ \frac{x}{x+1}+\frac{y}{y+1} $$
Step-by-Step Solution
Verified Answer
\(\frac{2xy + x + y}{(x + 1)(y + 1)}\) is the simplified expression.
1Step 1: Identify Common Denominator
To add the rational expressions, first identify a common denominator. In this case, the common denominator will be the product of the two separate denominators: \[(x + 1)(y + 1)\].
2Step 2: Rewrite Each Expression with the Common Denominator
Rewrite each rational expression to have the common denominator:For \(\frac{x}{x+1}\), multiply the numerator and denominator by \((y+1)\): \[\frac{x(y+1)}{(x+1)(y+1)}\]For \(\frac{y}{y+1}\), multiply the numerator and denominator by \((x+1)\):\[\frac{y(x+1)}{(x+1)(y+1)}\]
3Step 3: Add the Numerators
Add the numerators of the rewritten expressions over the common denominator:\[\frac{x(y+1) + y(x+1)}{(x+1)(y+1)}\]
4Step 4: Simplify the Numerator
Simplify the numerator by expanding and combining like terms:\[x(y+1) + y(x+1) = xy + x + yx + y = 2xy + x + y\]Now the expression becomes:\[\frac{2xy + x + y}{(x+1)(y+1)}\]
Key Concepts
Common DenominatorAddition of FractionsSimplifying Algebraic Expressions
Common Denominator
The concept of a common denominator is essential when working with rational expressions, especially for addition or subtraction. A rational expression is similar to a fraction, where the numerator and the denominator can be polynomials. To add or subtract these expressions, they must have the same denominator. This is called the common denominator.
- First, identify the denominators of each rational expression you are working with.
- For the exercise here, the denominators are \(x+1\) and \(y+1\).
- The common denominator is obtained by multiplying these denominators together: \((x+1)(y+1)\).
Addition of Fractions
Once you have identified the common denominator, the next step involves rewriting each fraction. Rewriting is crucial so that each rational expression has the new common denominator. This often involves multiplying both the numerator and the denominator by factors that will make each denominator equivalent to the common one.
- For \(\frac{x}{x+1}\), multiply both top and bottom by \(y+1\), becoming \(\frac{x(y+1)}{(x+1)(y+1)}\).
- For \(\frac{y}{y+1}\), multiply both top and bottom by \(x+1\), becoming \(\frac{y(x+1)}{(x+1)(y+1)}\).
Simplifying Algebraic Expressions
Simplifying the algebraic expression involves combining like terms and reducing the expression to its most straightforward form. Once the fractions are added, your expression might look complex. At this stage:
- Expand the expressions by distributing any multiplication inside the numerator.
- For the exercise, expand \(x(y+1) + y(x+1)\) to get \(xy + x + yx + y\).
- Combine like terms, in this case, \(xy\) and \(yx\), leading to \(2xy + x + y\).
Other exercises in this chapter
Problem 41
For the following exercises, find the sum or difference. $$(y-2)\left(y^{2}-4 y-9\right)$$
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For the following exercises, multiply the polynomials. $$ (y-2)\left(y^{2}-4 y-9\right) $$
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Simplify each expression. $$3 \sqrt{a b^{2}}-b \sqrt{a}$$
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For the following exercises, simplify the given expression. Write answers with positive exponents. $$\left(b^{-3} c\right)^{3}$$
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