Problem 41
Question
A heart defibrillator is used to enable the heart to start beating if it has stopped. This is done by passing a large current of 12 A through the body at 25 V for a very short time, usually about 3.0 ms. (a) What power does the defibrillator deliver to the body, and (b) how much energy is transferred?
Step-by-Step Solution
Verified Answer
(a) 300 watts, (b) 0.9 joules.
1Step 1: Understand the Power Formula
Power is calculated using the formula \( P = IV \), where \( P \) is the power in watts (W), \( I \) is the current in amperes (A), and \( V \) is the voltage in volts (V). Here, given \( I = 12 \) A and \( V = 25 \) V, substitute these values into the formula.
2Step 2: Calculate Power Delivered
Using the formula \( P = IV \), substitute \( I = 12 \) A and \( V = 25 \) V into the equation: \( P = 12 \times 25 = 300 \) watts.
3Step 3: Understand Energy Formula
Energy transferred is calculated using the formula \( E = Pt \), where \( E \) is energy in joules (J), \( P \) is power in watts, and \( t \) is time in seconds (s). The given time is 3.0 milliseconds, which is 3.0 ms = 3.0 x 10^{-3} s.
4Step 4: Calculate Energy Transferred
Substitute \( P = 300 \) W and \( t = 3.0 \times 10^{-3} \) s into the formula \( E = Pt \): \( E = 300 \times 3.0 \times 10^{-3} = 0.9 \) joules.
Key Concepts
Power CalculationEnergy TransferDefibrillator Physics
Power Calculation
In electrical circuits, calculating power is fundamental when understanding how devices like defibrillators function. The power output of a device is the rate at which it can transfer energy, measured in watts (W). This is crucial for determining how effective the device will be.
A simple and important formula for power calculation is given by \( P = IV \). Here, \( P \) is the power, \( I \) is the current in amperes, and \( V \) is the voltage in volts. In our example with the defibrillator:
A simple and important formula for power calculation is given by \( P = IV \). Here, \( P \) is the power, \( I \) is the current in amperes, and \( V \) is the voltage in volts. In our example with the defibrillator:
- The current \( (I) = 12 \) A
- The voltage \( (V) = 25 \) V
Energy Transfer
Energy transfer is a key component in understanding how electrical devices interact with their environment. It tells us how much energy is moved from one system or body to another. In the context of a defibrillator, this is important to assess its effectiveness in restarting a heart.
The formula to calculate energy transferred is \( E = Pt \), where \( E \) is the energy in joules, \( P \) is the power in watts, and \( t \) is the time in seconds during which the power is delivered. The shorter the time, the more precise and immediate the energy transfer.
In our example, we know:
This brief and potent delivery is essential during an emergency, highlighting the importance of accurate and efficient energy transfer.
The formula to calculate energy transferred is \( E = Pt \), where \( E \) is the energy in joules, \( P \) is the power in watts, and \( t \) is the time in seconds during which the power is delivered. The shorter the time, the more precise and immediate the energy transfer.
In our example, we know:
- Power \( P = 300 \) W
- Time \( t = 3.0 \times 10^{-3} \) s (converted from milliseconds)
This brief and potent delivery is essential during an emergency, highlighting the importance of accurate and efficient energy transfer.
Defibrillator Physics
Defibrillators are a fascinating application of physics principles, used to restore a heart's normal rhythm by delivering a controlled electric shock. Understanding how these devices work involves a blend of electricity and human physiology.
These devices operate by delivering a precise amount of power and energy to the heart. The aim is to depolarize the heart muscles, which can potentially reset the normal rhythm of the heart. This requires a delicate balance, as too little energy might be ineffective while too much could cause harm.
Key aspects of defibrillator physics include:
These devices operate by delivering a precise amount of power and energy to the heart. The aim is to depolarize the heart muscles, which can potentially reset the normal rhythm of the heart. This requires a delicate balance, as too little energy might be ineffective while too much could cause harm.
Key aspects of defibrillator physics include:
- Current and Voltage: The device needs a high current (12 A in our example) and suitable voltage (25 V) to be effective.
- Time Duration: The energy delivery happens over a very short time span (3 ms in our case), which is critical to avoid harm and achieve the desired reset efficiently.
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