Problem 41
Question
\(39-48=\) Simplify the expression. $$ \sqrt{125}-\sqrt{45} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(2\sqrt{5}\).
1Step 1: Simplify the Radical Expressions
Start by simplifying each radical expression individually. First, look at \(\sqrt{125}\). We know that \(125 = 25 \times 5\), and can thus rewrite it as \(\sqrt{25 \times 5}\). Because \(25\) is a perfect square, we can simplify further: \(\sqrt{25 \times 5} = \sqrt{25} \times \sqrt{5} = 5\sqrt{5}\).
2Step 2: Simplify the Second Radical
Next, simplify \(\sqrt{45}\). Notice that \(45 = 9 \times 5\), so we can rewrite it as \(\sqrt{9 \times 5}\). Since \(9\) is a perfect square, we further simplify it to \(\sqrt{9 \times 5} = \sqrt{9} \times \sqrt{5} = 3\sqrt{5}\).
3Step 3: Subtract the Simplified Terms
Now, with both radicals simplified, we have \(5\sqrt{5} - 3\sqrt{5}\). Since both terms have \(\sqrt{5}\) in common, we can combine them: \(5\sqrt{5} - 3\sqrt{5} = (5 - 3)\sqrt{5} = 2\sqrt{5}\).
Key Concepts
Radical ExpressionsPerfect SquaresCombining Like Terms
Radical Expressions
Radical expressions involve the use of roots, commonly square roots. Simplifying them means rewriting them in their simplest form. Consider the expression \( \sqrt{125} - \sqrt{45} \). We break each part into its prime factors or perfect squares to simplify:
- For \( \sqrt{125} \), recognize that 125 can be factored as \( 25 \times 5 \).
- Since 25 is a perfect square, we simplify \( \sqrt{25} \) to 5, resulting in \( 5\sqrt{5} \).
- Similarly, for \( \sqrt{45} \), use the factors \( 9 \times 5 \).
- The perfect square 9 simplifies to 3, giving us \( 3\sqrt{5} \).
Perfect Squares
A perfect square is an integer that is the square of another integer. Recognizing these can greatly help in simplifying radical expressions. In our exercise, we identified:
- 25 as a perfect square because \( 25 = 5^2 \).
- 9 as a perfect square because \( 9 = 3^2 \).
Combining Like Terms
When dealing with radical expressions, combining like terms is similar to how you handle variables in algebra. After simplifying radicals, you may find terms with the same radical part - these are like terms. In our case:
- We have \( 5\sqrt{5} \) and \( 3\sqrt{5} \).
- Both terms have \( \sqrt{5} \), which can be thought of like a variable \( x \).
- Therefore, you can combine them: \( 5\sqrt{5} - 3\sqrt{5} = (5-3)\sqrt{5} = 2\sqrt{5} \).
Other exercises in this chapter
Problem 41
\(29-46\) Simplify each expression. $$ \left(a^{2} a^{4}\right)^{3} $$
View solution Problem 41
Express the inequality in interval notation, and then graph the corresponding interval. $$ -2
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Multiply the algebraic expressions using the FOIL method, and simplify. \((3 t-2)(7 t-4)\)
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Perform the multiplication or division and simplify. $$ \frac{\frac{2 x^{2}-3 x-2}{x^{2}-1}}{\frac{2 x^{2}+5 x+2}{x^{2}+x-2}} $$
View solution