Problem 40
Question
UCHTING For Exercises 39 and 40 , use the following information. The amount of light that a source provides to a surface is called the illuminance. The illuminance \(E\) in foot candles on a surface is related to the distance \(R\) in feet from the light source. The formula sec \(\theta=\frac{1}{E R^{2}}\) where \(I\) is the intensity of the light source measured in candles and \(\theta\) is the angle between the light beam and a line perpendicular to the surface, can be used in situations in which lighting is important. Is the equation in Exercise 39 equivalent to \(R^{2}=\frac{I \tan \theta \cos \theta}{E} ?\) Explain.
Step-by-Step Solution
Verified Answer
No, unless \( I \tan \theta = 1 \).
1Step 1: Understand the Given Equation
The given equation is \( \sec \theta = \frac{1}{ER^2} \). This relates the illuminance \( E \), distance \( R \), and angle \( \theta \).
2Step 2: Transform the Secant Function
Recall that \( \sec \theta = \frac{1}{\cos \theta} \). Therefore, the given equation can be expressed in terms of cosine as \( \frac{1}{\cos \theta} = \frac{1}{ER^2} \).
3Step 3: Cross Multiply to Simplify
Cross multiply to get rid of the fractions: \( ER^2 = \cos \theta \).
4Step 4: Solve for \( R^2 \)
Divide both sides by \( E \) to solve for \( R^2 \): \( R^2 = \frac{\cos \theta}{E} \).
5Step 5: Compare with Given Equation
The equation we derived is \( R^2 = \frac{\cos \theta}{E} \), whereas the equation given is \( R^2 = \frac{I \tan \theta \cos \theta}{E} \). They are not the same unless \( I \tan \theta = 1 \).
Key Concepts
Light IntensityTrigonometric FunctionsMathematical Equations
Light Intensity
Light intensity is a critical factor in determining the illuminance, which describes how much light falls on a particular area.
A point light source emits light in all directions, and the intensity is measured in candles. Intensity is a property of the light source itself and describes how much energy it emits over a unit of time.
The relationship between light intensity and illuminance involves the distance from the light source, which is inversely proportional to the square of that distance and the cosine of the angle relative to the surface.
These mathematical connections ensure that light is calculated accurately, optimizing visibility and ambiance.
A point light source emits light in all directions, and the intensity is measured in candles. Intensity is a property of the light source itself and describes how much energy it emits over a unit of time.
- Consider a dull light bulb emitting lower intensity than a bright lamp.
- Intensity impacts the amount of light that can reach a surface, especially at greater distances.
The relationship between light intensity and illuminance involves the distance from the light source, which is inversely proportional to the square of that distance and the cosine of the angle relative to the surface.
These mathematical connections ensure that light is calculated accurately, optimizing visibility and ambiance.
Trigonometric Functions
Trigonometric functions, such as sine, cosine, and secant, play a vital role in measuring angles and distances in physics and engineering.
The secant function, denoted as \( \sec \theta \), is the reciprocal of the cosine function. Thus, \( \sec \theta = \frac{1}{\cos \theta} \).
This concept is often used in illuminance calculations where the angle \( \theta \) between the light beam and the surface is crucial.
The secant function, denoted as \( \sec \theta \), is the reciprocal of the cosine function. Thus, \( \sec \theta = \frac{1}{\cos \theta} \).
This concept is often used in illuminance calculations where the angle \( \theta \) between the light beam and the surface is crucial.
- Changes in the angle directly affect the illuminance. A larger \( \theta \) increases the value of secant, reflecting more angled light delivery.
- Trigonometry allows converting between functions, helping simplify complex equations.
Mathematical Equations
Mathematical equations are tools used to represent and solve physical phenomena like light distribution. In illuminating contexts, they equate various factors such as illuminance \( E \), light intensity \( I \), distance \( R \), and angle \( \theta \).
In the given context, the equation \( \sec \theta = \frac{1}{ER^2} \) encompasses multiple variables working together to explain how light behaves when it strikes a surface.
In the given context, the equation \( \sec \theta = \frac{1}{ER^2} \) encompasses multiple variables working together to explain how light behaves when it strikes a surface.
- Breaking down the equation requires algebraic manipulation, such as cross-multiplying to eliminate fractions.
- Transform the equation using properties of functions, like changing secant to cosine.
- Comparing different equation forms offers insight into whether adjustments in variables lead to consistent results.
Other exercises in this chapter
Problem 40
REASONING Describe the conditions under which you would use each of the three identities for \(\cos 2 \theta .\)
View solution Problem 40
ACT/SAT Which of the following is not equivalent to \(\cos \theta ?\) $$ \begin{array}{l}{\text { A } \frac{\cos \theta}{\cos ^{2} \theta+\sin ^{2} \theta}} \\
View solution Problem 40
Verify that each of the following is an identity. \(\cos (\alpha+\beta)=\frac{1-\tan \alpha \tan \beta}{\sec \alpha \sec \beta}\)
View solution Problem 40
Compare the graphs of \(y=-\sin \left[\frac{1}{4}\left(\theta-\frac{\pi}{2}\right)\right]\) and \(y=\cos \left[\frac{1}{4}\left(\theta+\frac{3 \pi}{2}\right)\ri
View solution